holt mcdougal algebra 2 13-5 compound events 13-5 compound events holt algebra 2 warm up warm up...

Holt McDougal Algebra 2

13-5 Compound Events13-5 Compound Events

Holt Algebra 2

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Lesson QuizLesson Quiz



13-5 Compound Events

Warm UpOne card is drawn from the deck. Find each probability.

1. selecting a two 2. selecting a face card

Two cards are drawn from the deck. Find each probability.

3. selecting two kings when the first card is replaced.

4. selecting two hearts when the first card is not replaced.



Find the probability of mutually exclusive events.

Find the probability of inclusive events.

Objectives



simple eventcompound eventmutually exclusive eventsinclusive events

Vocabulary



A simple event is an event that describes a single outcome. A compound event is an event made up of two or more simple events. Mutually exclusive events are events that cannot both occur in the same trial of an experiment. Rolling a 1 and rolling a 2 on the same roll of a number cube are mutually exclusive events.



Recall that the union symbol means “or.”

Remember!



Example 1A: Finding Probabilities of Mutually Exclusive Events

A group of students is donating blood during a

blood drive. A student has a probability of

having type O blood and a probability of

having type A blood.

Explain why the events “type O” and “type A” blood are mutually exclusive.

A person can only have one blood type.



Example 1B: Finding Probabilities of Mutually Exclusive Events

What is the probability that a student has type O or type A blood?

A group of students is donating blood during a

blood drive. A student has a probability of

having type O blood and a probability of

having type A blood.

P(type O type A) = P(type O) + P(type A)



Check It Out! Example 1a

Each student cast one vote for senior class president. Of the students, 25% voted for Hunt, 20% for Kline, and 55% for Vila. A student from the senior class is selected at random.

Explain why the events “voted for Hunt,” “voted for Kline,” and “voted for Vila” are mutually exclusive.

Each student can vote only once.



Check It Out! Example 1b

What is the probability that a student voted for Kline or Vila?

Each student cast one vote for senior class president. Of the students, 25% voted for Hunt, 20% for Kline, and 55% for Vila. A student from the senior class is selected at random.

P(Kline Vila) = P(Kline) + P(Vila)

= 20% + 55% = 75%



Inclusive events are events that have one or moreoutcomes in common. When you roll a number cube, the outcomes “rolling an even number” and “rolling a prime number” are not mutually exclusive. The number 2 is both prime and even, so the events are inclusive.



There are 3 ways to roll an even number, {2, 4, 6}.

There are 3 ways to roll a prime number, {2, 3, 5}.

The outcome “2” is counted twice when outcomes are added (3 + 3) . The actual number of ways to roll an even number or a prime is 3 + 3 – 1 = 5. The concept of subtracting the outcomes that are counted twice leads to the following probability formula.



Recall that the intersection symbol means “and.”

Remember!



Example 2A: Finding Probabilities of Compound Events

Find the probability on a number cube.

rolling a 4 or an even number

P(4 or even) = P(4) + P(even) – P(4 and even)

4 is also an even number.



Example 2B: Finding Probabilities of Compound Events

rolling an odd number or a number greater than 2

P(odd or >2) = P(odd) + P(>2) – P(odd and >2)

There are 2 outcomes where the number is odd and greater than 2.

Find the probability on a number cube.



Check It Out! Example 2a

A card is drawn from a deck of 52. Find the probability of each.

drawing a king or a heart

P(king or heart) = P(king) + P(heart) – P(king and heart)



Check It Out! Example 2b

drawing a red card (hearts or diamonds) or a face card (jack, queen, or king)

P(red or face) = P(red) + P(face) – P(red and face)

A card is drawn from a deck of 52. Find the probability of each.



Example 3: Application

Of 1560 students surveyed, 840 were seniors and 630 read a daily paper. The rest of the students were juniors. Only 215 of the paper readers were juniors. What is the probability that a student was a senior or read a daily paper?



Example 3 ContinuedStep 1 Use a Venn diagram.

Label as much information as you know. Being a senior and reading the paper are inclusive events.



Step 2 Find the number in the overlapping region.

Subtract 215 from 630. This is the number of senior paper readers, 415.

Step 3 Find the probability.

Example 3 Continued

The probability that the student was a senior or read the daily paper is about 67.6%.

P(senior reads paper)

= P(senior) + P(reads paper) – P(senior reads paper)



Example 3 Continued



Check It Out! Example 3

Of 160 beauty spa customers, 96 had a hair styling and 61 had a manicure. There were 28 customers who had only a manicure. What is the probability that a customer had a hair styling or a manicure?



Check It Out! Example 3 Continued

Step 1 Use a Venn diagram.

Label as much information as you know. Having a hair styling and a manicure are inclusive events.

hair styling manicure

160 customers

63 2833




Step 2 Find the number in the overlapping region.

Subtract 28 from 61. This is the number of hair stylings and manicures, 33.

Step 3 Find the probability. P(hair manicure) =

P(hair) + P(manicure) – P(hair manicure)

The probability that a customer had a hair styling or manicure is 77.5%.



Recall from Lesson 11-2 that the complement of an event with probability p, all outcomes that are not in the event, has a probability of 1 – p. You can use the complement to find the probability of a compound event.



Example 4 Application

Each of 6 students randomly chooses a butterfly from a list of 8 types. What is the probability that at least 2 students choose the same butterfly?

P(at least 2 students choose same) = 1 – P(all choose different)

Use the complement.



Example 4 Continued

P(at least 2 students choose same) = 1 – 0.0769 ≈ 0.9231

The probability that at least 2 students choose the same butterfly is about 0.9231, or 92.31%.



Check It Out! Example 4

In one day, 5 different customers bought earrings from the same jewelry store. The store offers 62 different styles. Find the probability that at least 2 customers bought the same style.

P(two customers bought same earrings) = 1 – P(all choose different)

Use the complement.




P(at least 2 choose the same) 1 – 0.8476 0.1524

The probability that at least 2 customers buy the same style is about 0.1524, or 15.24%.



Lesson Quiz: Part I

You have a deck of 52 cards.

1. Explain why the events “choosing a club” and “choosing a heart” are mutually exclusive.

2. What is the probability of choosing a club or a

heart?

A card can have only one suit.



Lesson Quiz: Part II

The numbers 1–9 are written on cards and placed in a bag. Find each probability.

3. choosing a multiple of 3 or an even number

4. choosing a multiple of 4 or an even number

5. Of 570 people, 365 were male and 368 had brown hair. Of those with brown hair, 108 were female. What is the probability that a person was male or had brown hair?



Lesson Quiz: Part III

6. Each of 4 students randomly chooses a pen from 9 styles. What is the probability that at least 2 students choose the same style? 0.5391

holt mcdougal algebra 2 13-5 compound events 13-5 compound events holt algebra 2 warm up warm up...

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