hm 3
DESCRIPTION
HM 3TRANSCRIPT
Why We Need It?
Fourier Law is for steady flow, in one dimension, and without heat generation. The cases other then this can not be solved by this equation.
Cartesian Coordinates: T(r, , z)
Derivation:
Assumptions:
K (conductivity), c (pecific heat) and (denisity) do not vary with position.
Heat generation is uniform.
Consider a small volume whose dimensions are dx, dy, dz. Material is homogenous and isotropic. Means its properties (density, h, k ) are same everywhere.
Temperature is indicated by T
Temperature is a function of distance do T changes as distance changes ( T changes as dx changes).
So rate of change of temperature T/ x
Change of temperature at a distance dx=> Tx - Tx+dx => T/x dx
In d s Kumar it is => T/x dx
Now
heat inflow during time dt
+ heat generated Eg during time dt
=
heat outflow during time dt
+ change in internal energy during time dt Est
ENERGY BALANCE EQ.
(dqx+dqy+dqz)dt
+Eg(dxdydz)dt
=
(dqx+dx + dqy+dy +dqz+dz)dt
c(dx.dy.dz)dT
Est =mcdT
m= X volume
Now consider single direction x and apply Fourier eq
Heat inflow per unit time:
dqx = -k(dydz) T/x where dy.dz is area
Heat outflow in x direction per unit time: it is increased by dx
dqx+dx = dqx + /x (dqs ).dx = - /x (-k(dydz) T/x ) + /x { (-k(dydz) T/x) dx}
dqx+dx dqx =qx= -k (dx dydz) /x { (T/x ) }
dqx+dx dqx = -k (dx dydz) 2T/x2
Heat outflow in y direction
dqy+dy dqy = -k (dx dydz) 2T/y2
Heat outflow in z direction
dqy+dy dqy = -k (dx dydz) 2T/y2
Putting them in energy balance eq and solving we get GENERAL HEAT CONDUCTION EQ
2T/x2 + 2T/y2 + 2T/z2 + Eg/k = cT/kt = (c/k) (T/t)
(Change in thermalenergy storage) (Net transfer of thermal energy into the control volume (inflow-outflow)control volume (inflow-outflow)) (Thermal energygeneration)
SIGNIFICANCE OF GENERAL HEAT CONDUCTION EQ
This eq. tells us about temp. distribution and heat flow in a solid homogeneous and isotropic material Via conduction.
Thermal Diffusivity
k/ c = is called thermal diffusivity and is property of the material science it consist of all property terms. Greater it is greater is the ability to store or conduct heat.
Thermal diffusivity is ratio of conductivity (k) to thermal storage capacity(c) .
Liquids have low conductivity but high heat storage capacity. Metals have low c and high k.
This also tells us how fast temperature change can occur in a material if surrounding temperature is changed.
Temperature distribution in unsteady state depend on conductivity and storage capacity / but in unsteady state only on conductivity.
If heat generation is nil Eg = 0 this eq. is Fouriers eq. in three dimension.
If system is in steady state but with heat generation this eq. is called poissons eq.
If no heat source and in steady state this is called laplace,s eq.
For one dimension / without generation / steady state the equation is
d2T/dx2 = 0
HEAT CONDUCTION EQUATION (RADIAL SYSTEMS)
When conduction occurs in shapes of radial geometries it is more convinent to work in cylindrical systems.
Cylindrical Coordinates: T(r, , z)
Derivation:
Assumptions: same
Now consider single direction x and apply Fourier eq
Net Heat flow in r direction per unit time
dqr+dr dqr = -k (dr ddz) 2T/r2
Net Heat flow in direction per unit time
dq+d dq = -k (dr ddz) 2T/2
Net Heat flow in z direction per unit time
dqz+dz dqz = -k (dr ddz) 2T/z2
Net heat generated per unit time
Eg r(dr ddz)
Net heat generated per unit time
c r (dr ddz) dT/dt
Putting in energy balance eqn and solving we get
2T/r2 + (1/r) T/r +(1/r2) 2T/2 + 2T/z2 + Eg/k = (c/k) (T/t) =(1/) (T/t)
(Thermal energygeneration) (Change in thermalenergy storage) (Net transfer of thermal energy into the control volume (inflow-outflow)control volume (inflow-outflow))
** Every other thing remains same as derivation before
For one dimension / without generation / steady state the equation is
2T/r2+(1/r) T/r = 0
1/r2 d/dr ( r dT/dr ) = 0
SPHERICAL COORDINATES: T(r, , )
Derivation:
Assumptions: same
Volume = (dr.rd.rsin.d)
Heat flow r- plan, direction per unit time
Inflow = dq = -k(dr . r.d)()
Heat stored or change in heat energy
dq+d - dq = .dt
dq+d - dq = k(dr.rd.rsin.d) []
Heat flow r- plan, direction
Inflow = dq = -k(dr . sin.d)()
dq+d - dq = (q) . rd
solving for time dt
dq+d - dq = k(V) ()().dt
Heat flow - plan, r direction
Similarly
dqr+dr - dqr = (q) . dr
solving for time dt
dqr+dr - dqr = k(V) () . dt
Putting in energy balance eqn and solving +
+ ()() + () + Eg/k =(1/) (T/t)
For one dimension / without generation / steady state the equation is
1/r2 d/dr ( r2 dT/dr ) = 0
OVER ALL
Steady-state conduction, no internal generation of energy
For one-dimensional, steady-state transfer by conduction without heat generation
i = 0 rectangular coordinates
i = 1 cylindrical coordinates
i = 2 spherical coordinates
THERMOPHYSICAL PROPERTIES
Thermal Conductivity: A measure of a materials ability to transfer thermal energy by conduction.
Thermal Diffusivity: A measure of a materials ability to respond to changes in its thermal environment.
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