home elevator general data 20100705161018
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Home Elevator
General Data
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HOME ELEVATOR
INSTALLATION DATA
Roping 1:1 / 2:1
Pulley (mm) 100
Speed (m/s) 0,15
Rope diameter (mm) 4
N of ropes 3
Rope weight/m (kg) 0,069Height no comp. chain (m) 9
Total rope weight(kg) 1,9
Braking torque (Nm) 55,1
Shaft efficiency(%) 80
Diverted pulley efficiency (%) 100
N of diverted pulleys 0
Nom. torque inst. (Nm) 64,9
Mec. Power(kW) 0,4
Model
MECHANICAL DATA
Nom. torque motor (Nm) 200
Max. torque motor(Nm) 280
Duty cycle (%) 50
Starts/hour 180
Static load (kg) 2000
Nominal speed (rpm) 60
Max. speed (rpm) 225Machine weight (Kg) 78
ELECTRICAL DATA
Nominal consuption (A) 2,5Max. Consumption (A) 10,8
Rated Voltage (V) 165
Nominal power(kW) 1,4
Herzs 6
Brake voltage (Vdc) 210Poles 12
ge75-100-225Home Elevator
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CALCULATION OF THE NUMBER OF THE ROPES
1. INTRODUCTION
The objective of this project is to calculate the number of traction ropes that are
required for the motor Home Elevator. This motor is designed using the machinery
directive U.N.E.-58-120 regulation (cranes and lifting devices), instead of the EN-81
regulation (Safety rules for the construction and installation of lifts).
2. CALCULATIONS
CLASSIFICATION TYPE
To make the rope calculation, first of all we have to classify the machine and see at
which group belongs to. These classification types are defined in the FEM 9.511
regulation Mechanisms Classification. To find the group, first we have to define thefollowing factors.
a- Duty Load.
b- Average operating time per working day.
a- Duty load
The duty load is evaluated in base on 4 types of service conditions, with the following
characteristics:
A. Light
Maximum Load: occasionally
Moderate Load: regularly
Light Load: Small
B. Medium
Maximum Load: frequently
Moderate Load: Regularly
Light Load: Medium
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C. Heavy
Maximum Load: Frequently
Medium Load: Regularly
Light Load: Big
D. Very heavy
Maximum Load: Regularly
Light Load: Very big
Taking into account the service conditions of the home elevator it is considered as
a Heavy duty machine.
b- Average operating time per working day
At it is exposed in the FEM 9.511 regulation, the average working time (t) is
calculated as follows:
60*
***2
V
TNHt=
Where:
H= Average lifting height
N= Number of cycles per hour (a cycle is a movement of up and down travel)
T= working (h) time
V= elevation speed (m/min)
In the home elevator case is considered an installation with the data:
H= 12m
N= 16hours/24cycles=0,67
T=16 h
V= 0.15m/s = 9m/min
So, the average operating time (t) is = 0.47
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CLASSIFICATION TYPE
We know that the Duty Load is Heavy and the average operating time =0.47, so,
from the following table we deduce the classification type of the Home Elevator
Average operating time(hours per day)
Duty Load0.5 1 2 4 8 16
LIGTH M31Bm M41Am M52m M63m
MEDIUMM31Bm
M41Am
M52m
M63m
M74m
HEAVYM31Bm
M41Am
M52m
M63m
M74m
VERY HEAVYM41Am
M52m
M63m
M74m
As per the table, the machine is in the group M4 1Am
ROPE TENSION
The rope tension is going to be calculated for an installation with these specifications:
Load (Q): 375 kg
Car Weight (P): 450kg
Roping: 2:1
Counterweight Balance: 50%
(Tmax) = (P+Q)/2=412,5 kg. Applying a safety factor of 1.25, 515,63 kg or
5058,28 N.
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MINIMUM DIAMETER ROPE CALCULATION
The calculation of the rope diameter is based on the UNE 58-120-91 regulation and it
says: SCd =
Where:
d: minimum rope diameter (mm)
C: rope selection factor [ N
mm
]S: Maximum tension of the rope [N]
As we know per the FEM 9.511 regulation, the Home Elevator is classified in the M4
1Am Group and from the table 1 of the UNE 58-120-91 regulation we know that the
value of C for an elevation mechanism M.4 type is = 0,095N
mm.
Knowing the value of C and once we calculate the maximum tension (Tmax=14347,2 N),
replacing the values in the equation we obtain that the minimum diameter rope is:
28,058.5095,0=d
dmin= 6,76 mm drope= 4 mm
smin= 35,85 mm2 srope= 12,57 mm
2
In the case that we use 4mm2 ropes, the number of ropes that are needed:
57,12
85,35=n
n = 2,85
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MINIMUM BREAKING LOAD CALCULATION
The minimum breaking load calculation it is done with the following calculation as it is
exposed in the UNE 58-120-91 regulation:
pZSF =0
Where:
S: Minimum tension of the rope [N]
Zp: Minimum ratio of practical use.
To calculate the maximum tension in this section, the maximum tension calculated
before is going to be divided by the number of ropes, so:
kNNS 69,109,686.13
5.058,28===
The value of Zp it is specified in the Table 1 of the UNE 58-120-91 regulation, that says
that for a determined elevating mechanism of the group M4 1 Am, the Zp is 4.0.
So, resolving the following equation we obtain that the minimum breaking load it has to
be bigger than:
0,469,10 =F
F0 6,74kN
The real minimum braking load of 4 mm rope cable is: 12,6kN
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MINIMUM PULLEY DIAMETER CALCULATION
To calculate the size of the pulley we use the Table 2 of the UNE58-120-91/1. As per
the table the pulley diameter must be 18 times bigger than the cable diameter.
4X18=72mm