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    Title of practice: Osmosis between sucrose and water

    Introduction

    For the cell to work efficiently, it must be kept stable, this is known as

    homeostasis. To maintain this balance there exists mechanisms for selective

    transport of materials called membranes which are selectively permeable,

    allowing the passage of some substances or particles (molecules, atoms, or ions),

    and preventing the passage of others. This selectivity is due to the double layer

    of membrane phospholipids. The manner in which the molecules pass through

    the membrane depends in part on the polarity in each one. Hydrophobic

    molecules, or non-polar, relatively free pass through the layer of lipid moleculeswhile hydrophilic or polar, including water, and larger molecules pass through

    channels formed by carrier proteins. The regulation of the transport of molecules,

    or the moving direction depends on its concentration gradient (the difference in

    concentration between the two locations).

    The molecules move constantly due to their kinetic energy and spread evenly

    into the available space. This movement, called Brownian motion, is the driving

    force of diffusion.

    Diffusion is defined as the natural movement of the particles from an area of

    higher concentration to an area of lower concentration to achieve a dynamic

    balance in which the particle motion is zero net. There exist two kinds of

    diffusions: passive and active transport, but the experiment only consisted on

    passive transport. Passive transport is a transport mechanisms by which the

    substances move across the cell passing through the plasma membrane and does

    not requires energy. Osmosis is a passive transport and it is defined as a passive

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    movement, or diffusion of water molecules across a partially membrane, from a

    region of lower solute concentration to a region of higher solute concentration.

    The objective of the following practice is to study how osmosis occurs, in two

    plastics that worked as membranes, adhere certain amount of sucrose to the

    plastics and weight them, then immersion the plastics in distilled water and after

    certain time take the plastics out and weight the semi permeable membranes

    again.

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    Problem/Research question

    What changed the experiment was the concentration of sucrose that was added in

    the plastic bag (0.5 M, 1.5 M and 2M) they were submerged by 15 minutes in a

    15mil solution of distilled water.

    The research question is: What would happen if a membrane with concentration

    solution sucrose of 0.5 M, 1.5 M and 2M is submerged in a 15 ml solution of

    distilled water during 15 minutes?

    The hypothesis is: If the concentration solution of sucrose in the membrane is

    changed, after 15 minutes of been submerged in a 15ml solution of water, the

    weight of them will change because osmosis will occur.

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    Variables

    There are 3 main factors that can prove the osmosis activity and they are:

    sucrose, distilled water, and semi-permeable membranes; these three factors will

    be controlled during all the experiment as can be seen in the following table:

    Table 1 Variables involved

    Type of variable Variable Units Control Method

    Independent

    Variable

    Distilled

    water

    ml Distilled water will be the solute

    that will be in contact with the

    membrane (sucrose substance)

    inside a beaker with 50 ml of

    distilled water.

    Dependent

    Variable

    Weight of the

    membrane

    Grams The weight of the membrane will

    be monitored during all the

    experiment with a balance.

    Controlled

    Variable

    Sucrose M The amount of M will be controlled

    when doing the semi-permeable

    membrane with sucrose. Sucrose

    will be used with a concentration of

    2 M. The quantity of sucrose of the

    semi-permeable membrane will be

    controlled, to control the amount of

    the initial solute inside the

    membrane.

    Temperature Celsius Room temperature

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    Hypotonic

    environment

    --------- The membrane is hypotonic to the

    amount of distilled water

    Materials

    2 Semi-permeable membranes (dialysis bag and string or rubber bandslaboratory)

    Blotting paper1 Test tube rack1 Test tubeBeaker (distilled water 50 ml)Beaker (distilled water 50 ml)Beaker (sucrose 2 M, 50 ml)Laboratory balance

    Reactants

    Sucrose 2 M, 50 mlDistilled water 100 ml

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    Picture or diagram of lab setup

