functions quadratics polynomials skill builder

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CfE Higher Maths. Unit Assessment Skills Builder Layout and content of the Unit Assessment will be different. This is not meant to be a carbon copy of the Unit Assessment. This booklet is an opportunity to practice all of the essential skills required to pass the Unit Assessment. This booklet should be used to identify any areas for improvement before you sit the Unit assessment for the first time. Unit Assessment standard Sub-skills H4LD 76 Relationships and Calculus RC1.1 Applying algebraic skills to solve equations factorising a cubic polynomial expression with unitary x 3 coefficient solving cubic polynomial equations with unitary x 3 coefficient given the nature of the roots of an equation, use the discriminant to find an unknown RC#2.1 Interpreting a situation where mathematics can be used and identifying a valid strategy For candidates undertaking the Course, Assessment Standard 2.1 should be achieved on at least two occasions from across the Course. H4LC 76 Expressions and Functions EF1.3 Applying algebraic and trigonometric skills to functions identifying and sketching related algebraic functions identifying and sketching related trigonometric functions determining composite and inverse functions (knowledge and use of the terms domain and range is expected) EF#2.1 Interpreting a situation where mathematics can be used and identifying a valid strategy For candidates undertaking the Course, Assessment Standard 2.1 should be achieved on at least two occasions from across the Course. EF#2.2 Explaining a solution and, where appropriate, relating it to context For candidates undertaking the Course, Assessment Standard 2.2 should be achieved on at least two occasions from across the Course. Mathematics Higher Revision Materials Functions, Quadratics & Polynomials Skills Builder

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Page 1: Functions Quadratics Polynomials Skill Builder

CfE Higher Maths. Unit Assessment Skills Builder

Layout and content of the Unit Assessment will be different. This is not meant to be a carbon copy of the Unit Assessment. This

booklet is an opportunity to practice all of the essential skills required to pass the Unit Assessment.

This booklet should be used to identify any areas for improvement before you sit the Unit assessment for the first time.

Unit Assessment standard Sub-skills

H4LD 76

Relationships

and Calculus

RC1.1 Applying algebraic

skills to solve equations factorising a cubic polynomial expression with unitary x

3 coefficient

solving cubic polynomial equations with unitary x3 coefficient

given the nature of the roots of an equation, use the discriminant to find an unknown

RC#2.1 Interpreting a

situation where mathematics

can be used and identifying a

valid strategy

For candidates undertaking the Course, Assessment Standard 2.1 should be achieved on at least two

occasions from across the Course.

H4LC 76

Expressions

and Functions

EF1.3 Applying algebraic and

trigonometric skills to

functions

identifying and sketching related algebraic functions

identifying and sketching related trigonometric functions

determining composite and inverse functions (knowledge and use of the terms domain and

range is expected)

EF#2.1 Interpreting a

situation where mathematics

can be used and identifying a

valid strategy

For candidates undertaking the Course, Assessment Standard 2.1 should be achieved on at least two

occasions from across the Course.

EF#2.2 Explaining a solution

and, where appropriate,

relating it to context

For candidates undertaking the Course, Assessment Standard 2.2 should be achieved on at least two

occasions from across the Course.

Mathematics Higher

Revision Materials

Functions, Quadratics & Polynomials Skills Builder

Page 2: Functions Quadratics Polynomials Skill Builder

CfE Higher Maths. Unit Assessment Skills Builder

RC1.1 Applying algebraic skills to solve equations

RC#2.1 Interpreting a situation where mathematics can be used and identifying a valid strategy

Sub-skills

factorising a cubic polynomial expression with unitary x3 coefficient (extended to non-unitary)

solving cubic polynomial equations with unitary x3 coefficient (extended to non-unitary)

Q1 a) Show that (π‘₯ βˆ’ 1) is a factor of 𝑓(π‘₯) = 2π‘₯3 βˆ’ 5π‘₯2 βˆ’ 2π‘₯ + 5 and hence factorise 𝑓(π‘₯) fully.

