geometry solving right triangles
DESCRIPTION
GEOMETRY Solving Right Triangles. Warm Up. Use your calculator to find each trigonometric ratio. Round to the nearest hundredth. 1) sin 63˚ 2) cos 27˚ 3) tan 64˚. Right Triangles. You can use trigonometric ratios to change a percent grade to an angle measure. - PowerPoint PPT PresentationTRANSCRIPT
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CONFIDENTIAL 1
GEOMETRY
Solving Right Triangles
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CONFIDENTIAL 2
Warm Up Warm Up
Use your calculator to find each trigonometric ratio. Round to the nearest hundredth.
1) sin 63˚ 2) cos 27˚ 3) tan 64˚
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CONFIDENTIAL 3
Right Triangles
You can use trigonometric ratios to change a percent grade to an angle measure.
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CONFIDENTIAL 4
Angles from Trigonometric Ratios
Use the trigonometric ratio cos A = 0.6 determine which angle of the triangle is /A.
3.6 cm
6 cm4.8 cm
2
1
Cosine is the ratio of the adjacent leg to the hypotenuse.
The leg adjacent to /1 is 3.6. The hypotenuse is 6.
The leg adjacent to /2 is 4.8. The hypotenuse is 6.
cos A = adj. leg
hyp.
cos1 = 3.6
6
cos2 = 4.8
6
Since cos A = cos1,1 is 1.
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CONFIDENTIAL 5
Now you try!
Use the given trigonometric ratio to determine which angle of the triangle is /A.
1a) sin A = 8/17
1b) tan A = 1.875
30.6 m
27 m
14.4 m
2
1
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CONFIDENTIAL 6
Inverse Trigonometric Functions
If tan A = x, then tan-1 x = mA
If sin A = x, then sin-1 x = mA
If cos A = x, then cos-1 x = mA
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CONFIDENTIAL 7
Calculating Angle Measures from Trigonometric Ratios
Use your calculator to find each angle measure to the nearest degree.
tan-1(3.2) = 73 sin-1(0.45) = 27 cos-1(0.5)= 60
A cos-1(0.5) B sin-1(0.45) C tan-1(3.2)
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CONFIDENTIAL 8
Now you try !
Use your calculator to find each angle measure to the nearest degree.
1) tan-1(0.75) 2) cos-1(0.05) 3) sin-1(0.67)
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CONFIDENTIAL 9
Solving Right TrianglesFind the unknown measures. Round lengths to the nearest
hundredth and angle measures to the nearest degree.
7.5
5
C
BAMethod 2:
mA = tan-15
7.5 34
Since the acute angles of a right triangle are complementry,mC 90 - 34 56
sin A =5
AC, so AC =
5
7.5.
AC 5
sin tan-15
7.5 9.01
Method 1:
By the Pythagorean Theorem AC2 = AB2 + BC2 = (7.5) 2 + 52 = 81.25
So AC = 81.25 9.01
mA= tan-15
7.5 34
Since the acute angles of a right triangle are complementry,mC 90 - 34 56
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CONFIDENTIAL 10
Now you try!
Find the unknown measures. Round lengths to the nearest hundredth and angle measures to the nearest degree.
58
14
F
DE
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X
Y
3
3-3 0
LK
J
CONFIDENTIAL 11
Solving a Right Triangle in the Coordinate Plane
The coordinates of the vertices of ∆JKL are J(-1,2), K(-1,-3), and L(3,-3). Find the side lengths to the nearest hundredth and the angle measures to the nearest degree.
Next page
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CONFIDENTIAL 12
Step 1 Find the side lengths. Plot points J, K, and L. JK = 5 KL = 4 By the Distance Formula. JL = [3 - (-1) ]2 + ( -3 -2 )2
= 42 + (-5) 2
= 16 + 25 = 41 6.40
Step 2 Find the angle measures.
m K = 90 JK and KL are
m J = tan-1 4
5 39 KL is opp. J, and JK is adj. to J.
mL 90 - 39 51 The acute s of a rt. are comp.
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CONFIDENTIAL 13
Now you try!
The coordinates of the vertices of ∆RST are R(-3,5), S(4,5), and T(4,-2). Find the side lengths to the nearest
hundredth and the angle measures to the nearest degree.
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CONFIDENTIAL 14
Travel Application
San Francisco’s Lombard Street is known as one of “the crookedest streets in the world.” The road’s eight
switchbacks were built in the 1920s to make the steep hill passable by cars. If the hill has a percent grade of 84%,
what angle does the hill make with a horizontal line? Round to the nearest degree.
84 % = 84/100
An 84% grade means the hill rises 84 ft for every 100 ft of horizontal distance.
Change the percent grade to a fraction
Next page
84 ft
100 ft
C
BA
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CONFIDENTIAL 15
mA = tan-184
100 40
84 ft
100 ft
C
BA
Draw a right triangle to represent the hill. /A is the angle the hill makes with a horizontal line.
