im3 se m02 t01 l01 - es...2. given z2 1 2z 2 15 = (z 2 3)(z 1 5), write another polynomial in...

16
LESSON 1: Satisfactory Factoring M2-7 © Carnegie Learning, Inc. Satisfactory Factoring Factoring Polynomials to Identify Zeros 1 Learning Goals • Factor higher order polynomials. Distinguish between factoring polynomial equations over the set of real numbers and over the set of complex numbers. Identify zeros of polynomials when suitable factorizations are available. Use the zeros of a polynomial to sketch a graph of the function. You have determined factors of degree-2 equations. How can you factor higher-degree polynomial functions? Warm Up Solve each equation for x. 1. 2x 2 2 4 5 8 2. (x 2 1) 3 2 5 5 0 3. 3(x 2 6) 4 1 11 5 15 4. x 3 2 27 5 0

Upload: others

Post on 25-Jun-2020

2 views

Category:

Documents


0 download

TRANSCRIPT

Page 1: IM3 SE M02 T01 L01 - ES...2. Given z2 1 2z 2 15 = (z 2 3)(z 1 5), write another polynomial in general form that has a factored form of (z 2 3)(z 1 5) with different values for z. A

LESSON 1: Satisfactory Factoring • M2-7

© C

arne

gie

Lear

ning

, Inc

.

Satisfactory FactoringFactoring Polynomials to Identify Zeros

1

Learning Goals• Factor higher order polynomials.• Distinguish between factoring polynomial equations

over the set of real numbers and over the set of complex numbers.

• Identify zeros of polynomials when suitable factorizations are available.

• Use the zeros of a polynomial to sketch a graph of the function.

You have determined factors of degree-2 equations. How can you factor higher-degree polynomial functions?

Warm UpSolve each equation for x.

1. 2x2 2 4 5 8

2. (x 2 1)3 2 5 5 0

3. 3(x 2 6)4 1 11 5 15

4. x3 2 27 5 0

IM3_SE_M02_T01_L01.indd 7IM3_SE_M02_T01_L01.indd 7 8/24/18 3:13 AM8/24/18 3:13 AM

Page 2: IM3 SE M02 T01 L01 - ES...2. Given z2 1 2z 2 15 = (z 2 3)(z 1 5), write another polynomial in general form that has a factored form of (z 2 3)(z 1 5) with different values for z. A

© C

arne

gie

Lear

ning

, Inc

.

M2-8 • TOPIC 1: Relating Factors and Zeros

GETTING STARTED

Factor Tree Factory

At the Factor Tree Factory, a factor machine takes any whole number as input and outputs one of its factor pairs.

1. Suppose the number 24 is entered into the machine.

a. What factor pairs might you see as the output?

b. How do you know whether two numbers are a factor pair of 24?

c. Can 5 be an output value? Explain your reasoning.

2. Cherise and Jemma each begin a factor tree for 24 using different outputs from the factor machine.

Cherise

24

2 12

Jemma

24

3 8

Cherise says both factor trees will show the same prime factorization when completed. Jemma says because they each started with a different factor pair, the prime factorizations will be different. Who’s correct? Complete each factor tree to justify your answer.

© C

arne

gie

Lear

ning

, Inc

.

?

24

IM3_SE_M02_T01_L01.indd 8IM3_SE_M02_T01_L01.indd 8 8/24/18 3:13 AM8/24/18 3:13 AM

Page 3: IM3 SE M02 T01 L01 - ES...2. Given z2 1 2z 2 15 = (z 2 3)(z 1 5), write another polynomial in general form that has a factored form of (z 2 3)(z 1 5) with different values for z. A

LESSON 1: Satisfactory Factoring • M2-9

© C

arne

gie

Lear

ning

, Inc

.3. Consider the expression 2 ? 2 ? 2 ? 3.

a. How does 2 ? 2 ? 2 ? 3 relate to the factors determined by Cherise and Jemma?

b. How does it relate to 24?

4. If you know a factor of a given whole number, how can you determine another factor?

5. What is the remainder when you divide a whole number by any of its factors? Explain your reasoning.

6. Create a factor tree to show the prime factorization of each number.

a. 66 b. 210

IM3_SE_M02_T01_L01.indd 9IM3_SE_M02_T01_L01.indd 9 8/24/18 3:13 AM8/24/18 3:13 AM

Page 4: IM3 SE M02 T01 L01 - ES...2. Given z2 1 2z 2 15 = (z 2 3)(z 1 5), write another polynomial in general form that has a factored form of (z 2 3)(z 1 5) with different values for z. A

M2-10 • TOPIC 1: Relating Factors and Zeros

Throughout your previous mathematics courses, you have applied the idea that a whole number can be decomposed into a product of its factors to solve a variety of problems. In this lesson, you will explore different methods of decomposing a polynomial into a product of its factors. Once you have factored a polynomial, you can use the factors to identify the zeros and then use the zeros to sketch a graph.

