hidrolika 2

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1 2 3 4

1 ######## 16.845 4.000 0.429 62.940 354.036 224.407

-200.000

#REF!

#REF!

Grafik gabungan Q terhadap Cw

GRAFIK AMBANG LEBAR

-3.625

E1V3V1Modular Ambang

Grafik gabungan Q terhadap V1

REKAPITULASI HASIL PERHITUNGAN

No.

SALURAN TERBUKA

Ambang Lebar Pen

CWHWhwQ

5 6 7

0

150

300

450

600

750

900

62.940

Q

V1

0

150

300

450

600

750

900

0.429

Q

Cv

856.838

856.838

Q



1 2 3 4

1 #VALUE! #VALUE! 3.500 ###### #VALUE! #VALUE

-200.00

#REF!

#REF!

Grafik gabungan Q terha


5 6

-3.943

GRAFIK AMBANG LE

No.Q hw HW CW Modular Ambang

Ambang Lengkung

V1 V3

0

150

300

450

600

750

900

1050

1200

0.000

Q

V1

0

150

300

450

600

750

900

1050

1200

0.000

Q

Cv

971.563

971.563



1 2 3 4

1 #VALUE! #VALUE! 6.000 ###### #VALUE! #VALU

-200.0

#REF

#REF


Grafik gabungan Q terh

5 6

-2.083

V1 V3

Ambang Tajam

No.Q hw HW CW Modular Ambang

GRAFIK AMBANG

0

150

300

450

600

750

900

1050

1200

1350

0.000

Q

V1

0

150

300

450

600

750

900

1050

1200

1350

0.000

Q

Cv

1121.864

1121.8



3.1.1

* Data Hasil Praktikum 100 1000

P = 18.50 = 18.5

∆H = 70.00 = 7

b = 8.00 = 8

y1 = 22.50 = 22.50

y3 = 4.00 = 4

L = 26.50 = 26.5

g = 9.81

1.

1/2

1/2

2.

3 1/3

2 q b2

3 1/3

2 1416.1 8.00

3

2

3. Menghitung tinggi muka air pada hulu di atas ambang

4.

2 2/3

3

2 2/3 0.66667

3 2.55734

39587.4

m

=Q ( ∆H 0.6 )

m2/dtk

m

m/Hg

m

m

m

π * ( 70 *

Analisa Perhitungan Ambang Lebar Pen

Menghitung Debit Air

*π*171.81

0.6 )

=

π*

= 171.81 *

Menghitung Jarak Garis Energi total terhadap permukaan air

hw = * (Q

2

)

= * (11,329.15

)

= 11.22972526

=

*

HW = -

= 4.000

y1 P

= 22.500 - 18.500

( b hw 2/3 g )

= 0.4293

cm

CW =

=

11329.151

( 8.00 16.845 2/3 g )

cm

mm/hg

cm

cm

cm

Menentukan Koefisien Aliran

Q

11,329.15 cm3/dtk

cm

16.845 cm



5.

y3 -

4.00 -

6.

b * y1 b * y3

8.00 * 22.50 8.00 * 4.00

7.

2 g 2 g

2 9.81 2 9.81

8.

9.

g *

9.81 * 259.965

16.123

10. Menentukan Jenis Loncatan Berdasarkan Froude di Awal Loncatan

g *

220.79.81 * 14.86

Loncatan Kritis )

= 62.9422.5

= 4.24 (

= 3.90

Fr =V1

y1

Menentukan Jenis Loncatan

F =L

V1

=62.94

26.5

= 224.4067 - 6392.454435

=

224.4067081 cm

354.0359813

=

Menghitung Beda Tinggi Garis Energi

∆E = E1 - E3

= 6392.454435

+V3

2

= 22.5 +

62.94

= 4.00 +

Menghitung Garis Energi

E1 = y1

V12

+ E3 = y3

= 62.94

4.00

=11,329.15

18.50

Menghitung Data Modular Ambang

=P

HW

=

= -3.625

Menghitung Kecepatan di Awal Loncatan

=Q

V1 V3 =

cm/dtk

Q

=11,329.15

= 354.036

cm

-6168.04773 cm

cm/dtk



3.1.2


P = 17.00 = 17.00

∆H = 90.00 = 9.00

b = 8.00 = 8.00

y1 = 20.50 = 20.50

y3 = 3.20 = 3.20L = 29.50 = 29.50

g = 9.81

1.

1/2

1/2

2.

3 1/32 q b

2

3 1/3

2 ###### 8.00

3

2


4.

