lab activity information
DESCRIPTION
Lab activity information. Vi = 0 m/s T = 10 s Find d = Find v f =. Chapter 4 Problems. Guided Practice Problems. Problem #1. Find the uniform acceleration that causes a car’s velocity to change from 32m/s to change to 76 m/s. In an 8.0 s period. Problem #1. Unknown: a =. Given: - PowerPoint PPT PresentationTRANSCRIPT
![Page 1: Lab activity information](https://reader035.vdocuments.site/reader035/viewer/2022062501/56815b6b550346895dc961c0/html5/thumbnails/1.jpg)
Vi = 0 m/s T = 10 s Find d = Find vf =
Lab activity information
![Page 2: Lab activity information](https://reader035.vdocuments.site/reader035/viewer/2022062501/56815b6b550346895dc961c0/html5/thumbnails/2.jpg)
Chapter 4 ProblemsGuided Practice Problems
![Page 3: Lab activity information](https://reader035.vdocuments.site/reader035/viewer/2022062501/56815b6b550346895dc961c0/html5/thumbnails/3.jpg)
Find the uniform acceleration that causes a car’s velocity to change from 32m/s to change to 76 m/s. In an 8.0 s period.
Problem #1
![Page 4: Lab activity information](https://reader035.vdocuments.site/reader035/viewer/2022062501/56815b6b550346895dc961c0/html5/thumbnails/4.jpg)
Given: Vi = 32 m/s Vf = 76 m/s T = 8.0 s
Unknown: a =
Problem #1
![Page 5: Lab activity information](https://reader035.vdocuments.site/reader035/viewer/2022062501/56815b6b550346895dc961c0/html5/thumbnails/5.jpg)
Equation: A = Δv Δt
Problem #1
![Page 6: Lab activity information](https://reader035.vdocuments.site/reader035/viewer/2022062501/56815b6b550346895dc961c0/html5/thumbnails/6.jpg)
Answer: 5.5 m/s/s
Problem #1
![Page 7: Lab activity information](https://reader035.vdocuments.site/reader035/viewer/2022062501/56815b6b550346895dc961c0/html5/thumbnails/7.jpg)
Solution: 76m/s-32m/s / 8 s =
Problem #1
![Page 8: Lab activity information](https://reader035.vdocuments.site/reader035/viewer/2022062501/56815b6b550346895dc961c0/html5/thumbnails/8.jpg)
A supersonic jet flying at 155 m/s is accelerated uniformly at the rate of 23.1 m/s2 for 30 s.
A. What is its final velocity? B. The speed of sound in air is 331 m/s. How
many times the speed of sound is the plane’s final speed?
Problem #2
![Page 9: Lab activity information](https://reader035.vdocuments.site/reader035/viewer/2022062501/56815b6b550346895dc961c0/html5/thumbnails/9.jpg)
Given: Time = 30 s A = 23.1 m/s2
Vi = 155 m/s ______________ Vf = Speed of sound is
331 m/s
Unknown: Vf =
Problem #2
![Page 10: Lab activity information](https://reader035.vdocuments.site/reader035/viewer/2022062501/56815b6b550346895dc961c0/html5/thumbnails/10.jpg)
Equation: A Vf = vi + at
Problem 2
![Page 11: Lab activity information](https://reader035.vdocuments.site/reader035/viewer/2022062501/56815b6b550346895dc961c0/html5/thumbnails/11.jpg)
Equation B: N= 848 m/s/331m/s=
Problem #2
![Page 12: Lab activity information](https://reader035.vdocuments.site/reader035/viewer/2022062501/56815b6b550346895dc961c0/html5/thumbnails/12.jpg)
Answer to A = 848 m/s
Problem #2
![Page 13: Lab activity information](https://reader035.vdocuments.site/reader035/viewer/2022062501/56815b6b550346895dc961c0/html5/thumbnails/13.jpg)
Answer to B:2.56 times
Problem #2
![Page 14: Lab activity information](https://reader035.vdocuments.site/reader035/viewer/2022062501/56815b6b550346895dc961c0/html5/thumbnails/14.jpg)
Solutions for A: 155m/s + (23.1 m/s/s)(30.0 s) =vf
Problem #2
![Page 15: Lab activity information](https://reader035.vdocuments.site/reader035/viewer/2022062501/56815b6b550346895dc961c0/html5/thumbnails/15.jpg)
Solution for B : 848 m/s/331m/s =
Problem #2
![Page 16: Lab activity information](https://reader035.vdocuments.site/reader035/viewer/2022062501/56815b6b550346895dc961c0/html5/thumbnails/16.jpg)
Determine the displacement of a plane that is uniformly accelerated from 66 m/s to 88 m/s in 14 s.
