7/17/2019 Homework 2

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2)

a)

The original sequence provided is:

5’ CTCTCATTACCCACACACGAAGGAAAGCAGGACCTTCATCCCAGTGACCTCAGCTAAGACTG 3’

 And its complementary (cDNA) :

3’ GAGAGTAATGGGTGTGTGCTTCCTTTCGTCCTGGAAGTAGGGTCACTGGAGTCGATTCTGAC 5’

The translated RNA from the original sequence:

5’ CUCUCAUUACCCACACACGAAGGAAAGCAGGACCUUCAUCCCAGUGACCUCAGCUAAGACUG 3’

The cDNA is translated into cRNA

3’ GAGAGUAAUGGGUGUGUGCUUCCUUUCGUCCUGGAAGUAGGGUCACUGGAGUCGAUUCUGAC 5’

b)

The protein sequence for the original:

L S L P T H E G K Q D L H P S D L S D

For the complementary:

Q S stop L R S L G stop R S C F P S C V G N E

c)

First frame:5’ CUC UCA UUA CCC ACA CAC GAA GGA AAG CAG GAC CUU CAU

CCC AGU GAC CUC AGC UAA GAC3’

L S L P T H E G K Q D L HP S D L S stop D

Second frame:

5’ UCU CAU UAC CCA CAC ACG AAG GAA AGC AGG ACC UUC AUC

CCA GUG ACC UCA GCU AAG ACU3’

7/17/2019 Homework 2

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S H Y P H T K E S R T F I

P V T S A K T

Third frame:

5’ CUC AUU ACC CAC ACA CGA AGG AAA GCA GGA CCU UCA UCC

CAG UGA CCU CAG CUA AGA CUG 3’

L I T H T R R K A G P S S

Q stop P Q L R

 And three frames from the complementary:

Fourth frame:

5’CAG UCU UAG CUG AGG UCA CUG GGA UGA AGG UCC UGC UUU

CCU UCG UGU GUG GGU AAU GAG3’

Q S stop L R S L G stop R S C FP S C V G N E

Fifth frame: 

5’AGU CUU AGC UGA GGU CAC UGG GAU GAA GGU CCU GCU UUC

CUU CGU GUG UGG GUA AUG AG3’

S L S stop G H W D E G P A F

L R V W V M R

Sixth frame: 

5’GUC UUA GCU GAG GUC ACU GGG AUG AAG GUC CUG CUU UCC

UUC GUG UGU GGG UAA UGA GAG3’

V L A E V T G M K V L L S

F V C G stop stop E

As can be seen in the resulting 6 frames, only the second does not have a stop and

hence is the correct one.