2 2/3

3

2 2/3 0.66667

3 2.55734

#VALUE!= #VALUE!

=

#VALUE!

( 8.00 ###### 2/3 g )


CW =

Q

( b hw 2/3 g )

= 20.500 - 17.000

= 3.500 cm

=

HW = y1 - P

#VALUE! cm

= * (#VALUE!

)

= * #VALUE!


hw = * ( Q 2

)

( 90 * 0.6 )

= #VALUE! cm3/dtk

( ∆H * 0.6 ) π

= 171.81 * π *

m2/dtk


Q = 171.81 * π *

cm m

cm mcm m

Analisa Perhitungan Ambang Lengkung

cm m

mm/hg m/Hg

cm m



5.

y3 -

3.20 -

6.

b * y1 b * y3

8.00 * 20.50 8.00 * 3.20

7.

2 g 2 g

2 9.81 2 9.81

8.

9.

g *

9.81 * 289.395

17.012

10. Menentukan Jenis Loncatan Berdasarkan Froude di Awal Loncatan

g *

201.1

9.81 * 14.18

= #VALUE! ( Loncatan Kritis )

Fr =V1

y1

=#VALUE!

20.5

=#VALUE!

29.5

= #VALUE!

= #VALUE!


F =V1

L

cm

∆E = E1 - E3

= #VALUE! - #VALUE!

#VALUE!

= =


#VALUE! cm #VALUE! cm

+V3

2

= 20.5 + #VALUE! = 3.20 +


E1 = y1 +V1

2

E3 = y3

=#VALUE!

=#VALUE!

= #VALUE! = #VALUE!cm/dtk cm/dtk

V1 =Q

V3 =Q

=17.00

3.50

=


-3.94285714


=P

HW



3.1.3


P = 17.00 = 17.00

∆H = 120.00 = 12.00

b = 8.00 = 8.00

y1 = 23.00 = 23.00

y3 = 4.50 = 4.50L = 16.50 = 16.50

g = 9.81

1.

1/2

1/2

2.

3 1/32 q b

2

3 1/3

2 ###### 8.00

3

2


4.

2 2/3

3

2 2/3 0.66667

3 2.55734

#VALUE!= #VALUE!

=

#VALUE!

( 8.00 ###### 2/3 g )


CW =

Q

( b hw 2/3 g )

= 23.000 - 17.000

= 6.000

=

HW = y1 - P

#VALUE!

= * (#VALUE!

)

= * #VALUE!


hw = * ( Q

2

)

( 120 * 0.6 )

= #VALUE! cm3/dtk

( ∆H * 0.6 ) π

= 171.81 * π *

m2/dtk


Q = 171.81 * π *

cm m

cm mcm m

Analisa Perhitungan Ambang Tajam

cm m

mm/hg m/Hg

cm m



5.

y3 -

4.50 -

6.

b * y1 b * y3

8.00 * 23.00 8.00 * 4.50

7.

2 g 2 g

2 9.81 2 9.81

8.

9.

g *

9.81 * 161.865

12.723

10.

g *

225.6

9.81 * 15.02

= #VALUE! ( Loncatan Kritis )

Fr =V1

y1

=#VALUE!

23

=#VALUE!

16.5

= #VALUE!

Menentukan Jenis Loncatan Berdasarkan Froude di Awal Loncatan

= #VALUE!


F =V1

L

∆E = E1 - E3

= #VALUE! - #VALUE!

#VALUE!

= #VALUE! = #VALUE!


+V3

2

= 23 + #VALUE! = 4.50 +


E1 = y1 +V1

2

E3 = y3

=#VALUE!

=#VALUE!

= #VALUE! = #VALUE!

V1 =Q

V3 =Q

=17.00

6.00

= -2.08333



=P

HW



3.2.1

* 100 1000

L = 98.00 0.98 Panjang Pipa

∆H = 170.00 ekanan Air

T = 1.50 Waktu

Vol = 0.05 Vplume Air 5 Liter

= 12.60

= 1.00

Ø = 1/2 * 2.54 0.50

= 1.27

= 0.01270

g = 9.81

=

=

=

=

1.

2.

3. Menghitung Headloss Air

Analisa Perhitungan Saluran Tertutup Pipa Ø 1/2 "

cm

mm/hg

detik


Q =

m3

1/4 * π * d2

=

π

=

=

= 0.653

m

Menghitung Kecepatan

V =

γ Airh = ∆H *

= 170.00 *

= 2142

γ Air Raksa

m3/detik

Q

T

0.0000828

0.000126677

m/detik

12.60

1.00

m2

m30.00012414

V

T

0.00012414

1.50

Data Hasil Praktikum

0.0000828

cm

Luasan

2.142

γ Air Raksa

γ Air

0.000126677

Volume 1/4 * π * d2

* L

mm/Hg



4.

