lab-2b

7/29/2019 LAB-2b

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DEPARTMENT OF ELECTRICAL ENGINEERING

LAB WORK – ET502 POWER ELECTRONICS

EXPERIMENT: 2b

TITLE : SINGLE PHASE HALF-WAVE AND FULL WAVE UNCONTROLLED

RECTIFIER (Practical)

OUTCOME :

Upon completion of this unit, student should be able to:

i. Handle the practical work on the power electronics converters using

appropriate equipment. [CLO3](PLO2,LD2,P3)

OBJECTIVES :

1. Justify the results in Lab 2a

2. Describe the performances of these Rectifiers3. Describe the differences of these Rectifiers

COMPONENTS/EQUIPMENTS:

1. Diodes 1N4002

2. Resistor 1kohm

3. LED

4. AC Supply Unit

5. Oscilloscope

6. Digital Multimeter

BRIEF THEORY :

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One of the important applications of the P-N junction diodes is in convertingalternating current (AC) into direct current (DC). Half-wave rectifiers can be used,but they are highly inefficient in converting AC power to DC power. Additionally theyhave high contents of harmonics, which are difficult to filter out and to smooth outthe ripple in the rectified AC power. On the other hand, full-wave rectifier improveson the conversion efficiency of AC power to DC power. It will also reduce the

harmonic contents of the rectified waveform and reduce the requirement on thesmoothing filter needed to reduce the ripple in the rectified waveform.

PART 1:

Single Phase Half Wave Rectifier

PROCEDURE :

1. Construct the circuit in Figure 1.

2. Set the AC Supply Unit with 12V and connect to the circuit.

3. Connect the probe of the oscilloscope to point A and point B.

4. Draw the waveform obtained.

5. Next, connect the diode in opposite direction.

6. Repeat Step 3 and 4.

PART 2:

Single Phase Full Wave Rectifier

PROCEDURE :

1. Construct the circuit in Figure 1.

2. Set the AC Supply Unit with 12V and connect to the circuit.

3. Connect the probe of the oscilloscope to point A, point B and point C.

4. Draw the waveform obtained.

5. Measure the current at point D. (Remember to select DC range at your digital

multimeter)

6. Next, connect the diode in opposite direction.

7. Repeat Step 3 to 5.

Notes:

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1. In the previous experiment, the value of your voltage was 17Vp where p =

peak.

2. In this experiment, the value of your voltage from the AC Supply Unit is not in

peak value, instead is in rms value.

3. Therefore the conversion of the Vp to Vrms can be done through Vrms =(Vp/√2).

RESULTS:

As your result: print out:

1. Sketch the respective graphs complete with their labels indicating forward

biased and reversed biased.

2. Complete the chart at the next page.

3. Discuss the results by comparing the simulation results and the practicalresults.

Table 1: Results

Single Phase Half WaveRectifier

Single Phase Full WaveRectifier

VinVout

Part 1:

Figure 1: Single Phase Half Wave Rectifier

Part 2:

Point A Point B

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Figure 2: Single Phase Full Wave Rectifier

Point A

Point B

Point C

Point D

lab-2b

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