b) Hence solve the equation 2π‘₯3 βˆ’ π‘₯2 βˆ’ 2π‘₯ + 3 = 4π‘₯2 βˆ’ 2

Q2 a) Show that (π‘₯ βˆ’ 3) is a factor of 𝑓(π‘₯) = 3π‘₯3 βˆ’ 17π‘₯2 + 29π‘₯ βˆ’ 15 and hence factorise 𝑓(π‘₯) fully.

b) Hence solve the equation 3π‘₯3 βˆ’ 15π‘₯2 + 29π‘₯ βˆ’ 14 = 2π‘₯2 + 1

Q3 a) Show that (π‘₯ βˆ’ 1) is a factor of 𝑓(π‘₯) = 2π‘₯3 βˆ’ 3π‘₯2 βˆ’ 5π‘₯ + 6 and hence factorise 𝑓(π‘₯) fully.

b) Hence solve the equation 2π‘₯3 βˆ’ 2π‘₯2 + 3π‘₯ + 13 = π‘₯2 + 8π‘₯ + 7

Q4 a) Show that (π‘₯ + 3) is a factor of 𝑓(π‘₯) = π‘₯3 + 4π‘₯2 βˆ’ 17π‘₯ βˆ’ 60 and hence factorise 𝑓(π‘₯) fully.

b) Hence solve the equation 2π‘₯3 + 4π‘₯2 βˆ’ 17π‘₯ βˆ’ 61 = π‘₯3 βˆ’ 1

Q5 a) Show that (π‘₯ βˆ’ 2) is a factor of 𝑓(π‘₯) = 2π‘₯3 βˆ’ 9π‘₯2 + 13π‘₯ βˆ’ 6 and hence factorise 𝑓(π‘₯) fully.

b) Hence solve the equation 2π‘₯3 βˆ’ 13π‘₯2 + 13π‘₯ βˆ’ 1 = 5 βˆ’ 4π‘₯2

Q6 a) Show that (π‘₯ + 3) is a factor of 𝑓(π‘₯) = 3π‘₯3 + 20π‘₯2 + 29π‘₯ βˆ’ 12 and hence factorise 𝑓(π‘₯) fully.

b) Hence solve the equation 3π‘₯3 + 22π‘₯2 + 29π‘₯ βˆ’ 19 = 2π‘₯2 βˆ’ 7

Q7 a) Show that (π‘₯ + 1) is a factor of 𝑓(π‘₯) = 2π‘₯3 βˆ’ 8π‘₯2 + 2π‘₯ + 12 and hence factorise 𝑓(π‘₯) fully.

b) Hence solve the equation 2π‘₯3 βˆ’ 11π‘₯2 + π‘₯ + 13 = 1 βˆ’ π‘₯ βˆ’ 3π‘₯2

Q8 a) Show that (π‘₯ + 3) is a factor of 𝑓(π‘₯) = 2π‘₯3 + π‘₯2 βˆ’ 12π‘₯ + 9 and hence factorise 𝑓(π‘₯) fully.

b) Hence solve the equation 2π‘₯3 + 6π‘₯2 βˆ’ 13π‘₯ + 9 = 5π‘₯2 βˆ’ π‘₯

Q9 a) Show that (π‘₯ βˆ’ 2) is a factor of 𝑓(π‘₯) = π‘₯3 βˆ’ 2π‘₯2 βˆ’ π‘₯ + 2 and hence factorise 𝑓(π‘₯) fully.

b) Hence solve the equation π‘₯3 βˆ’ 2π‘₯2 + 8π‘₯ + 1 = 9π‘₯ βˆ’ 1

Q10 a) Show that (π‘₯ βˆ’ 4) is a factor of 𝑓(π‘₯) = 3π‘₯3 βˆ’ 25π‘₯2 + 56π‘₯ βˆ’ 16 and hence factorise 𝑓(π‘₯) fully.

b) Hence solve the equation 3π‘₯3 + 5π‘₯2 + 27π‘₯ βˆ’ 15 = 30π‘₯2 βˆ’ 29π‘₯ + 1

Page 3: Functions Quadratics Polynomials Skill Builder

CfE Higher Maths. Unit Assessment Skills Builder

RC1.1 Applying algebraic skills to solve equations

Sub-skills

given the nature of the roots of an equation, use the discriminant to find an unknown

Q11 Each of the following functions has 2 real and distinct roots.

