introduction to the mips

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Introduction to the MIPS Lecture for CPSC 5155 Edward Bosworth, Ph.D. Computer Science Department Columbus State University

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Introduction to the MIPS. Lecture for CPSC 5155 Edward Bosworth, Ph.D. Computer Science Department Columbus State University. Introduction to the MIPS. - PowerPoint PPT Presentation

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Page 1: Introduction to the MIPS

Introduction to the MIPSLecture for CPSC 5155

Edward Bosworth, Ph.D.Computer Science Department

Columbus State University

Page 2: Introduction to the MIPS

Introduction to the MIPS

• The Microprocessor without Interlocked Pipeline Stages is a RISC microprocessor architecture developed by MIPS Technologies, Inc, starting in about 1981.

• The first commercial product was the R2000, marketed in 1984.

• For a good historical account, go to http://en.wikipedia.org/wiki/MIPS_architecture

• MIPS processors are found in a variety of products, such as TiVo, Cisco routers,the Nintendo 64, and Sony PlayStation.

Page 3: Introduction to the MIPS

MIPS Integer Arithmetic

• The integer arithmetic used in our version of the MIPS is 32-bit arithmetic.

• There is a 64-bit version of the MIPS.• The range of integers represented in 32 bits

Unsigned: 0 to 232 – 1Signed: -231 to 231 – 1

• All memory addresses are unsigned integers.

Page 4: Introduction to the MIPS

8-bit example of Signed Integers

• The number 0 is denoted as 0000 0000.• Consider the pattern 1111 1111.

Add one to this 0000 0001The result is 0000 0000The carry-out from the left column is dropped.

• Thus, the pattern 1111 1111 representsthe negative number -1.

• This pattern generalizes to 16 bits, 32 bits, etc.

Page 5: Introduction to the MIPS

The Two’s Complement

• Recall that the one’s complement of a bit pattern is achieved by changing every 0 to a 1 and every 1 to a 0. What is the sum X + X’?

• We have only 0 + 1 = 1 and 1 + 0 = 1, so X + X’ = -1. Consider the example.X 1011 1001X’ 0100 0110Sum 1111 1111

• If X + X’ = -1, then X + (X’ + 1) = 0; -X = X’ + 1.

Page 6: Introduction to the MIPS

Chapter 2 — Instructions: Language of the Computer — 6

Register Operands Arithmetic instructions use register

operands MIPS has a 32 × 32-bit register file

Use for frequently accessed data Numbered 0 to 31 32-bit data called a “word”

Assembler names $t0, $t1, …, $t9 for temporary values $s0, $s1, …, $s7 for saved variables

Design Principle 2: Smaller is faster c.f. main memory: millions of locations

§2.3 Operands of the C

omputer H

ardware

Page 7: Introduction to the MIPS

The MIPS Register SetThere are 32 registers, 0 - 31

Name Register Number Usage$zero 0 Holds the constant value 0. Read only.$at 1 Reserved for use by the assembler.$v0 – $v1 2 – 3 Holds values from functions.$a0 – $a3 4 – 7 Holds arguments sent to functions$t0 – $t7 8 – 15 Temporary registers, not saved in a call$s0 – $s7 16 – 23 Saved registers$t8 – $t9 24 – 25 More temporary registers$k0 – $k1 26 – 27 Reserved for the Operating System$gp 28 Pointer to global variables$sp 29 The stack pointer$fp 30 The frame pointer, useful in the call stack.$ra 31 Return address from functions.

Page 8: Introduction to the MIPS

Chapter 2 — Instructions: Language of the Computer — 8

Instruction Set The repertoire of instructions of a

computer Different computers have different

instruction sets But with many aspects in common

Early computers had very simple instruction sets Simplified implementation

Many modern computers also have simple instruction sets

§2.1 Introduction

Page 9: Introduction to the MIPS

Variables and Labels

• The idea of a “variable” is a construct of high level languages only. Each variable is given a type, which determines the operations on it.

• In assembly language, there are no variables. Labels are used to identify locations only.The operation is determined by the assembly language instruction only.

