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Introduction and Mathematical Concepts Chapter 1

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Introduction and Mathematical Concepts. Chapter 1. 1.1 The Nature of Physics. Physics has developed out of the efforts of men and women to explain our physical environment. Physics encompasses a remarkable variety of phenomena: planetary orbits radio and TV waves magnetism lasers - PowerPoint PPT Presentation

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Page 1: Introduction and Mathematical Concepts

Introduction and Mathematical Concepts

Chapter 1

Page 2: Introduction and Mathematical Concepts

1.1 The Nature of Physics

Physics has developed out of the effortsof men and women to explain our physicalenvironment.

Physics encompasses a remarkable variety of phenomena:

planetary orbitsradio and TV wavesmagnetismlasers

many more!

Page 3: Introduction and Mathematical Concepts

1.1 The Nature of Physics

Physics predicts how nature will behavein one situation based on the results of experimental data obtained in anothersituation.

Newton’s Laws → Rocketry

Maxwell’s Equations → Telecommunications

Page 4: Introduction and Mathematical Concepts

1.2 Units

Physics experiments involve the measurementof a variety of quantities.

These measurements should be accurate andreproducible.

The first step in ensuring accuracy andreproducibility is defining the units in whichthe measurements are made.

Page 5: Introduction and Mathematical Concepts

1.2 Units

SI units

meter (m): unit of length

kilogram (kg): unit of mass

second (s): unit of time

Page 6: Introduction and Mathematical Concepts

1.2 Units

Page 7: Introduction and Mathematical Concepts

1.2 Units

Page 8: Introduction and Mathematical Concepts

1.2 Units

Page 9: Introduction and Mathematical Concepts

1.2 Units

The units for length, mass, and time (aswell as a few others), are regarded asbase SI units.

These units are used in combination to define additional units for other important

physical quantities such as force and energy.

Page 10: Introduction and Mathematical Concepts

1.3 The Role of Units in Problem Solving

THE CONVERSION OF UNITS

1 ft = 0.3048 m

1 mi = 1.609 km

1 hp = 746 W

1 liter = 10-3 m3

Page 11: Introduction and Mathematical Concepts

1.3 The Role of Units in Problem Solving

Example 1 The World’s Highest Waterfall

The highest waterfall in the world is Angel Falls in Venezuela,with a total drop of 979.0 m. Express this drop in feet.

Since 3.281 feet = 1 meter, it follows that

(3.281 feet)/(1 meter) = 1

feet 3212meter 1

feet 281.3meters 0.979 Length

Page 12: Introduction and Mathematical Concepts

1.3 The Role of Units in Problem Solving

Page 13: Introduction and Mathematical Concepts

1.3 The Role of Units in Problem Solving

Reasoning Strategy: Converting Between Units

1. In all calculations, write down the units explicitly.

2. Treat all units as algebraic quantities. When identical units are divided, they are eliminated algebraically.

3. Use the conversion factors located on the pagefacing the inside cover. Be guided by the fact that multiplying or dividing an equation by a factor of 1does not alter the equation.

Page 14: Introduction and Mathematical Concepts

1.3 The Role of Units in Problem Solving

Example 2 Interstate Speed Limit

Express the speed limit of 65 miles/hour in terms of meters/second.

Use 5280 feet = 1 mile and 3600 seconds = 1 hour and 3.281 feet = 1 meter.

second

feet95

s 3600

hour 1

mile

feet 5280

hour

miles 6511

hour

miles 65 Speed

second

meters29

feet 3.281

meter 1

second

feet951

second

feet95 Speed

Page 15: Introduction and Mathematical Concepts

1.3 The Role of Units in Problem Solving

DIMENSIONAL ANALYSIS

[L] = length [M] = mass [T] = time

221 vtx

Is the following equation dimensionally correct?