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CONFIDENTIAL 16
Now you try!
Baldwin St. in Dunedin, New Zealand, is the steepest street in the world. It has a grade of 38%. To the nearest
degree, what angle does Baldwin St. make with a horizontal line?
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CONFIDENTIAL 17
Now some practice problems for you!
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CONFIDENTIAL 18
Use the given trigonometric ratio to determine which angle of the triangle is /A .
1) sin A = 4
5
2) tan A = 11
3
3) cos A = 0.8
2
1 10 in.6 in.
8 in.
Assessment
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CONFIDENTIAL 19
Use your calculator to find each angle measure to the nearest degree.
1) tan-1(2.1) 2) cos-11
3 3) sin-1(0.61)4) 5) 6)
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CONFIDENTIAL 20
Multi-Step Find the unknown measures. Round lengths to the nearest hundredth and angle measures to the nearest degree.
2)1)
7.4
32A
C
B
Q P8.9
3.1
R
7) 8)
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CONFIDENTIAL 21
9) Find the side lengths to the nearest hundredth and the angle measures to the nearest degree for
the given triangle.
D(4,1), E(4,-2), F(-2,-2)
10) A hill in the Tour de France bike race has a grade of 8%. To the nearest degree, what is the angle that this hill makes with a horizontal line?
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CONFIDENTIAL 22
Angles from Trigonometric Ratios
Use the trigonometric ratio cos A = 0.6 determine which angle of the triangle is /A.
Cosine is the ratio of the adjacent leg to the hypotenuse.
The leg adjacent to /1 is 3.6. The hypotenuse is 6.
The leg adjacent to /2 is 4.8. The hypotenuse is 6.
cos A = adj. leg
hyp.
cos1 = 3.6
6
cos2 = 4.8
6
Since cos A = cos1,1 is 1.
3.6 cm
6 cm4.8 cm
2
1
Let’s review
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CONFIDENTIAL 23
Inverse Trigonometric Functions
If tan A = x, then tan-1 x = mA
If sin A = x, then sin-1 x = mA
If cos A = x, then cos-1 x = mA
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CONFIDENTIAL 24
Calculating Angle Measures from Trigonometric Ratios
Use your calculator to find each angle measure to the nearest degree.
tan-1(3.2) = 73 sin-1(0.45) = 27 cos-1(0.5)= 60
A cos-1(0.5) B sin-1(0.45) C tan-1(3.2)
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CONFIDENTIAL 25
Solving Right TrianglesFind the unknown measures. Round lengths to the nearest hundredth and angle measures to the nearest degree.
Method 2:
mA = tan-15
7.5 34
Since the acute angles of a right triangle are complementry,mC 90 - 34 56
sin A =5
AC, so AC =
5
7.5.
AC 5
sin tan-15
7.5 9.01
Method 1:
By the Pythagorean Theorem AC2 = AB2 + BC2 = (7.5) 2 + 52 = 81.25
So AC = 81.25 9.01
mA= tan-15
7.5 34
Since the acute angles of a right triangle are complementry,mC 90 - 34 56
7.5
5
C
BA
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CONFIDENTIAL 26
Travel Application
San Francisco’s Lombard Street is known as one of “the crookedest streets in the world.” The road’s eight switchbacks were built in the 1920s to make the steep hill passable by cars. If the hill has a percent grade of 84%, what angle does the hill make with a horizontal line? Round to the nearest degree.
84 % = 84/100
An 84% grade means the hill rises 84 ft for every 100 ft of horizontal distance.
Change the percent grade to a fraction
Next page
84 ft
100 ft
C
BA
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CONFIDENTIAL 27
mA = tan-184
100 40
84 ft
100 ft
C
BA
Draw a right triangle to represent the hill. /A is the angle the hill makes with a horizontal line.
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X
Y
3
3-3 0
LK
J
CONFIDENTIAL 28
Solving a Right Triangle in the Coordinate Plane
The coordinates of the vertices of ∆JKL are J(-1,2), K(-1,-3), and L(3,-3). Find the side lengths to the nearest hundredth
and the angle measures to the nearest degree.
Next page
![Page 29: GEOMETRY Solving Right Triangles](https://reader033.vdocuments.site/reader033/viewer/2022061410/56815aa2550346895dc827db/html5/thumbnails/29.jpg)
CONFIDENTIAL 29
Next page
X
Y
3
3-3 0
LK
J
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CONFIDENTIAL 30
Step 1 Find the side lengths. Plot points J, K, and L. JK = 5 KL = 4 By the Distance Formula. JL = [3 - (-1) ]2 + ( -3 -2 )2
= 42 + (-5) 2
= 16 + 25 = 41 6.40
Step 2 Find the angle measures.
m K = 90 JK and KL are
m J = tan-1 4
5 39 KL is opp. J, and JK is adj. to J.
mL 90 - 39 51 The acute s of a rt. are comp.
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CONFIDENTIAL 31
You did a great job today!You did a great job today!