Problem #3
![Page 17: Lab activity information](https://reader035.vdocuments.site/reader035/viewer/2022062501/56815b6b550346895dc961c0/html5/thumbnails/17.jpg)
Given: 66 m/s = Vi
88 m/s = Vf
T = 14 s
Unknown: d
Problem #3
![Page 18: Lab activity information](https://reader035.vdocuments.site/reader035/viewer/2022062501/56815b6b550346895dc961c0/html5/thumbnails/18.jpg)
Equation D=(vf + vi)t/2 =
Problem #3
![Page 19: Lab activity information](https://reader035.vdocuments.site/reader035/viewer/2022062501/56815b6b550346895dc961c0/html5/thumbnails/19.jpg)
Answer #3: 550 m
Problem #3
![Page 20: Lab activity information](https://reader035.vdocuments.site/reader035/viewer/2022062501/56815b6b550346895dc961c0/html5/thumbnails/20.jpg)
Solution #3 : (88 m/s + 66 m/s)14 s/2 =
Problem #3
![Page 21: Lab activity information](https://reader035.vdocuments.site/reader035/viewer/2022062501/56815b6b550346895dc961c0/html5/thumbnails/21.jpg)
If a bullet leaves the muzzle of a gun with a speed of 500 m/s, and the barrel of the rifle is .9 m long. What is the acceleration of the bullet while in the barrel?
Problem #4
![Page 22: Lab activity information](https://reader035.vdocuments.site/reader035/viewer/2022062501/56815b6b550346895dc961c0/html5/thumbnails/22.jpg)
Given: Vf = 500 m/s D = .9 m Vi = 0 m/s
Unknown: A =
Problem #4
![Page 23: Lab activity information](https://reader035.vdocuments.site/reader035/viewer/2022062501/56815b6b550346895dc961c0/html5/thumbnails/23.jpg)
Equation: a = Vf
2 – vi2 /2d
Problem #4
![Page 24: Lab activity information](https://reader035.vdocuments.site/reader035/viewer/2022062501/56815b6b550346895dc961c0/html5/thumbnails/24.jpg)
Answer :1.38 X 105 m/s/s
Problem #4
![Page 25: Lab activity information](https://reader035.vdocuments.site/reader035/viewer/2022062501/56815b6b550346895dc961c0/html5/thumbnails/25.jpg)
Solution: (500 m/s)2-0 /(2) (0.9 m) =
Problem #4
![Page 26: Lab activity information](https://reader035.vdocuments.site/reader035/viewer/2022062501/56815b6b550346895dc961c0/html5/thumbnails/26.jpg)
A plane travels 600 m while being accelerated uniformly from rest at the rate of 5.0 m/s2. What final velocity does it attain?
Problem #5
![Page 27: Lab activity information](https://reader035.vdocuments.site/reader035/viewer/2022062501/56815b6b550346895dc961c0/html5/thumbnails/27.jpg)
Given: d = 600 m a= 5.0 m/s2
Vi = 0 m/s
Unknown: Vf =
Problem #5
![Page 28: Lab activity information](https://reader035.vdocuments.site/reader035/viewer/2022062501/56815b6b550346895dc961c0/html5/thumbnails/28.jpg)
Equation: Vf
2 =vi2 + 2ad
Problem #5
![Page 29: Lab activity information](https://reader035.vdocuments.site/reader035/viewer/2022062501/56815b6b550346895dc961c0/html5/thumbnails/29.jpg)
Answer: 77.5 m/s
Problem #5
![Page 30: Lab activity information](https://reader035.vdocuments.site/reader035/viewer/2022062501/56815b6b550346895dc961c0/html5/thumbnails/30.jpg)
Solution: Sq root 0 +2(5.0 m/s/s)(600 m) =
Problem #5
![Page 31: Lab activity information](https://reader035.vdocuments.site/reader035/viewer/2022062501/56815b6b550346895dc961c0/html5/thumbnails/31.jpg)
Page 82: 1,5, Page 83 : 8,9,10, 16 Page 84: 24, Reviewing concepts: 1,2,3,8, Applying concepts: 3, 8, 9 Due thursday
Assignment
![Page 32: Lab activity information](https://reader035.vdocuments.site/reader035/viewer/2022062501/56815b6b550346895dc961c0/html5/thumbnails/32.jpg)
Vf = vi + at d = ½ (vf + Vi)t d = vit + ½ at2
Vf2 = vi
2 + 2ad
Vi vf a t Vi d vf t Vi d a t Vf d vi a
Equations of Motion for Uniform acceleration