5.

6.

V * Ø

0.653333 *

7.

8.

f * L * V2

2 * Ø * g

0.004699 * 0.98 * 0.653

2 * 1.27 * 9.81

0.004699

67.25

Log 0.653

Menentukan Kecepatan Air

Log h Log 2.142

0.33081947

=

=

=

Menghitung Angka Bilangan Reynold

0.804 *

Re =

0.316

=

=

0.0000828

67.25

0.000000804

Hf =

=

Menghitung Kehilangan Energi

=

Menghitung Faktor Gesek

f =Re

0.316

= 0.00012 m

=

Log V =

=

10-6

0.000000804

Velocity

-0.1849

Kekentalan Air (Velocity)

=



3.2.2

* 100 1000

L = 30.00 0.3

∆H = 240.00 0.24

T = 2.23

Vol = 0.05

= 12.60

= 1.00

Ø = 3/4 * 2.54 0.75

= 1.91

= 0.01905

g = 9.81

=

=

=

=

1.

2.


Analisa Perhitungan Saluran Tertutup Pipa Ø 3/4 "


cm

mm/hg

detik

m3

γ Air Raksa

γ Air

cm

m


* L

0.00008551 m3

Luasan 1/4 * π * d2

0.000285023 m2


Q =V

πT

=0.00008551

2.23

= 0.0000383 m3/detik


V =Q

T

=0.0000383

0.000285023

= 0.135 m/detik

h = ∆H *γ Air Raksa

γ Air

= 240.00 *12.60

1.00

= 3024 mm/Hg 3.024



4.

5.

6.

V * Ø

0.134529 *

7.

8.

f * L * V2

2 * Ø * g

0.049253 * 0.3 * 0.135

2 * 1.91 * 9.81


Log V = Log 0.135 Log h = Log 3.024

= -0.8712 = 0.48058179


= 0.804 * 10-6

= 0.000000804


Re =Velocity

=0.0000383

0.000000804

= 6.42


f =0.316

Re

=0.316

6.42

= 0.000053 m

= 0.049253


Hf =

=



3.2.3

* 100 1000

L = 35.00 0.35

∆H = 270.00 0.27

T = 3.00

Vol = 0.05

= 12.60

= 1.00

Ø = 1.00 * 2.54 1.00

= 2.54

= 0.02540

g = 9.81

=

=

=

=

1.

2.


Analisa Perhitungan Saluran Tertutup Pipa Ø 1 "


cm

mm/hg

detik

m3

γ Air Raksa

γ Air

cm

m


* L

0.00017735 m3

Luasan 1/4 * π * d2

0.000506707 m2


Q =V

πT

=0.00017735

3.00

= 0.0000591 m3/detik


V =Q

T

=0.0000591

0.000506707

= 0.117 m/detik

h = ∆H *γ Air Raksa

γ Air

= 270.00 *12.60

1.00

= 3402 mm/Hg 3.402



4.

5.

6.

V * Ø

0.116667 *

7.

8.

f * L * V2

2 * Ø * g

0.036838 * 0.35 * 0.117

2 * 2.54 * 9.81


Log V = Log 0.117 Log h = Log 3.402

= -0.9331 = 0.53173431


= 0.804 * 10-6

= 0.000000804


Re =Velocity

=0.0000591

0.000000804

= 8.58


f =0.316

Re

=0.316

8.58

= 0.000030 m

= 0.036838


Hf =

=



1 2 3 6 7 8

1 0.000083 0.653 2142.00 -0.185 0.331 67.253 0.004699 0.000

1 2 3 6 7 8

1 0.0000383 0.135 3024.00 -0.8712 0.481 6.416 0.0493 0.000

1 2 3 6 7 8

1 0.0000591 0.11667 3402.00 -0.9331 0.532 8.578 0.0368 0.000

5

5

0.000000804

Veloocity Re

5

0.000000804

Veloocity Re

0.000000804

f Hf

Percobaan pipa Ø 1 "

No.Q V H Log hLog V

4

f Hf

Percobaan pipa Ø 3/4 "

No.Q V H Log h

f Hf

REKAPITULASI HASIL PERHITUNGAN

SALURAN TERTUTUP

Percobaan pipa Ø 1/2 "

No.Q ReVeloocityV H Log hLog V

Log V

4

4

hidrolika 2

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