Calculate the range of values for π‘˜ so that the function will maintain 2 real and distinct roots.

a) 𝑓(π‘₯) = π‘˜π‘₯2 + 6π‘₯ + 8

b) 𝑓(π‘₯) = 3π‘₯2 + π‘˜π‘₯ + 12

c) 𝑓(π‘₯) = 4π‘₯2 βˆ’ 2π‘₯ + π‘˜

d) 𝑓(π‘₯) = π‘˜π‘₯2 + 7π‘₯ + 12

e) 𝑓(π‘₯) = βˆ’2π‘₯2 + π‘˜π‘₯ + 2

f) 𝑓(π‘₯) = βˆ’4π‘₯2 + π‘₯ + π‘˜

g) 𝑓(π‘₯) = π‘˜π‘₯2 βˆ’ 5π‘₯ + 6

h) 𝑓(π‘₯) = 3π‘₯2 + π‘˜π‘₯ + 8

i) 𝑓(π‘₯) = βˆ’π‘₯2 + π‘₯ + π‘˜

j) 𝑓(π‘₯) = π‘˜π‘₯2 βˆ’ 6π‘₯ + 8

Q12 For what values of 𝑝 does the equation π‘₯2 βˆ’ 2π‘₯ + 𝑝 = 0 have:

a) equal roots b) real and distinct roots c) non real roots

Q13 Find π‘š given that π‘₯2 + π‘šπ‘₯ + π‘₯ + 9 = 0 has equal roots.

Q14 Find the values of π‘Ž, 𝑏 π‘Žπ‘›π‘‘ 𝑐 if each of the equations have equal roots

a) π‘Žπ‘₯2 + 4π‘₯ + 2 = 0 b) 3π‘₯2 + 𝑏π‘₯ + 3 = 0 c) π‘₯2 + 6π‘₯ + 𝑐 = 0

Q15 For what value of 𝑑 does 𝑑π‘₯2 + 6π‘₯ + 𝑑 = 0 have equal roots?

Q16 Find the value of π‘ž if π‘₯2 + (π‘ž βˆ’ 3)π‘₯ + 1 = 0 has equal roots.

Q17 Find the range of values of π‘š for which 5π‘₯2 βˆ’ 3π‘šπ‘₯ + 5 = 0 has two real and distinct roots.

Q18 For what value of π‘˜ does the graph 𝑦 = π‘˜π‘₯2 βˆ’ 3π‘˜π‘₯ + 9 touch the π‘₯ axis.

Q19 Find the values for n which ensure that the following equations have equal roots:

a) π‘₯2+1

π‘₯= 𝑛 b)

(π‘₯βˆ’2)2

π‘₯2+2= 𝑛

Q20 find π‘˜ if (2π‘˜ βˆ’ 2)π‘₯2 + 24π‘₯ + π‘˜ = 0 has:

a) equal roots b) real and distinct roots

Page 4: Functions Quadratics Polynomials Skill Builder

CfE Higher Maths. Unit Assessment Skills Builder

EF1.3 Applying algebraic and trigonometric skills to functions.

Sub-skills

identifying and sketching related algebraic functions

Q21 The graph of 𝑦 = 𝑓(π‘₯) is shown opposite.

a) Sketch 𝑦 = 𝑓(π‘₯ βˆ’ 2)

b) Sketch 𝑦 = 𝑓(π‘₯) + 5

c) Sketch 𝑦 = 𝑓(π‘₯ βˆ’ 1) + 2

d) Sketch 𝑦 = 𝑓(βˆ’π‘₯)

e) Sketch 𝑦 = βˆ’2𝑓(π‘₯ βˆ’ 4)

