gate chemical engineering 1994 2

8/20/2019 GATE Chemical Engineering 1994 2

1/8

w w

w . e x a

m r a c e

. c o m

IGATE - 199.1

I Ol M

l,:==:=

CHEMIC L NGIN RING

====::::.l

BEcnON·A

ONE M RKS QUESTIONS 1·20)

Use tltr

fo

ll

owing val

ur

.s:

R

(uoive1

'S

a l

gas

constant

=

8.314 ,J/mole k : g {accel

erat

ion

du

e

to gniVily)

=

9.8

1

m

/s>.

z.

3,

5

The tn\'erse olamamx ts

a

b. [ :

c.

[l

;

a

l

;hJ

d.

"

fhe

hmlt or ffs) = x/sln

x

as

x->

o 1s

a. o

b.

c. 1

cl

lntegmling fac1or fM the d•ll'er

en

tini

equation

tly +l (x)y : Q(x) is

dx

a ' 'P[J Pd I


2/8

w w

w . e x a

m r a c e

. c o m

d r,.

II A e w \ ~ n i a n liquid \ft density. f

=

v h ~ < l > i il> flowiug witb \'clocity v in u

tube of l a m c ~ r

D. L.t Al

be tbo prcssul'i\·i y

d. Tioennal

di Tuslvil)

to momentum

d

:IT

usivi

y

13.

For

a JumltW

n

o11 of iluid in u cirl llbr

tube. b,

s tlJ

l

•. The ~ : n e r g ) cbnoge

of

a c m

uodotglllng

any

r e v ~ i b

p r o ~ e ~ $ fs

zero

b. h 15 nol possible lo transfer heal fro m a

lower temperMure lo higher

tcmpCI':IlW'c

0::.

11Je I U I ~ I

o:tl


3/8

w w

w . e x a

m r a c e

. c o m

d.

TI>c

integl'nl of I x is --'

t . T

he

Cheen· tlu:orem n:l;otcs

integrnls

IQ

surface inlegrnl

s.

E t f a

· is a

l a r

and

l

is •

v ~ c t o r th

en

\

nh

=

____

g The .tilforential equation d 0.

tLV"

With

th

e

o o d i t i o n ~ )'

(o)

~ a l) =

I is called • pmblcm.

h. Uo ubte

CQnbct

do11blo

absQtplion

proc.:ss is used for11te m a n u f a of

I, F

t on

orifice mc11.-r. lit

prcossure

teCO\'Cl)' I•

l h ~ n lhnl

t\lr a

vcnrurimc:tc.1r

J, / . gas bubble lll prto;sv re

11f tlt

-

~ s e d

du

·ough a solvent with a

sntuntion vapor pl'llSsurc 11f P,.. 1f lhc

Lme

of

pn

sSllge

of

th

e

bubbl

e

1$

long

nnrl

is insoluble

in

the so lvent,

the

mole. r : ~ c t i o n or solvent in Lite bubblo

will

be equal

to

------

Ti

oc hell or on111lllun or . compuuud

is defmed ns h

<

at of renction

leading to the lo m>alion of

th

e

C(ompound (rum

I. A S

llJl


4/8

w w

w . e x a

m r a c e

. c o m

23.

- /) cl

c,

. .

d::

j.

A me

dium

is o l w : a y ~ rcquirod for

hcot

to ba tr.uaferrod..

Forced conveelinn

is

relati\'cly

I ' ~

dfeclivc in i n c r e : . ~ i n g the rnte m : . <

lta.niJ\:r ifSchm\dt

numhc:r

is l ~ t g o t

I.

tr

th

e

rate

of U1e

trYevenible re3ction

A B 2C

is

kCACn, tlten Ute renctiott

is

11lwnysclcmenl:uy

m.

T\\O

m x d e n o t O ~ > ;

Q f

Ul1

CqWll

~ i z e ore

• vailnble for

produ

cing a specified

produtt, fonnotl

bj

o h o m Q g c n t o

le

co

n-'htevc

m : ~ .

m u r n product on rate, the

& ~ n • l l e r

reactor , bmold be pl

nce.l

in

•aic•

hellmo the larger fdlcJOr.

" ' F11r Ute sam e c o n e r ~ l n n the holding

litue

tcquire


5/8

w w

w . e x a

m r a c e

. c o m

h. For a sphen: of den•ity ;. wrd vo lume V

placed in a Ouid of

n:$.iS

tan

d 2B C

(A)rale

of

Naclion

of

A

shows

a

mruUmum wi

th

time

(11)

C"

a

shQW•

o

u ~ C i m u m wi

th time

(C' ) t)c shows n mux

rnmm

with timnti nuou• L' decn:a


6/8

w w

w . e x a

m r a c e

. c o m

27

28

.

(5)

Saturated steam at BO C rs Qowing

tluough a

~ t e • pi11e of 0.02bn iJISi.de

(Gameler

and O,OZ7m 011J;ide diameter.

The pipe is 1nsltlated omade wiU1 0,38m

Irick i n s u l n ~ o n The runbienl air oulside

lheillsvla1ion is a

27

oc, Calculate

a. Ihnat;>

f h ~ a t

loss

per

mvter

length

of

'tllbe.

b U e overal l

heat

transfer coefficie.nl

based

911

mside smfuce an:a

of

steel

pipe,

Additfomldo/a

Tiiemial cNtdnctivily of steel

=

W/(m.k)

Thermal conductiv1ty of insulation

=

0.064WI(m.k)

Convective lteat transfer o q e f f i ~ ~ e n l

iJJRide

the

;I

eel

p i p e

. l 6 7 f ; W

m

~

Convectiv" }.eat

b\Jl

tsfe· c.oeillcient

ou.sicle tl'1

eh

1sulatioti = l l \V /(m.

2

k)

(5j

The heat of eacti•m

at

30() k and al om>

a1mospltl:ng

vapour phnse reaction from etltyleue:

C

1

H

4

g +H,O g) J C,H,OH g)

The

valoe

of

for

t:he

. above reaction

at

1

aln1

and C is 5040

J.

Calculate t lte

conversion obtained i f an isot:heonal

reactor operating at J25•C

and

2 atm is

fed

with a mixture containing 30

rt1ole

%

ethylene and 50 mole· % 4 steam. Assume

tllllt cq_uilibtinru

is:

J'9llched at the exit of

tjte reactor

and

gases behave ideally_

An e:'Pa

Cnm·sec.tiowtl area = 5 l 'J

-1

m

2

Elevation above prunt 2= 3 m

T h e b ~ a t of

Pressure= 1.25 10 '

Pa

Is

Cross-sectional area=

15

,. 1

111

fluid

ve

locity= l 1rlis

Other Data


7/8

w w

w . e x a

m r a c e

. c o m

•·

.

; , .

34

3 5.

30.

nensity

of

flu

id = 1

000 c


8/8

w w

w . e x a

m r a c e

. c o m2

43.

Check \ihcther the •ystcm

i•

IU ble or not,

11.

The cnsi of a

blo•ver

in

1981) Rio.

2.(\(1()

(i) \Vhal il

the cost of the blower

in

1.998

w1ll1 thesa111e

cnll3city? Ote cost

iud"" fot•the blower

in

1980 and 1988

respectively 25(1 and

3110

(ii) Wlu l is the

I S dit'fuJ

gate chemical engineering 1994 2

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