To begin factoring any polynomial, always look for a greatest common factor (GCF). You can factor out the greatest common factor of the polynomial, and then factor what remains.

Factoring Out a GCFAC TIVIT Y

1.1

b. Completely factor the expression that Ping and Shalisha started to factor.

c. Use the factors to identify the zeros of f(x) = 3x3 1 12x2 2 36x. Then sketch the graph of the polynomial.

x

y

Remember:

A greatest common factor can be a variable, constant, or both.

1. Ping and Shalisha each attempt to factor 3x3 1 12x2 2 36x by factoring out the greatest common factor.

Ping3x3 1 12x2 2 36x

3x(x2 1 4x 2 12)  

Shalisha3x3 1 12x2 2 36x

3(x3 1 4x2 2 12x)

a.  Analyze each student’s work. Determine which student is correct and explain the inaccuracy in the other student’s work.

© C

arne

gie

Lear

ning

, Inc

.

IM3_SE_M02_T01_L01.indd 10IM3_SE_M02_T01_L01.indd 10 8/24/18 3:13 AM8/24/18 3:13 AM

Page 5: IM3 SE M02 T01 L01 - ES...2. Given z2 1 2z 2 15 = (z 2 3)(z 1 5), write another polynomial in general form that has a factored form of (z 2 3)(z 1 5) with different values for z. A

LESSON 1: Satisfactory Factoring • M2-11

© C

arne

gie

Lear

ning

, Inc

.2. Factor each polynomial function and identify the zeros. Then,

use the factors to sketch a graph of the function defined by the polynomial.

a. f(x) = 3x3 1 3x2 2 6x

x

y

b. f(x) = 2x2 1 6x

     

x

y

Remember:

Look for a greatest common factor first. Identify the zeros and other key points before graphing.

c. f(x) = 3x2 2 3x 2 6

         

x

y

d. f(x) = 10x2 2 50x 2 60

     

x

y

3. Analyze the factored form and the corresponding graphs in Questions 1 and 2. What do the graphs in Question 1 and Question 2, parts (a) and (b) have in common that the graphs of Question 2, parts (d) and (e) do not? Explain your reasoning.

4. Write a statement about the graphs of all polynomials that have a monomial GCF that contains a variable.

IM3_SE_M02_T01_L01.indd 11IM3_SE_M02_T01_L01.indd 11 8/24/18 3:13 AM8/24/18 3:13 AM

Page 6: IM3 SE M02 T01 L01 - ES...2. Given z2 1 2z 2 15 = (z 2 3)(z 1 5), write another polynomial in general form that has a factored form of (z 2 3)(z 1 5) with different values for z. A

M2-12 • TOPIC 1: Relating Factors and Zeros

5. Tony and Eva each attempt to factor f(x) = x3 − 2x2 + 2x. Analyze their work.

a. If you consider the set of real numbers, who’s correct? If you consider the set of complex numbers, who’s correct? Explain your reasoning.

b. Use the Distributive Property to rewrite Eva’s function to verify that the function in factored form is equivalent the original function in standard form.

c. Identify the zeros of the function f(x).

Remember:

The set of complex numbers is the set of numbers that includes both real and imaginary numbers.

TonyFirst, I removed the GCF, x.

The expression x2 - 2x + 2 cannot be factored, sof(x) = x(x2 - 2x + 2).

Evaf(x) = x(x2 - 2x + 2)x2 − 2x + 2 = 0

x = 2(22) ± √ _________________

(22)22 4(1)(2) _________________________

2(1)

x = 2 ± √ _____

2 4 __________ 2

x = 2 ± 2i _________________________ 2 x = 1 ± i

The function in factored form isf(x) = (x)[x − (1 + i)][x − (1 − i)].

© C

arne

gie

Lear

ning

, Inc

.