Q22 The graph of 𝑦 = 𝑔(π‘₯) is shown opposite.

a) Sketch 𝑦 = 𝑔(π‘₯ + 3)

b) Sketch 𝑦 = 𝑔(π‘₯) βˆ’ 4

c) Sketch 𝑦 = 𝑔(π‘₯ βˆ’ 2) βˆ’ 1

d) Sketch 𝑦 = 𝑔(βˆ’π‘₯)

e) Sketch 𝑦 = 2𝑔(π‘₯ + 1)

Q23 The graph of 𝑦 = β„Ž(π‘₯) is shown opposite.

a) Sketch 𝑦 = β„Ž(π‘₯ βˆ’ 1)

b) Sketch 𝑦 = β„Ž(π‘₯) + 2

c) Sketch 𝑦 = β„Ž(π‘₯ + 1) + 4

d) Sketch 𝑦 = βˆ’β„Ž(π‘₯)

e) Sketch 𝑦 = 2β„Ž(π‘₯)

Q24 The graph of 𝑦 = π‘˜(π‘₯) is shown opposite.

a) Sketch 𝑦 = π‘˜(π‘₯ βˆ’ 3)

b) Sketch 𝑦 = π‘˜(π‘₯) βˆ’ 2

c) Sketch 𝑦 = π‘˜(π‘₯ βˆ’ 1) + 3

d) Sketch 𝑦 = βˆ’π‘˜(π‘₯)

e) Sketch 𝑦 = 4π‘˜(π‘₯ βˆ’ 3)

Page 5: Functions Quadratics Polynomials Skill Builder

CfE Higher Maths. Unit Assessment Skills Builder

EF1.3 Applying algebraic and trigonometric skills to functions.

Sub-skills

identifying and sketching related algebraic functions

Q25 For each of the following graphs identify the value of π‘Ž.

a) b) c) d)

e) f) g) h)

EF1.3 Applying algebraic and trigonometric skills to functions.

Sub-skills

determining composite and inverse functions (knowledge and use of the terms domain and range is expected)

Q26 Write down the equation of the inverse functions for the following.

a) 𝑓(π‘₯) = 2π‘₯ b) 𝑓(π‘₯) = 3π‘₯ c) 𝑓(π‘₯) = 4π‘₯ d) 𝑓(π‘₯) = 7π‘₯

e) 𝑓(π‘₯) = π‘Žπ‘₯ f) 𝑓(π‘₯) = 10π‘₯ g) 𝑓(π‘₯) = 𝑒π‘₯ h) 𝑓(π‘₯) = 5π‘₯

i) 𝑓(π‘₯) = (1

2)

π‘₯ j) 𝑓(π‘₯) = 9π‘₯ k) 𝑓(π‘₯) = (2

3)

π‘₯ l) 𝑓(π‘₯) = (1

5)

π‘₯

Page 6: Functions Quadratics Polynomials Skill Builder

CfE Higher Maths. Unit Assessment Skills Builder

EF1.3 Applying algebraic and trigonometric skills to functions

Sub-skills

determining composite and inverse functions

(knowledge and use of the terms domain and range is expected)

Q27 Determine the inverse function for each of the following, assuming an appropriate domain and range.

a) 𝑓(π‘₯) = 5π‘₯ βˆ’ 2 b) 𝑓(π‘₯) = 3 βˆ’ 4π‘₯ c) 𝑓(π‘₯) = 2π‘₯ + 7

d) 𝑓(π‘₯) =π‘₯βˆ’2

4 e) 𝑓(π‘₯) =

3

2βˆ’ 5π‘₯ f) 𝑓(π‘₯) = 2(3π‘₯ βˆ’ 1)

g) 𝑓(π‘₯) = 5π‘₯2 h) 𝑓(π‘₯) = 3(π‘₯ βˆ’ 2)2 i) 𝑓(π‘₯) = 2(3π‘₯ + 1)2

EF1.3 Applying algebraic and trigonometric skills to functions

EF#2.2 Explaining a solution and, where appropriate, relating it to context

Sub-skills

determining composite and inverse functions

(knowledge and use of the terms domain and range is expected)

Q28 In each of the examples below, functions 𝑓 and 𝑔 are defined on suitable domains.

