geometry formulas:
DESCRIPTION
Geometry Formulas:. Surface Area & Volume. A formula is just a set of instructions. It tells you exactly what to do! All you have to do is look at the picture and identify the parts. Substitute numbers for the variables and do the math. That’s it! . Let’s start in the beginning… - PowerPoint PPT PresentationTRANSCRIPT
Geometry Formulas:
Surface Area Surface Area & Volume& Volume
A formula is just a set of instructions. It tells you exactly what to do!
All you have to do is look at the picture and identify the parts.
Substitute numbers for the variables and do the math. That’s it!
Let’s start in the beginning…
Before you can do surface area or volume, you have to know the following formulas.
Rectangle A = lw
Triangle A = ½ bh
Circle A = π r²
C = πd
You can tell the base and height of a triangle by finding the right angle:
TRIANGLES
CIRCLESYou must know the difference between RADIUS and DIAMETER.
r
d
Let’s start with a rectangular prism.
Surface area can be done using the formula
SA = 2 lw + 2 wl + 2 lw OR
Either method will gve you the same answer.
you can find the area for each surface and add them up.
Volume of a rectangular prism is V = lwh
Example:
7 cm
4 cm
8 cm Front/back 2(8)(4) = 64
Left/right 2(4)(7) = 56
Top/bottom 2(8)(7) = 112
Add them up!
SA = 232 cm²
V = lwh
V = 8(4)(7)
V = 224 cm³
To find the surface area of a triangular prism you need to be able to imagine that you can take the prism apart like so:
Notice there are TWO congruent triangles and THREE rectangles. The rectangles may or may not all be the same.
Find each area, then add.
Example:
8mm
9mm
6 mm 6mm
Find the AREA of each SURFACE
1. Top or bottom triangle:
A = ½ bh
A = ½ (6)(6)
A = 18
2. The two dark sides are the same.
A = lw
A = 6(9)
A = 54
3. The back rectangle is different
A = lw
A = 8(9)
A = 72
ADD THEM ALL UP!
18 + 18 + 54 + 54 + 72
SA = 216 mm²
SURFACE AREA of a CYLINDER.
You can see that the surface is made up of two circles and a rectangle.
The length of the rectangle is the same as the circumference of the circle!
Imagine that you can open up a cylinder like so:
EXAMPLE: Round to the nearest TENTH.
Top or bottom circle
A = πr²
A = π(3.1)²
A = π(9.61)
A = 30.2
Rectangle
C = length
C = π d
C = π(6.2)
C = 19.5
Now the area
A = lw
A = 19.5(12)
A = 234
Now add:
30.2 + 30.2 + 234 =
SA = 294.4 in²
There is also a formula to find surface area of a cylinder.
Some people find this way easier:
SA = 2πrh + 2πr²
SA = 2π(3.1)(12) + 2π(3.1)²
SA = 2π (37.2) + 2π(9.61)
SA = π(74.4) + π(19.2)
SA = 233.7 + 60.4
SA = 294.1 in²
The answers are REALLY close, but not exactly the same. That’s because we rounded in the problem.
Find the radius and height of the cylinder.
Then “Plug and Chug”…
Just plug in the numbers then do the math.
Remember the order of operations and you’re ready to go.
The formula tells you what to do!!!!
2πrh + 2πr² means multiply 2(π)(r)(h) + 2(π)(r)(r)
Volume of Prisms or Cylinders
You already know how to find the volume of a rectangular prism: V = lwh
The new formulas you need are:
Triangular Prism V = (½ bh)(H)
h = the height of the triangle and
H = the height of the cylinder
Cylinder V = (πr²)(H)
Volume of a Triangular Prism
We used this drawing for our surface area example. Now we will find the volume.
V = (½ bh)(H)
V = ½(6)(6)(9)
V = 162 mm³
This is a right triangle, so the sides are also the base and height.
Height of the prism
Try one:
Can you see the triangular bases?
V = (½ bh)(H)
V = (½)(12)(8)(18)
V = 864 cm³
Notice the prism is on its side. 18 cm is the HEIGHT of the prism. Picture if you turned it upward and you can see why it’s called “height”.
V = (πr²)(H)
V = (π)(3.1²)(12)
V = (π)(3.1)(3.1)(12)
V = 396.3 in³
Volume of a Cylinder
We used this drawing for our surface area example. Now we will find the volume.
optional step!
Try one:
10 m
d = 8 m
V = (πr²)(H)
V = (π)(4²)(10)
V = (π)(16)(10)
V = 502.7 m³Since d = 8,
then r = 4
r² = 4² = 4(4) = 16
Here are the formulas you will need to know:
A = lw SA = 2πrh + 2πr²
A = ½ bh V = (½ bh)(H)
A = π r² V = (πr²)(H)
C = πd
and how to find the surface area of a prism by adding up the areas of all the surfaces