IM3_SE_M02_T01_L01.indd 12IM3_SE_M02_T01_L01.indd 12 8/24/18 3:13 AM8/24/18 3:13 AM

Page 7: IM3 SE M02 T01 L01 - ES...2. Given z2 1 2z 2 15 = (z 2 3)(z 1 5), write another polynomial in general form that has a factored form of (z 2 3)(z 1 5) with different values for z. A

LESSON 1: Satisfactory Factoring • M2-13

© C

arne

gie

Lear

ning

, Inc

.6. Analyze each expression.

x2 + 4    x2 − 4    x2 + 2x + 5    x2 + 4x − 5

−x2 + x + 12     x2 + 4x − 1     −x2 + 6x − 25

a. Sort each expression based on whether it can be factored over the set of real numbers or over the set of imaginary numbers.

Complex Factors

Real Factors Imaginary Factors

b. Factor each expression over the set of complex numbers.

Some functions can be factored over the set of real numbers. However, all functions can be factored over the set of complex numbers.

IM3_SE_M02_T01_L01.indd 13IM3_SE_M02_T01_L01.indd 13 8/24/18 3:13 AM8/24/18 3:13 AM

Page 8: IM3 SE M02 T01 L01 - ES...2. Given z2 1 2z 2 15 = (z 2 3)(z 1 5), write another polynomial in general form that has a factored form of (z 2 3)(z 1 5) with different values for z. A

© C

arne

gie

Lear

ning

, Inc

.

M2-14 • TOPIC 1: Relating Factors and Zeros

Certain polynomials in quadratic form may have common factors in some of the terms, but not all terms. In this case, it may be helpful to write the terms as a product of 2 terms. You can then substitute the common term with a variable, z, and factor as you would any polynomial in quadratic form. This method of factoring is called chunking.

Using Structure to Factor Polynomials

AC TIVIT Y

1.2

Worked Example

You can use chunking to factor 9x2 1 21x 1 10.

Notice that the first and second terms both contain the common factor 3x.

9x2 1 21x 1 10 5 (3x)2 1 7(3x) 1 10 Rewrite terms as a product of common factors.

5 z2 1 7z 1 10 Let z 5 3x.

5 (z 1 5)(z 1 2) Factor the quadratic.

5 (3x 1 5)(3x 1 2) Substitute 3x for z.

The factored form of 9x2 1 21x 1 10 is (3x 1 5)(3x 1 2).

x

y

1. Use chunking to factor and identify the zeros of f(x) 5 25x2 1 20x 2 21. Then sketch the polynomial.

IM3_SE_M02_T01_L01.indd 14IM3_SE_M02_T01_L01.indd 14 8/24/18 3:13 AM8/24/18 3:13 AM

Page 9: IM3 SE M02 T01 L01 - ES...2. Given z2 1 2z 2 15 = (z 2 3)(z 1 5), write another polynomial in general form that has a factored form of (z 2 3)(z 1 5) with different values for z. A

LESSON 1: Satisfactory Factoring • M2-15

© C

arne

gie

Lear

ning

, Inc

.2. Given z2 1 2z 2 15 = (z 2 3)(z 1 5), write another polynomial

in general form that has a factored form of (z 2 3)(z 1 5) with different values for z.

A special form of a polynomial is a perfect square trinomial. A perfect square trinomial has first and last terms that are perfect squares and a middle term that is equivalent to 2 times the product of the first and last term's square root.

Factoring a perfect square trinomial can occur in two forms.

a2 2 2ab 1 b2 5 (a 2 b)2

a2 1 2ab 1 b2 5 (a 1 b)2

3. Determine which of the polynomial expression(s) is a perfect square trinomial and write it as the square of a sum or difference. If it is not a perfect square trinomial, explain why not.

a. x4 1 14x2 2 49 b. 16x2 2 40x 1 100

c. 64x2 2 32x 1 4 d. 9x4 1 6x2 1 1

Remember:

You can use the difference of two squares to factor a binomial of the form a2 2 b2.The binomial a2 2 b2 5 (a 1 b)(a 2 b).

IM3_SE_M02_T01_L01.indd 15IM3_SE_M02_T01_L01.indd 15 8/24/18 3:13 AM8/24/18 3:13 AM

Page 10: IM3 SE M02 T01 L01 - ES...2. Given z2 1 2z 2 15 = (z 2 3)(z 1 5), write another polynomial in general form that has a factored form of (z 2 3)(z 1 5) with different values for z. A

© C

arne

gie

Lear

ning

, Inc

.

