in a spur gear drive for a stone crusher

8/12/2019 In a Spur Gear Drive for a Stone Crusher

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In a spur gear drive for a stone crusher, the gears are made of C40 steel. The pinion

is transmitting 30kW at 1200 r.p.m. The gear ratio is 3. ear is to !ork " hours per

da#, si$ da#s a !eek and for 3 #ears. %esign the drive.

P = 30 kW, N1= 1200 rpm, i = 3

Since the pinion and gear are made of same material, therefore we have to do the design

of pinion alone.

&aterial selection Pinion and gear are made of ! "0 Steel,

#ss$me s$rface hardness % 3&0

'ear life = ( ) &2 ) * ) 3 = +"(( ho$rs

ife in n$m-ers of ccles, N = *0 ) +"(( )1200 = &3./ ) 10+ ccles

!alc$lation of initial design tor$e t

4esign tor$e t = t. 5. 5 d = 1.3 ) 23(.+3 = 310.3" Nm

Calculation of 'e(, )*+, )*c-

6e = 2.1& ) 10& N7mm2

n = 2 5 8 = 1.& , N= &3./) 10+ccles9 5 -l=0.+, 8$= *30 N7mm2

2

1 7&.**21203&.0 mm N

u =+=

− σ σ

1".1

−= σ σ

σ nK K bl

b = 111.23 N7mm2

!: = 2*.& ;:! = && 5 cl = 0.&(&

[ ] Kcl HRC R

C c =σ = (&2.*" N7mm2

Center distance #ss$me < =0.3

[ ]

[ ]3

2

+".0=1>

+≥

ψ σ i

t M

eq

E

c

ia = 1&& mm

?1 = 1+, ?2 = i.?1 = 3 ) 1+ = &1

21

2

z z

a

m

+= = ".&* mm standard m = & mm

evised Center distance a = 1+0 mm



Calculation of +, d1, v and /p-

- = <.a = 0.3 ) 1+0 = &1 mm

d1= m.?1= & ) 1+ = (& mm

Picth line velocit >v =21

11

z z

N d

+

π

= &.3" m7s

< p = -7d1 = 0.* 5 =1.03 5 d = 1." evised %esign tor(ue )&t 344.24 m

Check for ending-

abmy

t M i

b

=1> +=σ = (*.+( N7mm2 @ 8 -

Check for !ear strength-

ib

i

t M eq E

a

i

c

1

=1>+".0

++=σ = +*&./ N7mm2 @ 8c

helical gear !ith 30o heli$ angle has to transmit 3 kW at 100 rpm !ith a speed

reduction ratio of 2.. If the pinion has 24 teeth, %esign the gear for 20 o full depth

teeth and service is continuous. ssume 40i2Cr1&o2" material for +oth pinion

and !heel.Selection of material properties

8$= 1&&0 N7mm2 S$rface hardness && :! and core hardness%3&0A;N

!alc$lation of design stresses

n = 2.& 5 8 = 1.& N= 10000 ) *0 ) 1&00 =/0 ) 10+ccles9 5 -l=0.+

1

".1

3−

= σ

σ

σ

nK

bl K

b

= 1+3.1N7mm2

2

7&.**21203&.01 mm N u =+=− σ σ

!: = 2*.& ;:! = && 5 cl = 0.&(&

[ ]cl

K HRC R

C c =σ =(&2.*N7mm2

t = 2(/.** N.m 6 = 2.1)10& i = 2.& < =0.&



• !alc$lation of a)ial mod$le

m)= 2a7>E? = (.01mm Standard m)=10mm

:evise a and o-tain d1

a = 0.& m)>E? = 32& mm

Pitch circle diameter of worm = d1= m) = 110 mm

Ds=D17cosF tanF= C7 = % lead angle F = 1&.2&o

D1 = Pitch line velocit of the worm

=

×1000*0

11nd π

= (.3 m7s

:evised 8c = 12+ N7mm2

%etermination of induced stresses

10

31=7>

7

&"0

+=

t M

a

q z

q z cσ

= 120 N7mm2@ 8c

v x

t

bqzym

M 3

/.1=σ = 2.33 N7mm2 @ 8 -

=tan>

tan/&.0

ρ ν

ν η

+= = 0.("/

6eat emoval nal#sis

>1GH ) Inp$t Power = 22*0 Nm

%esign a 12 speed gear +o$ for an all geared headstock of a lathe. &a$imum and

minimum speeds are 700 rpm and 2 rpm respectivel#. The drive is from an electric

motor giving 2.2 kW at 1440 rpm.

Progression ratio1

1

min

ma)

−

=

N

n

nϕ = 1.33& Where N B No of Speeds in gear -o)

Jrom :"0 series Speed >Skip " speeds B 2&,33.&, "&, *0, (0, 10*, 1"0, 1/0, 2&0, 33&, "&0 and*00 rpm

Str$ct$ral form$la for 12 speeds

= 3>1 2>3 2>*



machine tool gear +o$ po!ered +# 11 kW, 890 rpm motor is to give 14 spindle

speeds ranging from 20 to 400 rpm. %ra! the kinematic arrangement and the speed

chart.

in a spur gear drive for a stone crusher

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