For each question, obtain expressions for 𝑓(𝑔(π‘₯)) π‘Žπ‘›π‘‘ 𝑔(𝑓(π‘₯)) in their simplest form.

a) 𝑓(π‘₯) = π‘₯ βˆ’ 2 𝑔(π‘₯) = π‘₯2

b) 𝑓(π‘₯) = 2π‘₯ + 1 𝑔(π‘₯) = π‘₯2 βˆ’ 2π‘₯ + 1

c) 𝑓(π‘₯) = 5π‘₯ βˆ’ 3 𝑔(π‘₯) =π‘₯+3

5 , explain the relationship between 𝑓(π‘₯)π‘Žπ‘›π‘‘ 𝑔(π‘₯).

d) 𝑓(π‘₯) = 4 βˆ’ 3π‘₯ 𝑔(π‘₯) =4βˆ’π‘₯

3 , explain the relationship between 𝑓(π‘₯)π‘Žπ‘›π‘‘ 𝑔(π‘₯).

e) 𝑓(π‘₯) = π‘₯2 + 1 𝑔(π‘₯) = (π‘₯ + 1)2

f) 𝑓(π‘₯) =2

3π‘₯ βˆ’ 4 𝑔(π‘₯) =

3

2π‘₯ + 6 , explain the relationship between 𝑓(π‘₯)π‘Žπ‘›π‘‘ 𝑔(π‘₯).

g) 𝑓(π‘₯) = 3 βˆ’ 2π‘₯2 𝑔(π‘₯) = π‘₯ βˆ’ 1

h) 𝑓(π‘₯) = 3π‘₯ + 5 𝑔(π‘₯) =2

π‘₯+1

i) 𝑓(π‘₯) =π‘₯βˆ’2

π‘₯+1 𝑔(π‘₯) =

1

π‘₯βˆ’2

j) 𝑓(π‘₯) = √π‘₯ + 4 𝑔(π‘₯) = π‘₯2 βˆ’ 4 , explain the relationship between 𝑓(π‘₯)π‘Žπ‘›π‘‘ 𝑔(π‘₯).

Page 7: Functions Quadratics Polynomials Skill Builder

CfE Higher Maths. Unit Assessment Skills Builder

EF1.3 Applying algebraic and trigonometric skills to functions

Sub-skills

identifying and sketching related trigonometric functions

Q29 Sketch each of the following trigonometric functions, where 0 ≀ π‘₯ ≀ 2πœ‹

a) 𝑦 = sin π‘₯ b) 𝑦 = cos π‘₯

c) 𝑦 = 2 sin π‘₯ d) 𝑦 = 3cos π‘₯

e) 𝑦 = sin π‘₯ + 3 f) 𝑦 = cos π‘₯ βˆ’ 4

g) 𝑦 = sin 2π‘₯ h) 𝑦 = cos (1

2π‘₯)

i) 𝑦 = βˆ’ sin π‘₯ j) 𝑦 = βˆ’ cos π‘₯

k) 𝑦 = 2 sin 3π‘₯ βˆ’ 1 l) 𝑦 = 2 βˆ’ cos 3π‘₯

EF1.3 Applying algebraic and trigonometric skills to functions

EF#2.1 Interpreting a situation where mathematics can be used and identifying a valid strategy

Sub-skills

identifying and sketching related trigonometric functions

Q30 Use the information provided in the table below to identify the equation of the curves.

All equations are of the form 𝑦 = π‘Ž sin 𝑏π‘₯ + 𝑐 π‘œπ‘Ÿ 𝑦 = π‘Ž cos 𝑏π‘₯ + 𝑐.