Page 10: Introduction to the MIPS

Chapter 2 — Instructions: Language of the Computer — 10

The MIPS Instruction Set Used as the example throughout the book Stanford MIPS commercialized by MIPS

Technologies (www.mips.com) Large share of embedded core market

Applications in consumer electronics, network/storage equipment, cameras, printers, …

Typical of many modern ISAs See MIPS Reference Data tear-out card, and

Appendixes B and E

Page 11: Introduction to the MIPS

Chapter 2 — Instructions: Language of the Computer — 11

Arithmetic Operations Add and subtract, three operands

Two sources and one destinationadd a, b, c # a gets b + c

All arithmetic operations have this form Design Principle 1: Simplicity favours

regularity Regularity makes implementation simpler Simplicity enables higher performance at

lower cost

§2.2 Operations of the C

omputer H

ardware

Page 12: Introduction to the MIPS

Chapter 2 — Instructions: Language of the Computer — 12

Arithmetic Example C code:f = (g + h) - (i + j);

Compiled MIPS code:add t0, g, h # temp t0 = g + hadd t1, i, j # temp t1 = i + jsub f, t0, t1 # f = t0 - t1

NOTE: This is not exactly the MIPS syntax.

Page 13: Introduction to the MIPS

Chapter 2 — Instructions: Language of the Computer — 13

Register Operand Example C code:f = (g + h) - (i + j); f, …, j in $s0, …, $s4

Compiled MIPS code:add $t0, $s1, $s2add $t1, $s3, $s4sub $s0, $t0, $t1

Page 14: Introduction to the MIPS

Chapter 2 — Instructions: Language of the Computer — 14

Memory Operands Main memory used for composite data

Arrays, structures, dynamic data To apply arithmetic operations

Load values from memory into registers Store result from register to memory

Memory is byte addressed Each address identifies an 8-bit byte

Words are aligned in memory Address must be a multiple of 4

MIPS is Big Endian Most-significant byte at least address of a word c.f. Little Endian: least-significant byte at least address

Page 15: Introduction to the MIPS

Big-Endian vs. Little-Endian

Page 16: Introduction to the MIPS

Memory DumpNote: Powers of 256 are 2560 = 1, 2561 = 256, 2562 = 65536, 2563 = 16,777,216

Suppose one has the following memory map as a result of a core dump. The memory is byte addressable.

Address 0x200 0x201 0x202 0x203 Contents 02 04 06 08

What is the value of the 32–bit long integer stored at address 0x200?

This is stored in the four bytes at addresses 0x200, 0x201, 0x202, and 0x203.

Big Endian: The number is 0x02040608. Its decimal value is 22563 + 42562 + 62561 + 81 = 33,818,120

Little Endian: The number is 0x08060402. Its decimal value is 82563 + 62562 + 42561 + 21 = 134,611,970.

Page 17: Introduction to the MIPS

Chapter 2 — Instructions: Language of the Computer — 17

Memory Operand Example 1 C code:g = h + A[8]; g in $s1, h in $s2, base address of A in $s3

Compiled MIPS code: Index 8 requires offset of 32

4 bytes per wordlw $t0, 32($s3) # load wordadd $s1, $s2, $t0

offset base register

Page 18: Introduction to the MIPS

Chapter 2 — Instructions: Language of the Computer — 18

Memory Operand Example 2 C code:A[12] = h + A[8]; h in $s2, base address of A in $s3

Compiled MIPS code: Index 8 requires offset of 32lw $t0, 32($s3) # load wordadd $t0, $s2, $t0sw $t0, 48($s3) # store word

Page 19: Introduction to the MIPS

Chapter 2 — Instructions: Language of the Computer — 19

Registers vs. Memory Registers are faster to access than

memory Operating on memory data requires loads

and stores More instructions to be executed

Compiler must use registers for variables as much as possible Only spill to memory for less frequently used

variables Register optimization is important!

Page 20: Introduction to the MIPS

Chapter 2 — Instructions: Language of the Computer — 20

Immediate Operands Constant data specified in an instructionaddi $s3, $s3, 4 #$s3 = $s3 + 4

No subtract immediate instruction Just use a negative constantaddi $s2, $s1, -1 #$s2 = $s1 - 1

Design Principle 3: Make the common case fast Small constants are common Immediate operand avoids a load instruction

Page 21: Introduction to the MIPS

Chapter 2 — Instructions: Language of the Computer — 21

The Constant Zero MIPS register 0 ($zero) is the constant 0

Cannot be overwritten Useful for common operations

E.g., move between registersadd $t2, $s1, $zero

Page 22: Introduction to the MIPS

Chapter 2 — Instructions: Language of the Computer — 22

Representing Instructions Instructions are encoded in binary

Called machine code MIPS instructions

Encoded as 32-bit instruction words Small number of formats encoding operation code

(opcode), register numbers, … Regularity!

