How Tall Is It?2011

Maddie WohlfarthWill Freeman

Maryellen Newton Madeline Held

30°

40

x

30°

Tan=opp/adjTan30=x/40Tan30*40=xx≈23.09

Short leg= long leg / √340/√3=x23.09=x

x + my height ( up to my eyes) = the height of the goal post23.09+5=height of goal postGoal post= 28.09 feet

45°

90°

45°

45°

x ft

22 ft

Tan=opp/adjTan45=x/22Tan45(22)=xx=22 ftIn a 45-45-90 Δ, leg=leg, so x=22 ft.

22 ft+5.58 ft=27.58 ft

My height to my eyes≈5.58 ft Height of the

Goalpost≈27.58 ft

60°

x+my height ( up to my eyes)=the height of the goal post24.25+4.8=height of goal postGoal post=29.05

60°

14 ft

x ft

Tan=opp/adjTan60=x/14Tan60*14=xx=24.25

Short leg=Long leg√314=x√3x=14/√3x=24.25

25°

25°44 ft.

x

Tan 25=

Tan 25=

x + my height ( up to my eyes) = the height of the goal post20.52+5.25=height of goal postGoal post=25.77

x≈20.52

ConclusionWe learned how to use geometry, trigonometry, and special right Δs in everyday life to solve for height and length based problems that can be used in architecture and design. Our average goal post height was 27.62.