ian beardsley's equations of ai

20
of 1 20 Ian Beardsley’s Equations of Artificial Intelligence

Upload: discover

Post on 24-Jul-2016

216 views

Category:

Documents


0 download

DESCRIPTION

It really is quite fascinating.

TRANSCRIPT

Page 1: Ian Beardsley's Equations Of AI

� of �1 20

Ian Beardsley’s Equations of Artificial Intelligence

Page 2: Ian Beardsley's Equations Of AI

� of �2 20

Copyright © 2015 by Ian Beardsley

Page 3: Ian Beardsley's Equations Of AI

� of �3 20

We define the building blocks of organic life by adding down the structural formula of the Amino Acids, and Across the structural formula of the Amino Acids, and taking their ratios. That is why we call it the Amino Acid Cross Theory.

We write out the decimal to the point where it does not need to be rounded up. We write the decimal out to at least two places. We dope silicon (Si) with group III elements, Boron (B) and Gallium (Ga) to make p-type silicon and, dope silicon (Si) with group V elements, such as phosphorus (p) and arsenic (As) to make n-type silicon. This is the basis of AI (artificial intelligence) and should have the golden ratio, or its conjugate in its means.

We see that as:

I am writing a program in C and Python called Discover. It searches for hidden nuances in Nature and the Universe. The first program is called add. It is based on:

The arithmetic mean is the midpoint, c, between two extremes a, and c:

!

The harmonic mean is not necessarily the midpoint between two extremes but is the value that occurs most frequently:

!

The geometric mean, b, between a and c, is the side of a square that has the same area as a rectangle with sides a and c:

!

The following relationship holds:

!

Page 4: Ian Beardsley's Equations Of AI

� of �4 20

The Program add.c

#include <stdio.h> #include <math.h> int main(void) { int n; do { printf("How many numbers do you want averaged? "); scanf("%d", &n); } while (n<=0);

float num[n], sum=0.0, average; for (int i=1; i<=n; i++) { printf("%d enter a number: ", i); scanf("%f", &num[n]); sum+=num[n]; average=sum/n; } printf("sum of your numbers are: %.2f\n", sum); printf("average of your numbers is: %.2f\n", average);

float a, b, product, harmonic; printf("enter two numbers (hint choose P and B): \n"); printf("give me a: "); scanf("%f", &a); printf("give me b: "); scanf("%f", &b); product = 2*a*b; sum=a+b; harmonic=product/sum; printf("harmonic mean: %.2f\n", harmonic); double geometric; geometric=sqrt(a*b); printf("geometic mean: %.2f\n", geometric);}

Page 5: Ian Beardsley's Equations Of AI

� of �5 20

Running Discover

jharvard@appliance (~): cd Dropbox/pset2 jharvard@appliance (~/Dropbox/pset2): ./add transistors are Silicon doped with Phosphorus and Boron Artificial Intelligence would be based on this the golden ratio conjugate is basic to life The Golden Ratio Conjugate Is: 0.618 Molar Mass Of Phosphorus (P) Is: 30.97 Molar Mass Of Boron (B) Is: 10.81 Molar Mass Of Silicon (Si) Is: 28.09 How many numbers do you want averaged? 2 1 enter a number: 9 2 enter a number: 5 sum of your numbers are: 14.00 average of your numbers is: 7.00 enter two numbers (hint choose P and B): give me a: 30.97 give me b: 10.81 harmonic mean: 16.03 geometic mean: 18.30 geometric mean between P and B divided by Si: 0.65 harmonic mean between P and B divided by Si: 0.57 0.65 + 0.57 divided by 2 is: 0.61 those are the the first two digits in the golden ratio conjugate jharvard@appliance (~/Dropbox/pset2):

Page 6: Ian Beardsley's Equations Of AI

� of �6 20

Here we have run the program for phosphorus, boron, and silicon because if artificial intelligence (AI) is to have the golden ratio conjugate in it, this is where it should be found. The guess proved successful. This immediately results in the relationship between artificial intelligence and biological, or organic, life.

Essentially we are saying (The sum of the geometric mean between P and B by Si with the harmonic mean of P and B by Si, their arithmetic mean is the first two digits in the golden ratio conjugate :

\frac { \sqrt { PB } }{ Si } =\frac { (30.97)(10.81) }{ (28.09) } =0.65\\ \frac { 2PB }{ P+B } /Si=\frac { 2(30.97)(10.81) }{ (30.97+10.81) } /28.09=0.57\\ \frac { 0.65+0.57 }{ 2 } =0.61

Page 7: Ian Beardsley's Equations Of AI

� of �7 20

The Golden Ratio

Let us draw a line and divide it such that the length of that line divided by the larger section is equal to the larger section divided by the smaller section. That ratio is The Golden Ratio, or phi:

!

Page 8: Ian Beardsley's Equations Of AI

� of �8 20

That is, we have found the following, where Au is gold, Ag is silver, He is helium, H is hydrogen and 3/10 is 0.3 is the albedo of the earth. The sun fuses hydrogen into helium and, Au/Ag is about 9/5, which is the ratio of the solar radius to the lunar orbital radius:

\frac { \sqrt { PB } (P+B)+2PB }{ 2(P+B)(Si) } \approx \phi \\ \phi =0.618=golden\quad ratio\quad conjugate

\frac { \sqrt { PB } (P+B)\quad +2PB }{ 2(P+B)(Si) } \left[ \frac { 3 }{ 10 } \frac { Au }{ Ag } +\frac { He }{ H } \right] =\frac { COOH }{ { NH }_{ 2 } }

Page 9: Ian Beardsley's Equations Of AI

� of �9 20

Page 10: Ian Beardsley's Equations Of AI

� of �10 20

Page 11: Ian Beardsley's Equations Of AI

� of �11 20

Page 12: Ian Beardsley's Equations Of AI

� of �12 20

Page 13: Ian Beardsley's Equations Of AI

� of �13 20

Page 14: Ian Beardsley's Equations Of AI

� of �14 20

We found the building blocks of AI are in the means of silicon doped with phosphorus and boron and are in Gallium and Arsenic, all used to make transistors. We now show the skeleton of an AI robot should be titanium alloyed with aluminum, and for an older generation AI using Germanium for the semiconductor that the skeleton should be iron. This all makes sense because titanium alloyed with aluminum makes strong lightweight metals used in aerospace, and iron is a key metal to engineering.

Page 15: Ian Beardsley's Equations Of AI

� of �15 20

\sqrt { PB } (P+B)=764.4486\\ 2PB=669.5714\\ 2(P+B)Si=2,347.2004\\ \sqrt { 764.44866 } =27.64866\\ \sqrt { 669.5714 } =25.876\\ (27.64866+25.876)/2=26.76233\approx Al=26.98\\ \sqrt { 2,347.2004 } =48.4479\approx Ti=47.88\\ \sqrt { (Ga)(As) } =72.27\approx Ge=72.61\\ 2(Si)=56.18\approx Fe=55.85

Page 16: Ian Beardsley's Equations Of AI

� of �16 20

Ian Beardsley studied physics at the University of Oregon and worked in astronomy for four years and the state observatory, Pine Mountain Observatory, in the high desert east of Bend, Oregon. His name appears on several papers in The Astrophysical Journal.

Page 17: Ian Beardsley's Equations Of AI

� of �17 20

NOTES

Page 18: Ian Beardsley's Equations Of AI

� of �18 20

Page 19: Ian Beardsley's Equations Of AI

� of �19 20

Page 20: Ian Beardsley's Equations Of AI

� of �20 20