Register numbers $t0 – $t7 are reg’s 8 – 15 $t8 – $t9 are reg’s 24 – 25 $s0 – $s7 are reg’s 16 – 23

§2.5 Representing Instructions in the C

omputer

Page 23: Introduction to the MIPS

Chapter 2 — Instructions: Language of the Computer — 23

MIPS R-format Instructions

Instruction fields op: operation code (opcode) rs: first source register number rt: second source register number rd: destination register number shamt: shift amount (00000 for now) funct: function code (extends opcode)

op rs rt rd shamt funct6 bits 6 bits5 bits 5 bits 5 bits 5 bits

Page 24: Introduction to the MIPS

Chapter 2 — Instructions: Language of the Computer — 24

R-format Example

add $t0, $s1, $s2

special $s1 $s2 $t0 0 add

0 17 18 8 0 32

000000 10001 10010 01000 00000 100000

000000100011001001000000001000002 = 0232402016

op rs rt rd shamt funct6 bits 6 bits5 bits 5 bits 5 bits 5 bits

Page 25: Introduction to the MIPS

Chapter 2 — Instructions: Language of the Computer — 25

Hexadecimal Base 16

Compact representation of bit strings 4 bits per hex digit

0 0000 4 0100 8 1000 c 11001 0001 5 0101 9 1001 d 11012 0010 6 0110 a 1010 e 11103 0011 7 0111 b 1011 f 1111

Example: eca8 6420 1110 1100 1010 1000 0110 0100 0010 0000

Page 26: Introduction to the MIPS

Chapter 2 — Instructions: Language of the Computer — 26

MIPS I-format Instructions

Immediate arithmetic and load/store instructions rt: destination or source register number Constant: –215 to +215 – 1 Address: offset added to base address in rs

Design Principle 4: Good design demands good compromises Different formats complicate decoding, but allow 32-bit

instructions uniformly Keep formats as similar as possible

op rs rt constant or address6 bits 5 bits 5 bits 16 bits

Page 27: Introduction to the MIPS

Chapter 2 — Instructions: Language of the Computer — 27

Stored Program Computers Instructions represented in

binary, just like data Instructions and data stored

in memory Programs can operate on

programs e.g., compilers, linkers, …

Binary compatibility allows compiled programs to work on different computers Standardized ISAs

The BIG Picture

Page 28: Introduction to the MIPS

Chapter 2 — Instructions: Language of the Computer — 28

Memory Layout Text: program code Static data: global

variables e.g., static variables in C,

constant arrays and strings $gp initialized to address

allowing ±offsets into this segment

Dynamic data: heap E.g., malloc in C, new in

Java Stack: automatic storage

Page 29: Introduction to the MIPS

All Memory Maps Use Virtual Addresses

• Virtual memory is a service of the computer’s operating system in conjunction with the MMU (Memory Management Unit).

• Logical addresses are generated by the code and then translated into physical addresses.

• For example, the global pointer contains the logical address 0x1000 8000. The actual physical address is determined by the OS.

Page 30: Introduction to the MIPS

The Stack and Heap

• The stack and heap are two dynamic memory structures, assigned to occupy memory with virtual addresses above the static data.

• To avoid a rigid partitioning of this block of memory, the stack starts at the top and grows down, while the heap starts at the bottom and grows up.

Page 31: Introduction to the MIPS

Chapter 2 — Instructions: Language of the Computer — 31

Logical Operations Instructions for bitwise manipulation

Operation C Java MIPSShift left << << sll

Shift right >> >>> srlBitwise AND & & and, andiBitwise OR | | or, ori

Bitwise NOT ~ ~ nor

Useful for extracting and inserting groups of bits in a word

§2.6 Logical Operations

Page 32: Introduction to the MIPS

Chapter 2 — Instructions: Language of the Computer — 32

AND Operations Useful to mask bits in a word

Select some bits, clear others to 0

and $t0, $t1, $t2

0000 0000 0000 0000 0000 1101 1100 0000

0000 0000 0000 0000 0011 1100 0000 0000

$t2

$t1

0000 0000 0000 0000 0000 1100 0000 0000$t0

Page 33: Introduction to the MIPS

Chapter 2 — Instructions: Language of the Computer — 33

OR Operations Useful to include bits in a word

Set some bits to 1, leave others unchanged

or $t0, $t1, $t2

0000 0000 0000 0000 0000 1101 1100 0000

0000 0000 0000 0000 0011 1100 0000 0000

$t2

$t1

0000 0000 0000 0000 0011 1101 1100 0000$t0

Page 34: Introduction to the MIPS

Chapter 2 — Instructions: Language of the Computer — 34

NOT Operations Useful to invert bits in a word

Change 0 to 1, and 1 to 0 MIPS has NOR 3-operand instruction

a NOR b == NOT ( a OR b )