TLTT

LL 2

Page 16: Introduction and Mathematical Concepts

1.3 The Role of Units in Problem Solving

Is the following equation dimensionally correct?

vtx

LTT

LL

Page 17: Introduction and Mathematical Concepts

1.4 Trigonometry

Page 18: Introduction and Mathematical Concepts

1.4 Trigonometry

h

hosin

h

hacos

a

o

h

htan

Page 19: Introduction and Mathematical Concepts

1.4 Trigonometry

m2.6750tan oh

m0.80m2.6750tan oh

a

o

h

htan

Page 20: Introduction and Mathematical Concepts

1.4 Trigonometry

h

ho1sin

h

ha1cos

a

o

h

h1tan

Page 21: Introduction and Mathematical Concepts

1.4 Trigonometry

a

o

h

h1tan 13.9m0.14

m25.2tan 1

Page 22: Introduction and Mathematical Concepts

1.4 Trigonometry

222ao hhh Pythagorean theorem:

Page 23: Introduction and Mathematical Concepts

1.5 Scalars and Vectors

A scalar quantity is one that can be describedby a single number:

temperature, speed, mass

A vector quantity deals inherently with both magnitude and direction:

velocity, force, displacement

Page 24: Introduction and Mathematical Concepts

1.5 Scalars and Vectors

By convention, the length of a vectorarrow is proportional to the magnitudeof the vector.

8 lb4 lb

Arrows are used to represent vectors. Thedirection of the arrow gives the direction ofthe vector.

Page 25: Introduction and Mathematical Concepts

1.5 Scalars and Vectors

Page 26: Introduction and Mathematical Concepts

1.6 Vector Addition and Subtraction

Often it is necessary to add one vector to another.

Page 27: Introduction and Mathematical Concepts

1.6 Vector Addition and Subtraction

5 m 3 m

8 m

Page 28: Introduction and Mathematical Concepts

1.6 Vector Addition and Subtraction

Page 29: Introduction and Mathematical Concepts

1.6 Vector Addition and Subtraction

2.00 m

6.00 m

Page 30: Introduction and Mathematical Concepts

1.6 Vector Addition and Subtraction

2.00 m

6.00 m

222 m 00.6m 00.2 R

R

m32.6m 00.6m 00.2 22 R

Page 31: Introduction and Mathematical Concepts

1.6 Vector Addition and Subtraction

2.00 m

6.00 m

6.32 m

00.600.2tan

4.1800.600.2tan 1

Page 32: Introduction and Mathematical Concepts

1.6 Vector Addition and Subtraction

When a vector is multiplied by -1, the magnitude of the vector remains the same, but the direction of the vector is reversed.

Page 33: Introduction and Mathematical Concepts

1.6 Vector Addition and Subtraction

A

B

BA

A

B

BA

Page 34: Introduction and Mathematical Concepts

1.7 The Components of a Vector

. ofcomponent vector theand

component vector thecalled are and

r

yx

y

x

Page 35: Introduction and Mathematical Concepts

1.7 The Components of a Vector

.AAA

AA

A

yx

that soy vectoriall together add and

axes, and the toparallel are that and vectors

larperpendicu twoare of components vector The

yxyx

Page 36: Introduction and Mathematical Concepts

1.7 The Components of a Vector

It is often easier to work with the scalar components rather than the vector components.

. of

componentsscalar theare and

A

yx AA

1. magnitude with rsunit vecto are ˆ and ˆ yx

yxA ˆˆ yx AA

Page 37: Introduction and Mathematical Concepts

1.7 The Components of a Vector

Example

A displacement vector has a magnitude of 175 m and points atan angle of 50.0 degrees relative to the x axis. Find the x and ycomponents of this vector.

rysin

m 1340.50sinm 175sin ry

rxcos

m 1120.50cosm 175cos rx

yxr ˆm 134ˆm 112

Page 38: Introduction and Mathematical Concepts

1.8 Addition of Vectors by Means of Components

BAC

yxA ˆˆ yx AA

yxB ˆˆ yx BB

Page 39: Introduction and Mathematical Concepts

1.8 Addition of Vectors by Means of Components

yx

yxyxC

ˆˆ

ˆˆˆˆ

yyxx

yxyx

BABA

BBAA

xxx BAC yyy BAC