internal degrees of the freedom of the nuclear matter

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1 Internal degrees of the freedom of the nuclear matter A.Malakhov Joint Institute for Nuclear Research, Dubna Joint Institute for Nuclear Research, Dubna [email protected] [email protected] Hadron Structure 2011 Tatranská Štrba, Slovak Republic, June 27th - July 1st, 2011

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Internal degrees of the freedom of the nuclear matter. A.Malakhov. Joint Institute for Nuclear Research, Dubna [email protected]. Hadron Structure 2011 Tatranská Štrba, Slovak Republic, June 27th - July 1st, 2011. A.M.Baldin:. I + II → 1 + 2 + 3 + …. b ik = - ( u i – u k ) 2. - PowerPoint PPT Presentation

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Page 1: Internal degrees of the freedom of the nuclear matter

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Internal degrees of the freedom of the nuclear matter

A.Malakhov

Joint Institute for Nuclear Research, DubnaJoint Institute for Nuclear Research, Dubna

[email protected]@lhe.jinr.ru

Hadron Structure 2011

Tatranská Štrba, Slovak Republic, June 27th - July 1st, 2011

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A.M.Baldin and L.A.Didenko. Fortschr. Phys. 38 (1990) 4, 261-332.

I + II → 1 + 2 + 3 + …

bik = - (ui – uk)2

i, k = I, II, 1, 2, 3, ….

A.M.Baldin:

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• Correlation Depletion Principle (CDP)

• Invariant definition of hadron jets

• Automodelity Principle

This approach in 4-velocity space was very fruitful:

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Classification of relativistic nuclear collisions on bik

bik ~ 10-2

classic nuclear physics

0.1 < bik < 1

intermediate domain

bik >> 1

nuclei should be considered asquark-gluon systems

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Dependence of T0 parameter for pion at 180o for p-Cu collisions on the energy of incident proton Tp. Pion cross-section parameterized by the form E·d/dp3 = C·exp(-T/T0), where T is the pion laboratory kinetic energy

L.S.Schroeder et al. Phys. Rev. Lett., v.43, No.24, 1979, p.1787

E·d/dp3 = C·exp(-T/T0)

p +Cu → + …

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- + p → 0 (ω0, η0) + n

t - square of 4-momentum transferred

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d/dbI1 = A· exp(-bI1/B)

A.I.Malakhov, G.L.Melkumov. JINR Rapid Commun., No.19-86 (1986) pp.32-39).

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As it possible see in figure asymptotic regime is beginning with

pion momentum p 25 GeV.

bI II = - (uπ – up)2 = - (1 - 2uπup – 1) =

= 2(uπup -1) = 2(Eπ/mπ – 1) = 2Tπ /mπ

2∙ 25/0.130 380.

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Conclusion• bik is the good parameter describing

internal structure of interacting particles and nucleus

• This parameter shows the areas for manifestation various internal degrees of freedom of the interacting objects

• It is possible that in area bik ≥ 400 the internal degrees of freedom of quarks start to be shown

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Thank you !