M2-16 • TOPIC 1: Relating Factors and Zeros

4. Colt factors the polynomial expression x3 1 3x2 2 x 2 3.

Coltx3 1 3x2 2 x 2 3

x2(x 1 3) 2 1(x 1 3)

(x 1 3)(x2 2 1)

(x 1 3)(x 1 1)(x 2 1)

a. Explain the steps Colt took to factor the polynomial expression.

x3 1 3x2 2 x 2 3

x2(x 1 3) 2 1(x 1 3) Step 1:

(x 1 3)(x2 2 1) Step 2:

(x 1 3)(x 1 1)(x 2 1) Step 3:                  

b. Use the factors to identify the zeros of f(x) 5 x3 1 3x2 2 x 2 3 and then sketch the graph.

x

y

In polynomials of 4 terms, you may notice that although not all terms share a common factor, pairs of terms might share a common factor. In this situation, you can factor by grouping.

IM3_SE_M02_T01_L01.indd 16IM3_SE_M02_T01_L01.indd 16 8/24/18 3:13 AM8/24/18 3:13 AM

Page 11: IM3 SE M02 T01 L01 - ES...2. Given z2 1 2z 2 15 = (z 2 3)(z 1 5), write another polynomial in general form that has a factored form of (z 2 3)(z 1 5) with different values for z. A

LESSON 1: Satisfactory Factoring • M2-17

© C

arne

gie

Lear

ning

, Inc

.5. Use factor by grouping to factor and identify the zeros of

f(x) 5 x3 1 7x2 2 4x 2 28. Then sketch the polynomial.

x

y

6. Braxton and Kenny both factor the polynomial expression x3 1 2x2 1 4x 1 8. Analyze the set of factors in each student’s work. Describe the set of numbers over which each student factored.

Braxtonx3 1 2x2 1 4x 1 8

x2(x 1 2) 1 4(x 1 2)

(x2 1 4)(x 1 2)

Kennyx3 1 2x2 1 4x 1 8

x2(x 1 2) 1 4(x 1 2)

(x2 1 4)(x 1 2)

(x 1 2i)(x 2 2i)(x 1 2)

According to the Fundamental Theorem of Algebra, any polynomial function of degree n must have exactly n complex factors: f(x) 5 (x 2 r1)(x 2 r2) … (x 2 rn) where r ∈ {complex numbers}.

IM3_SE_M02_T01_L01.indd 17IM3_SE_M02_T01_L01.indd 17 8/24/18 3:13 AM8/24/18 3:13 AM

Page 12: IM3 SE M02 T01 L01 - ES...2. Given z2 1 2z 2 15 = (z 2 3)(z 1 5), write another polynomial in general form that has a factored form of (z 2 3)(z 1 5) with different values for z. A

© C

arne

gie

Lear

ning

, Inc

.

M2-18 • TOPIC 1: Relating Factors and Zeros

Some degree-4 polynomials, written as a trinomial ax4 1 bx2 1 c, have the same structure as quadratics. When this is the case, the polynomial may be factored using the same methods you would use to factor a quadratic. This is called factoring using quadratic form.

7. Factor each polynomial over the set of complex numbers. Use the factors to identify the zeros and then sketch the polynomial.

a. f(x) 5 x4 2 4x3 2 x2 1 4x b. f(x) 5 x4 2 10x2 1 9

x

y

x

y

Worked Example

Factor x4 2 29x2 1 100 using quadratic form.

x4 2 29x2 1 100

(x2 2 4)(x2 2 25)

(x 2 2)(x 1 2)(x 2 5)(x 1 5)

Determine whether you can factor the given trinomial into 2 factors.

Determine whether you can continue to factor each binomial.

IM3_SE_M02_T01_L01.indd 18IM3_SE_M02_T01_L01.indd 18 8/24/18 3:13 AM8/24/18 3:13 AM

Page 13: IM3 SE M02 T01 L01 - ES...2. Given z2 1 2z 2 15 = (z 2 3)(z 1 5), write another polynomial in general form that has a factored form of (z 2 3)(z 1 5) with different values for z. A

LESSON 1: Satisfactory Factoring • M2-19

© C

arne

gie

Lear

ning

, Inc

.

NOTESTALK the TALK

Fracture It to Factor It

You have used many diff erent methods of factoring:

• Factoring Out the Greatest Common Factor

• Chunking

• Factoring by Grouping

• Perfect Square Trinomials

• Factoring Using Quadratic Form

Depending on the polynomial, some methods of factoring are more effi cient than others.

1. Complete the table on the next page by matching each polynomial with the method of factoring you would use from the bulleted list given. Every method from the bulleted list should be used only once. Explain why you chose the factoring method for each polynomial. Finally, write the polynomial in factored form over the set of real numbers.