    Blotting paper to Semi-permeable membrane

    dry the membrane with 15 ml of sucrose Balance

    Sucrose 50 ml Sucrose 15 ml Distilled water 50 ml

    Setup

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    Methodology/Procedure

    Based on the reaction of osmosis, the method was designed to measure weight,

    the change of the membrane, to measure the quantity of distilled water that has

    passed through the membrane. The following is the procedure that was used forthe experiment:

    1. First the semi-permeable membrane was dried (dialysis bag) with ablotting paper.

    2. Then the knots in one of their corners were made.3. 15 ml of the sucrose solution were measured from the beaker (50 ml of

    sucrose) using the test tube.

    4. The solution from the test tube was added to the semi-permeablemembrane.

    5. Then the other side of the membrane was closed carefully, leaving no airinside it.

    6. Then it was dried and measured, and with the balance the initial weightwas recorded in the chart.

    7. Afterwards, the membrane was introduced inside a beaker with 50ml ofdistilled water.

    8. After a time of 10 minutes, the membrane was taken out of the sucroseand was dried with perfection, and afterwards recorded in the chart.

    9.Next, the membrane with sucrose is located inside the beaker, withdistilled water again.

    10.The entire list of steps was repeated with the second membrane.

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    Raw data

    In the following tables the raw data collected from the experiments will be

    represented. The tables contain the weight of the membranes that was taken in

    the initial time (without dipping the membranes in distilled water) and after 15

    minutes (submerged in distilled water). In the table it will be also the quantity

    and molarity of Sucrose in each membrane and in some cases the distilled water,

    the others didnt collect it. The weight was recorded with a balance uncertainty

    of 0.5 g.

    Tables

    Shows the data recorded by the membrane in the initial time, and after 15 minutes submerged in distilled water.

    Table 2 Molarity 0.5

    Sample 1 Sample 2Time

    (minutes)

    Sucrose

    (molarity)

    Membranes

    weight(grams)

    Membranes

    weight(grams)

    Distilled

    water(mL)

    Sucrose

    (molarity)

    Membranes

    weight(grams)

    Membranes

    weight(grams)

    Distilled

    water(mL)

    0 0.5 15.82 16.2 17.8 0.5 15.4 14.5 15.5

    15 0.5 16.5 16.8 17.9 0.5 15.7 14.9 15.7

    Table 3 Molarity 1.5

    Sample 3 Sample 4

    Time(minutes)

    Sucrose(molarity)

    Membranesweight

    (grams)

    Membranesweight

    (grams)

    Distilledwater

    (mL)

    Sucrose(molarity)

    Membranesweight

    (grams)

    Membranesweight

    (grams)

    Distilledwater

    (mL)

    0 1.5 16.5 19.4 1.5 16.9 17.5

    15 1.5 19.2 22.1 1.5 19.1 18.5

    Table 4 Molarity 2

    Sample 5

    Time(minutes)

    Sucrose(molarity)

    Membranesweight

    (grams)

    Membranesweight

    (grams)

    Distilledwater

    (mL)

    0 2 19.3 18.3

    15 2 23.5 21.8

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    Processed data presentation

    With the data obtained we are able to calculate the difference in grams. The

    following table shows the initial and final mass of each membrane and in some

    cases the mass of the distilled water. The mass released obtained during the 15

    minutes and the mass before the 15 minutes show the difference of the mass

    during the process, obtained with the formula Difference= (mass after 15

    minutes)-(mass 0 minutes) For example; using the first data in the table 2

    Molarity 0.5 of the experiment with the data collected, substitute the data in the

    formula: () () you obtain 0.68 grams of difference between the

    initial membrane and the final membrane, because a quantity of distilled waterwas adhering to the membrane during the 15 minutes . The same calculus was

    done with the data obtained from all the trials.