Type of curve Domain Maximum occurs at Minimum occurs at

a) sine 0 ≀ π‘₯ ≀ πœ‹ ( πœ‹

4, 1 ) (

3πœ‹

4, βˆ’1 )

b) cosine 0 ≀ π‘₯ β‰€πœ‹

2 ( 0, 1 ) (

πœ‹

2, 1 ) (

πœ‹

4, βˆ’1 )

c) sine 0 ≀ π‘₯ ≀ 2πœ‹ ( πœ‹

2, 3 ) (

3πœ‹

2, 1 )

d) cosine 0 ≀ π‘₯ ≀ πœ‹ ( 0, 3 ) ( πœ‹, 3 ) ( πœ‹

2, βˆ’3 )

e) sine 0 ≀ π‘₯ ≀ 2πœ‹ ( 3πœ‹

2, 5 ) (

πœ‹

2, 3 )

f) cosine 0 ≀ π‘₯ ≀ 2πœ‹ ( πœ‹, βˆ’1 ) ( 0, βˆ’3 ) ( 2πœ‹, βˆ’3 )

g) sine 0 ≀ π‘₯ ≀ πœ‹ ( πœ‹

4, 5 ) (

3πœ‹

4, 1 )

h) cosine 0 ≀ π‘₯ ≀ πœ‹ ( 0, 2) ( πœ‹, 2 ) ( πœ‹

2, βˆ’4 )

i) sine 0 ≀ π‘₯ ≀2πœ‹

3 (

πœ‹

6, 4 ) (

πœ‹

2, βˆ’2 )

j) cosine 0 ≀ π‘₯ β‰€πœ‹

2 (

πœ‹

4, 1 ) ( 0, βˆ’3 ) (

πœ‹

2, βˆ’3 )

Q31 Use your answers from Q30 to sketch the graphs of the trigonometric functions.