nor $t0, $t1, $zero

0000 0000 0000 0000 0011 1100 0000 0000$t1

1111 1111 1111 1111 1100 0011 1111 1111$t0

Register 0: always read as zero

Page 35: Introduction to the MIPS

Chapter 2 — Instructions: Language of the Computer — 35

Conditional Operations Branch to a labeled instruction if a

condition is true Otherwise, continue sequentially

beq rs, rt, L1 if (rs == rt) branch to instruction labeled L1;

bne rs, rt, L1 if (rs != rt) branch to instruction labeled L1;

j L1 unconditional jump to instruction labeled L1

§2.7 Instructions for Making D

ecisions

Page 36: Introduction to the MIPS

Chapter 2 — Instructions: Language of the Computer — 36

Compiling If Statements C code:if (i==j) f = g+h;else f = g-h; f, g, … in $s0, $s1, …

Compiled MIPS code: bne $s3, $s4, Else add $s0, $s1, $s2 j ExitElse: sub $s0, $s1, $s2Exit: …

Assembler calculates addresses

Page 37: Introduction to the MIPS

Chapter 2 — Instructions: Language of the Computer — 37

Compiling Loop Statements C code:while (save[i] == k) i += 1; i in $s3, k in $s5, address of save in $s6

Compiled MIPS code:Loop: sll $t1, $s3, 2 add $t1, $t1, $s6 lw $t0, 0($t1) bne $t0, $s5, Exit addi $s3, $s3, 1 j LoopExit: …

Page 38: Introduction to the MIPS

Chapter 2 — Instructions: Language of the Computer — 38

More Conditional Operations Set result to 1 if a condition is true

Otherwise, set to 0 slt rd, rs, rt

if (rs < rt) rd = 1; else rd = 0; slti rt, rs, constant

if (rs < constant) rt = 1; else rt = 0; Use in combination with beq, bne

slt $t0, $s1, $s2 # if ($s1 < $s2)bne $t0, $zero, L # branch to L

Page 39: Introduction to the MIPS

Chapter 2 — Instructions: Language of the Computer — 39

Branch Instruction Design Why not blt, bge, etc? Hardware for <, ≥, … slower than =, ≠

Combining with branch involves more work per instruction, requiring a slower clock

All instructions penalized! beq and bne are the common case This is a good design compromise

Page 40: Introduction to the MIPS

Chapter 2 — Instructions: Language of the Computer — 40

Signed vs. Unsigned Signed comparison: slt, slti Unsigned comparison: sltu, sltui Example

$s0 = 1111 1111 1111 1111 1111 1111 1111 1111 $s1 = 0000 0000 0000 0000 0000 0000 0000 0001 slt $t0, $s0, $s1 # signed

–1 < +1 $t0 = 1 sltu $t0, $s0, $s1 # unsigned

+4,294,967,295 > +1 $t0 = 0

Page 41: Introduction to the MIPS

The MIPS is a Load/Store RISC• Only 2 types of instructions reference memory

Load register from memory: LW, LB, LBU, etc.Store register to memory: SW, SB, etc.

• This restriction leads to a CPU design that is considerably simpler and faster.

• The MIPS is designed to work with a virtual memory system. The load/store feature simplifies the handling of page faults.More on this when we discuss the control unit.

Page 42: Introduction to the MIPS

Chapter 2 — Instructions: Language of the Computer — 42

Byte/Halfword Operations Could use bitwise operations MIPS byte/halfword load/store

String processing is a common caselb rt, offset(rs) lh rt, offset(rs)

Sign extend to 32 bits in rtlbu rt, offset(rs) lhu rt, offset(rs)

Zero extend to 32 bits in rtsb rt, offset(rs) sh rt, offset(rs)

Store just rightmost byte/halfword

Page 43: Introduction to the MIPS

Example: EBCDIC “E”• The EBCDIC for “E” is 0xC5 or 1100 0101.• A LB (load byte) instruction would treat this

as a negative 8-bit number and sign extend it.1111 1111 1111 1111 1111 1111 1100 0101or 0xFFFF FFC5.

• A LBU (load unsigned byte) would treat this as a character and zero extend the value.0000 0000 0000 0000 0000 0000 1100 0101or 0x0000 00C5.

Page 44: Introduction to the MIPS

Value vs. Address

• Consider the following data declaration:L1: .word 7 # Decimal value 7

• Suppose the assembler has located this at address 0x1000 7FF8.

• The instruction lw $a0, L1 would place the value 7 into register $a0.

• The instruction la $a0, L1 would place the value 0x1000 7FF8 into register $a0.