    Tables

    Show the difference in the initial and final mass of each of the membranes of the experiment

    showing every trial

    Table 5 Molarity 0.5 (Difference)

    Sample 1 Sample 2

    Time

    (minutes)

    Sucrose

    (molarity)

    Membranes

    weight(grams)

    Membranes

    weight(grams)

    Distilled

    water(mL)

    Sucrose

    (molarity)

    Membranes

    weight(grams)

    Membranes

    weight(grams)

    Distilled

    water(mL)

    0 0.5 15.82 16.2 17.8 0.5 15.4 14.5 15.5

    15 0.5 16.5 16.8 17.9 0.5 15.7 14.9 15.7

    Difference 0.68 0.6 0.1 Difference 0.3 0.4 0.2

    Table 6 Molarity 1.5 (Difference)

    Sample 3 Sample 4

    Time(minutes)

    Sucrose(molarity)

    Membranesweight

    (grams)

    Membranesweight

    (grams)

    Distilledwater

    (mL)

    Sucrose(molarity)

    Membranesweight

    (grams)

    Membranesweight

    (grams)

    Distilledwater

    (mL)

    0 1.5 16.5 19.4 1.5 16.9 17.5

    15 1.5 19.2 22.1 1.5 19.1 18.5

    Difference 2.7 2.7 Difference 2.2 1

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    Table 7 Molarity 2 (Difference)

    Sample 5

    Time(minutes)

    Sucrose(molarity)

    Membranesweight

    (grams)

    Membranesweight

    (grams)

    Distilledwater

    (mL)

    0 2 19.3 18.3

    15 2 23.5 21.8

    Difference 4.2 3.5

    Graph 1 Molarity 0.5 Show the mass during the 0 minutes and 15 minutes

    Graph 2 Molarity 1.5 Show the mass during the 0 minutes and 15 minutes

    0

    2

    4

    6

    8

    10

    12

    14

    16

    18

    0.5 M0.5 M

    Distilled

    water0.5 M

    0.5 MDistilled

    water

    0 minutes

    15 minutes

    0

    5

    10

    15

    20

    25

    1.5 M 1.5 M 1.5 M 1.5 M

    0 minutes

    15 minutes

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    Graph 3 Molarity 2 Show the mass during the 0 minutes and 15 minutes

    As it can be seen from the graphs the difference between the 0 minutes and 15

    minutes changed because of molarity. The molarity of sucrose acts in a regular

    way, more molarity more difference of membranes mass, less molarity less

    difference of membranes mass. The mass change because of the hypertonic

    environment, the membrane with sucrose was hypertonic to the distilled water.Then osmosis occur diffusion of water molecules (distilled water) across a

    partially membrane (dialysis bag or rubber bags laboratory), from a region of

    lower solute concentration (distilled water) to a region of higher solute

    concentration (15 mL of sucrose inside the membrane).

    Conclusion and evaluation

    It is clear that an empirical lab practice with a good methodology will always be

    successful, and that is in fact something this experiment had, in its planning and

    0

    5

    10

    15

    20

    25

    2 M 2 M

    O minutes

    15 minutes

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    in its materials, it was almost perfect, except for a few details that could be

    improved for further lab practices.

    First of all, the lack of knowledge of how to use the lab equipment, this is not a

    fault of the teacher or the biology academy, but still, not taking in consideration

    that some students lack the knowledge is something plain absurd.

    This experimental practice was, even though the team lack of experience and

    knowledge in the lab, a success, due to the results obtained throughout the

    investigation and research and the correction of mistakes.

    The hypothesis was support with the data obtained: a bag containing a certain

    quantity of sucrose, when put inside a beaker with water, will deploy osmosis,

    and thus distilled water will enter the membrane. This is verified by taking

    measures on the weight of the bag, before and after putting it into water; the

    difference between the data will (and actually did) prove that the process known

    as osmosis happened within the laboratory parameters.

    References

    Peeters, Minka., Talbot, Christopher, and Mayhofer Antony. BiologyInternational Baccalaureate. Australia: IBID Press, 2007. Print