Page 8: Functions Quadratics Polynomials Skill Builder

CfE Higher Maths. Unit Assessment Skills Builder

ANSWERS

Q1 a) 𝑓(π‘₯) = (π‘₯ + 1)(π‘₯ βˆ’ 1)(2π‘₯ βˆ’ 5) b) π‘₯ = βˆ’1, 1, 5

2

Q2 a) 𝑓(π‘₯) = (π‘₯ βˆ’ 3)(π‘₯ βˆ’ 1)(3π‘₯ βˆ’ 5) b) π‘₯ = 3, 1, 5

3

Q3 a) 𝑓(π‘₯) = (π‘₯ βˆ’ 1)(π‘₯ βˆ’ 2)(2π‘₯ + 3) b) π‘₯ = 1, 2, βˆ’3

2

Q4 a) 𝑓(π‘₯) = (π‘₯ + 3)(π‘₯ + 5)(π‘₯ βˆ’ 4) b) π‘₯ = βˆ’3, βˆ’ 5, 4

Q5 a) 𝑓(π‘₯) = (π‘₯ βˆ’ 2)(π‘₯ βˆ’ 1)(2π‘₯ βˆ’ 3) b) π‘₯ = 2, 1, 3

2

Q6 a) 𝑓(π‘₯) = (π‘₯ + 3)(π‘₯ + 4)(3π‘₯ βˆ’ 1) b) π‘₯ = βˆ’3, βˆ’ 4, 1

3

Q7 a) 𝑓(π‘₯) = 2(π‘₯ + 1)(π‘₯ βˆ’ 3)(π‘₯ βˆ’ 2) b) π‘₯ = βˆ’1, 3, 2

Q8 a) 𝑓(π‘₯) = (π‘₯ + 3)(π‘₯ βˆ’ 1)(2π‘₯ βˆ’ 3) b) π‘₯ = βˆ’3, 1, 3

2

Q9 a) 𝑓(π‘₯) = (π‘₯ βˆ’ 2)(π‘₯ βˆ’ 1)(π‘₯ + 1) b) π‘₯ = βˆ’1, 1, 2

Q10 a) 𝑓(π‘₯) = (π‘₯ βˆ’ 4)(π‘₯ βˆ’ 4)(3π‘₯ βˆ’ 1) b) π‘₯ = 4, 1

3

Q11 a) π‘˜ <9

8 b) π‘˜ > 12, π‘˜ < βˆ’12

c) π‘˜ <1

4 d) π‘˜ <

49

48

e) 𝐴𝑙𝑙 π‘£π‘Žπ‘™π‘’π‘’π‘  π‘œπ‘“ π‘˜ f) π‘˜ > βˆ’1

16

g) π‘˜ <25

24 h) π‘˜ > 4√6 , π‘˜ < βˆ’4√6

i) π‘˜ > βˆ’1

4 j) π‘˜ <

9

8

Q12 a) 𝑝 = 1 b) 𝑝 ≀ 1 c) 𝑝 > 1

Q13 π‘š = 5 , βˆ’7

Q14 a) π‘Ž = 2 b) 𝑏 = Β±6 c) 𝑐 = 9

Q15 𝑑 = Β±3

Q16 π‘ž = 1 , 5

Q17 π‘š β‰₯10

3 , π‘š ≀ βˆ’

10

3

Q18 π‘˜ = 4, π‘˜ β‰  0 π‘Žπ‘  π‘‘β„Žπ‘’π‘› 𝑦 = 9. π‘‡β„Žπ‘–π‘  𝑙𝑖𝑛𝑒 π‘π‘Žπ‘›π‘›π‘œπ‘‘ π‘‘π‘œπ‘’π‘β„Ž π‘‘β„Žπ‘’ π‘₯ π‘Žπ‘₯𝑖𝑠

Q19 a) 𝑛 = Β±2 b) 𝑛 = 0 , 3

Q20 a) π‘˜ = 9, βˆ’8 b) π‘˜ < βˆ’8 , π‘˜ > 9

Page 9: Functions Quadratics Polynomials Skill Builder

CfE Higher Maths. Unit Assessment Skills Builder

Q21 Q22

Page 10: Functions Quadratics Polynomials Skill Builder

CfE Higher Maths. Unit Assessment Skills Builder

Q23 Q24

Page 11: Functions Quadratics Polynomials Skill Builder

CfE Higher Maths. Unit Assessment Skills Builder

Q25 a) π‘Ž = 3 b) π‘Ž = 2

c) π‘Ž = 7 d) π‘˜π‘Ž = 3

e) π‘Ž = 4 f) π‘Ž = 2

g) π‘Ž =1

2 h) π‘Ž =

1

3

Q26 a) π’š = log2 π‘₯ b) π’š = log3 π‘₯

c) π’š = log4 π‘₯ d) π’š = log7 π‘₯

e) π’š = logπ‘Ž π‘₯ f) π’š = log10 π‘₯

g) π’š = log𝑒 π‘₯ π‘œπ‘Ÿ ln π‘₯ h) π’š = log5 π‘₯

i) π’š = log12

π‘₯ j) π’š = log9 π‘₯

k) π’š = log23

π‘₯ l) π’š = log15

π‘₯

Q27 a) π‘“βˆ’1(π‘₯) =π‘₯+2

5 b) π‘“βˆ’1(π‘₯) =

3βˆ’π‘₯

4 c) π‘“βˆ’1(π‘₯) =

π‘₯βˆ’7

2

d) π‘“βˆ’1(π‘₯) = 4π‘₯ + 2 e) π‘“βˆ’1(π‘₯) =3βˆ’2π‘₯

10 f) π‘“βˆ’1(π‘₯) =

π‘₯+2

6

g) π‘“βˆ’1(π‘₯) = √π‘₯

5 h) π‘“βˆ’1(π‘₯) = √

π‘₯

3+ 2 i) π‘“βˆ’1(π‘₯) =

√2(√π‘₯βˆ’2)

