hw 1

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Prove epsilon permutation and kronecker delta function relationship. ε ijk ε ilm =δ jl δ km δ kl δ jm Proof:- Consider ε ijk = | δ i 1 δ i2 δ i 3 δ j 1 δ j2 δ j 3 δ k 1 δ k2 δ k 3 | Equation a For [i j k] = [1 2 3] ε 123 = | δ 11 δ 12 δ 13 δ 21 δ 22 δ 23 δ 31 δ 32 δ 33 | ε 123 = | 1 0 0 0 1 0 0 0 1 | =1 For [i j k] = [2 13] ε 213 = | δ 21 δ 22 δ 23 δ 11 δ 12 δ 13 δ 31 δ 32 δ 33 | = | 0 1 0 1 0 0 0 0 1 | =−1 For [i j k] = [1 13] ε 113 = | δ 11 δ 12 δ 13 δ 11 δ 12 δ 13 δ 31 δ 32 δ 33 | = | 1 0 0 1 0 0 0 0 1 | =0 Hence for even combinations of i,j,k equation a gives 1, for odd combinations gives -1 and for repetitions gives 0.

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hw 1

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Page 1: hw 1

Prove epsilon permutation and kronecker delta function relationship.

ε ijk εilm=δ jlδ km−δ klδ jm

Proof:-

Consider

ε ijk=|δi1 δi2 δi3δ j1 δ j2 δ j3δk 1 δk 2 δk 3

| Equation a

For [i j k] = [1 2 3]

ε 123=|δ 11 δ12 δ13δ21 δ22 δ23δ31 δ32 δ33

|ε 123=|1 0 0

0 1 00 0 1|=1

For [i j k] = [2 13]

ε 213=|δ21 δ22 δ23δ 11 δ12 δ13δ31 δ32 δ33

|=|0 1 01 0 00 0 1|=−1

For [i j k] = [1 13]

ε 113=|δ11 δ 12 δ 13δ11 δ 12 δ 13δ31 δ 32 δ 33

|=|1 0 01 0 00 0 1|=0

Hence for even combinations of i,j,k equation a gives 1, for odd combinations gives -1 and for repetitions gives 0.

Now consider two matrices A, B of same order.

From the properties of matrices we know that

Det(A).Det(B)=Det(AB)

Page 2: hw 1

ε ijk εilm=|{δi1 δi2 δi3δ j1 δ j2 δ j3δk 1 δk 2 δk 3

}{δi1 δi2 δi3δ j1 δ j2 δ j3δ k 1 δ k 2 δk 3

}|