IM3_SE_M02_T01_L01.indd 19IM3_SE_M02_T01_L01.indd 19 8/24/18 3:14 AM8/24/18 3:14 AM

Page 14: IM3 SE M02 T01 L01 - ES...2. Given z2 1 2z 2 15 = (z 2 3)(z 1 5), write another polynomial in general form that has a factored form of (z 2 3)(z 1 5) with different values for z. A

© C

arne

gie

Lear

ning

, Inc

.

M2-20 • TOPIC 1: Relating Factors and Zeros

2. Factor each polynomial over the set of complex numbers. Explain why you chose the factoring method you used.

a. x4 2 7x2 2 18 b. x4 1 3x2 2 28

Polynomial Method of Factoring Reason Factored Form

3x4 1 2x2 2 8

x2 2 12x 1 36

x3 1 2x2 1 7x 1 14

25x2 2 30x 2 7

2x4 1 10x3 1 12x2

IM3_SE_M02_T01_L01.indd 20IM3_SE_M02_T01_L01.indd 20 8/24/18 3:14 AM8/24/18 3:14 AM

Page 15: IM3 SE M02 T01 L01 - ES...2. Given z2 1 2z 2 15 = (z 2 3)(z 1 5), write another polynomial in general form that has a factored form of (z 2 3)(z 1 5) with different values for z. A

LESSON 1: Satisfactory Factoring • M2-21

© C

arne

gie

Lear

ning

, Inc

.Assignment

Practice1. Factor each polynomial over the set of real numbers. Use the factors to sketch the polynomial.

a. f(x) 5 25x2 2 10x 2 24b. f(x) 5 x3 2 4x2 2 9x 1 36c. f(x) 5 x4 2 25x2 1 144d. f(x) 5 27x3 2 18x2 1 3xe. f(x) 5 16x3 1 54f. f(x) 5 7x4 2 56x

Stretch1. Sketch each piecewise function.

a. g(x) 5 { 2x 1 1,

x , 0

2x2 2 8x

x $ 0

b. f(x) 5 { x,

x , 21

x3 1 x2 2 x 2 1, 21 # x # 1 4

x . 1

RememberYou can factor out the GCF of a polynomial and then factor what remains. Analyzing the structure of a polynomial can help you decide the most effi cient method for factoring. Once you have factored a polynomial, you can use the factors to identify the zeros and then use the zeros to sketch a graph.

WriteDescribe the similarity between the chunking method of factoring and factoring by grouping. Discuss what the structure of a polynomial would look like in order for you to consider using each method.

−8 −6 −4 −2−2

−4

20 4 6 8

−8

−6

8

6

4

2

y

x −8 −6 −4 −2−2

−4

20 4 6 8

−8

−6

8

6

4

2

y

x

IM3_SE_M02_T01_L01.indd 21IM3_SE_M02_T01_L01.indd 21 8/24/18 3:14 AM8/24/18 3:14 AM

Page 16: IM3 SE M02 T01 L01 - ES...2. Given z2 1 2z 2 15 = (z 2 3)(z 1 5), write another polynomial in general form that has a factored form of (z 2 3)(z 1 5) with different values for z. A

© C

arne

gie

Lear

ning

, Inc

.

M2-22 • TOPIC 1: Relating Factors and Zeros

Review1. A manager conducted an 18-year

study of the profi ts of his company. The polynomial function p(x) models the company’s profi ts from the year 1996 (when x 5 0) to the year 2014 (when x 5 18).a. Estimate when the profi t was

$140,000. Explain your reasoning.b. At what point during the 18-year

study was the profi t the lowest? What was the profi t at that time?

c. Determine the average rate of change of the profi t over the entire 18-year study. Explain the meaning of your answer in terms of this problem situation.

2. Determine the average rate of change for the function f(x) 5 22x4 1 x3 2 7x2 2 2x 1 3 over the interval (4, 8).

3. Add or subtract each expression.a. (4x2 2 2x 1 7) 1 (28x2 1 5x 2 25) b. (29x2 1 16x 2 17) 2 (212x2 2 7x 1 3)

160

1412 16

120

10Time Since 1996 (years)

8642 18

p(x)

200

Prof

it (th

ousa

nds)

80

40

0 x

y

IM3_SE_M02_T01_L01.indd 22IM3_SE_M02_T01_L01.indd 22 8/24/18 3:14 AM8/24/18 3:14 AM