6

Q28 a) 𝑓(𝑔(π‘₯)) = π‘₯2 βˆ’ 2 𝑔(𝑓(π‘₯)) = (π‘₯ βˆ’ 2)2

b) 𝑓(𝑔(π‘₯)) = 2π‘₯2 βˆ’ 4π‘₯ + 3 𝑔(𝑓(π‘₯)) = 4π‘₯2

c) 𝑓(𝑔(π‘₯)) = π‘₯ 𝑔(𝑓(π‘₯)) = π‘₯

𝑓(π‘₯) = π‘”βˆ’1(π‘₯) π‘Žπ‘›π‘‘ π‘“βˆ’1(π‘₯) = 𝑔(π‘₯) (π‘–π‘›π‘£π‘’π‘Ÿπ‘ π‘’ π‘œπ‘“ π‘’π‘Žπ‘β„Ž π‘œπ‘‘β„Žπ‘’π‘Ÿ)

d) 𝑓(𝑔(π‘₯)) = π‘₯ 𝑔(𝑓(π‘₯)) = π‘₯

𝑓(π‘₯) = π‘”βˆ’1(π‘₯) π‘Žπ‘›π‘‘ π‘“βˆ’1(π‘₯) = 𝑔(π‘₯) (π‘–π‘›π‘£π‘’π‘Ÿπ‘ π‘’ π‘œπ‘“ π‘’π‘Žπ‘β„Ž π‘œπ‘‘β„Žπ‘’π‘Ÿ)

e) 𝑓(𝑔(π‘₯)) = (π‘₯ + 1)4 + 1 𝑔(𝑓(π‘₯)) = (π‘₯2 + 2)2

f) 𝑓(𝑔(π‘₯)) = π‘₯ 𝑔(𝑓(π‘₯)) = π‘₯

𝑓(π‘₯) = π‘”βˆ’1(π‘₯) π‘Žπ‘›π‘‘ π‘“βˆ’1(π‘₯) = 𝑔(π‘₯) (π‘–π‘›π‘£π‘’π‘Ÿπ‘ π‘’ π‘œπ‘“ π‘’π‘Žπ‘β„Ž π‘œπ‘‘β„Žπ‘’π‘Ÿ)

g) 𝑓(𝑔(π‘₯)) = 1 + 4π‘₯ βˆ’ 2π‘₯2 𝑔(𝑓(π‘₯)) = 2(1 + π‘₯)(1 βˆ’ π‘₯)

h) 𝑓(𝑔(π‘₯)) =6

π‘₯+1+ 5 𝑔(𝑓(π‘₯)) =

2

3(π‘₯+2)

i) 𝑓(𝑔(π‘₯)) =5βˆ’2π‘₯

π‘₯βˆ’1 𝑔(𝑓(π‘₯)) = βˆ’

(π‘₯+1)

(π‘₯+4)

j) 𝑓(𝑔(π‘₯)) = π‘₯ 𝑔(𝑓(π‘₯)) = π‘₯

𝑓(π‘₯) = π‘”βˆ’1(π‘₯) π‘Žπ‘›π‘‘ π‘“βˆ’1(π‘₯) = 𝑔(π‘₯) (π‘–π‘›π‘£π‘’π‘Ÿπ‘ π‘’ π‘œπ‘“ π‘’π‘Žπ‘β„Ž π‘œπ‘‘β„Žπ‘’π‘Ÿ)

Page 12: Functions Quadratics Polynomials Skill Builder

CfE Higher Maths. Unit Assessment Skills Builder

Q29

Page 13: Functions Quadratics Polynomials Skill Builder

CfE Higher Maths. Unit Assessment Skills Builder

Q30 a) 𝑦 = 𝑠𝑖𝑛 2π‘₯ b) 𝑦 = cos 4π‘₯

c) 𝑦 = 𝑠𝑖𝑛 π‘₯ + 2 d) 𝑦 = 3 cos 2π‘₯

e) 𝑦 = βˆ’π‘ π‘–π‘› π‘₯ + 4 f) 𝑦 = βˆ’cos π‘₯ βˆ’ 2

g) 𝑦 = 2𝑠𝑖𝑛 2π‘₯ + 3 h) 𝑦 = 3 cos 2π‘₯ βˆ’ 1

i) 𝑦 = 3𝑠𝑖𝑛 3π‘₯ + 1 j) 𝑦 = βˆ’2cos 4π‘₯ βˆ’ 1

Q31