iodometric titration of peracids – determination of active … titration.pdf · iodometric...

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Iodometric Titration of Peracids – Determination of Active Oxidant Procedure: 1. Dissolve ~1.5 g NaI in 50 mL distilled water. 2. Add 5 mL chloroform and 5 mL glacial acetic acid 3. Accurately weigh 0.1 g peracid and add to the above solution. Make sure the mixture is stirring vigorously. 4. Titrate the mixture with 0.10 M Na 2 S 2 O 3 solution (NB you need to know the concentration of this solution accurately – just diluting a random bottle of 1 M solution, etc. is not ok...) 5. Brown iodine colour fades to yellow then disappears (may be easier to see with starch). As a rough guide, 0.1 g mCPBA should need 9-11 mL 0.100 M Na 2 S 2 O 3 . Chemistry: RCO 3 H + 2I - + 2CH 3 CO 2 H → RCO 2 H + I 2 + 2CH 3 CO 2 - + H 2 O (I 2 liberation by peracid) I 2 + 2 S 2 O 3 2- → 2 I - + S 4 O 6 2- (Titration of I 2 by thiosulphate) So, mol RCO 3 H = mol I 2 = ½ mol S 2 O 3 2- Example calculation for mCPBA (MW 172.57): 0.1007 g mCPBA = 0.584 mmol (if concentration is 100%) Titrated with 9.00 mL of 0.100 M Na 2 S 2 O 3 solution mol Na 2 S 2 O 3 = conc. x vol. = (0.100 mol dm -3 ) x (9.00 x 10 -3 dm 3 ) = 0.900 mmol mol mCPBA = mol I 2 = ½ mol S 2 O 3 2- = (0.900mmol / 2) = 0.450 mmol % mCPBA = 0.450 mmol / 0.583 mmol = 77% Starch indicator solution (0.3% w/v) Add 150 mg starch (Chemstore 19:4) to 50 mL distilled water and heat until almost transparent. Allow to cool to room temperature before use. Store in the dark / prepare immediately before use. Add ~2 mL to the titration mixture just before the endpoint.

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Iodometric Titration of Peracids – Determination of Active Oxidant

Procedure:

1. Dissolve ~1.5 g NaI in 50 mL distilled water.

2. Add 5 mL chloroform and 5 mL glacial acetic acid

3. Accurately weigh 0.1 g peracid and add to the above solution. Make sure the

mixture is stirring vigorously.

4. Titrate the mixture with 0.10 M Na2S2O3 solution (NB you need to know the

concentration of this solution accurately – just diluting a random bottle of 1 M

solution, etc. is not ok...)

5. Brown iodine colour fades to yellow then disappears (may be easier to see with

starch). As a rough guide, 0.1 g mCPBA should need 9-11 mL 0.100 M Na2S2O3.

Chemistry:

RCO3H + 2I- + 2CH3CO2H → RCO2H + I2 + 2CH3CO2- + H2O (I2 liberation by peracid)

I2 + 2 S2O32- → 2 I- + S4O6

2- (Titration of I2 by thiosulphate)

So, mol RCO3H = mol I2 = ½ mol S2O32-

Example calculation for mCPBA (MW 172.57):

• 0.1007 g mCPBA = 0.584 mmol (if concentration is 100%)

• Titrated with 9.00 mL of 0.100 M Na2S2O3 solution

• mol Na2S2O3 = conc. x vol. = (0.100 mol dm-3) x (9.00 x 10-3 dm3) = 0.900 mmol

• mol mCPBA = mol I2 = ½ mol S2O32- = (0.900mmol / 2) = 0.450 mmol

• % mCPBA = 0.450 mmol / 0.583 mmol = 77%

Starch indicator solution (0.3% w/v)

• Add 150 mg starch (Chemstore 19:4) to 50 mL distilled water and heat until almost

transparent.

• Allow to cool to room temperature before use. Store in the dark / prepare

immediately before use.

• Add ~2 mL to the titration mixture just before the endpoint.

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written by Eleanor Merritt
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