instrumentation types and characteristics-2

8/13/2019 Instrumentation types and characteristics-2

1/42

: 3 & 4

2

, A

. , (B

H, 2001)


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3 & 4,

D 03092012 050920122.2

1. A ( )2. //

3.

4.

5. 6.

7.

8.

9. 10. H

11. D


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)

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2.

.

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4. I ,

(..)

.

5. I

,

.

6.

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H,

( )


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E 1

A 010

1.0% .

. .

1.0 ,

10% .


7/42

E 2

A 0 to 10 bar pressure gauge was found to have an error of

0.15bar when calibrated by the manufacturer. Calculate (a) the

percentage error of the gauge and (b) the possible error as a

percentage of the indicated value when a reading 0f 2.0 bars was

obtained in a test.

Solution:


8/42

,

0 1 ,

.


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2.2.2 //

1.

.2. I

, .

3. H . A .

4. , .


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5. , , , .

6. , , , .

7. B .

8.

.


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E

F: I


12/42

E D

. , .

B 1 .

2 . , .

F, 3 ,

.


13/42

2.2.3

.

.


14/42

E 1

1000 5%

.


15/42

2.2.

.


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2.2.

I .

F 2.6 .

, . . , , C 11.)

.

.


17/42

. 2. .


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I


19/42

E

A

0 200 2.0 .


20/42

2.2.

.

.


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, :


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E

I, , 2

10 ,

).


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I

1, 2, 3,, . ,

1, 2, 3, , . .


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E


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E


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2.2.

I ,

.

. ,

.

E.A 15

/. , , 15 /.


27/42

2.2.

..,

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.

.

A 20 /. , 5 /. 5 / .


28/42

E 1

I

. I ,

. .


29/42

E 2

A 0150

0.1 % F. F .

= (0.001)(150)

= 0.15


30/42

I ,

.

,

.


31/42

E 3A 5 /C. F

0.2 C.

:

A 0.2 C

(5 /C)(0.2 C ) = 1.0

, 1.0 .


32/42

2.2.

1. A

, , .

2.

. A ,, ., .

3. .


33/42

4.

, : B

5. . .

6. .


34/42

7.

.

.

/C.

.


35/42

9. /

.

10.I

.


36/42

E : () ; ()

; () .


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38/42

2.2.10 F

.

I ,

.

I , ().

. ,

.


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40/42

2.2.11

D

.

. H

.


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instrumentation types and characteristics-2

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