fractions grade 4 · 2016. 3. 1. · grade 4 fractions for more such worksheets visit answer the...
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Grade 4Fractions
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Answer the questions
(1) Shade the picture to show f ollowing f ractions:A)
6
7
B) 4
7
C)
6
10
D)
9
12
(2) What f raction is represented by shaded portion of these shapes :A)
B)
C)
D)
E)
F)
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(3) The f ollowing f igure shows f ruits in a basket at Benjie's house. What f raction of f ruits areapples?
(4) Shade the images to show the f ollowing f raction addition .
4
9
+ 1
9
+ 1
9
=
and and makes
Choose correct answer(s) from given choice
(5)Fermin has planted many f ruits in his f arm. He planted
2
14 of a f arm with bananas,
2
14 with
pears and 5
14 with apples. How much of the Fermin 's f arm is planted with f ruits ?
a. 7
14 b.
9
14
c. 14
9
(6) Which mixed f raction is shown by the f igure given below ?
a. 37
8 b. 4
7
8
c. 38
7 d. 3
1
8
Fill in the blanks
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(7) Write the f ollowing f ractions in the simplest f orm:A)
24
80 = .
B)
9
18 = .
C)
7
98 = .
D)
35
133 = .
E)
27
45 = .
F)
8
16 = .
(8) Subtract the f ollowing f ractions and reduce them to the simplest f orm:A)
46
45 -
2
9 =
B) 50
7 -
7
1 =
C) 21
30 -
1
5 =
D) 27
6 -
6
3 =
E) 26
3 -
8
3 =
F) 9
4 -
2
4 =
(9) Fill in the blank with < , > , or = sign:A)
10
4
16
4
B)
7
19
5
19
C)
8
17
6
17
D) 20
17
7
17
E) 3
2
16
2
F) 16
14
6
14
(10) In like f ractions, the numerator, the smaller the number will be.
(11)
3
19 +
1
19 +
3
19 =
(12) Fractions with same denominators are called f ractions.
(13) A f raction in which numerator is smaller than the denominator is called f raction.
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(15)Iska ate
2
7 of pizza in the dinner. If she had
5
7 of pizza, the part of the pizza that is lef t
with her is .
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Answers
(1) A)
Step 1
If you look at the picture caref ully, you will notice that the picture is divided into 7equal parts.
Step 2
Now to show the f raction 6
7 , we have to shade any 6 parts of the picture out
of the 7 parts.
Step 3
Theref ore the shaded picture is like as:
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B)
Step 1
If you look at the picture caref ully, you will notice that the picture is divided into 7equal parts.
Step 2
Now to show the f raction 4
7 , we have to shade any 4 parts of the picture out
of the 7 parts.
Step 3
Theref ore the shaded picture is like as:
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C)
Step 1
If you look at the picture caref ully, you will notice that the picture is divided into10 equal parts.
Step 2
Now to show the f raction 6
10 , we have to shade any 6 parts of the picture out
of the 10 parts.
Step 3
Theref ore the shaded picture is like as:
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D)
Step 1
If you look at the picture caref ully, you will notice that the picture is divided into12 equal parts.
Step 2
Now to show the f raction 9
12 , we have to shade any 9 parts of the picture out
of the 12 parts.
Step 3
Theref ore the shaded picture is like as:
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(2) A)
6
7
Step 1
We have been asked to f ind the f raction that represents the shaded portion ofthe f ollowing shape:
Step 2
Total number of equal parts in the image = 7Number of parts that are shaded in the image = 6
Step 3
Fraction of parts of the image that are shaded = Number of shaded parts
Total number of parts
= 6
7
Step 4
Hence, the f raction that is represented by the shaded portion of the shape is 6
7
.
ID : ph-4-Fractions [9]
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B)
9
10
Step 1
We have been asked to f ind the f raction that represents the shaded portion ofthe f ollowing shape:
Step 2
Total number of equal parts in the image = 10Number of parts that are shaded in the image = 9
Step 3
Fraction of parts of the image that are shaded = Number of shaded parts
Total number of parts
= 9
10
Step 4
Hence, the f raction that is represented by the shaded portion of the shape is 9
10 .
ID : ph-4-Fractions [10]
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C)
9
14
Step 1
We have been asked to f ind the f raction that represents the shaded portion ofthe f ollowing shape:
Step 2
Total number of equal parts in the image = 14Number of parts that are shaded in the image = 9
Step 3
Fraction of parts of the image that are shaded = Number of shaded parts
Total number of parts
= 9
14
Step 4
Hence, the f raction that is represented by the shaded portion of the shape is 9
14 .
ID : ph-4-Fractions [11]
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D)
4
5
Step 1
We have been asked to f ind the f raction that represents the shaded portion ofthe f ollowing shape:
Step 2
Total number of equal parts in the image = 5Number of parts that are shaded in the image = 4
Step 3
Fraction of parts of the image that are shaded = Number of shaded parts
Total number of parts
= 4
5
Step 4
Hence, the f raction that is represented by the shaded portion of the shape is 4
5
.
ID : ph-4-Fractions [12]
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E)
9
13
Step 1
We have been asked to f ind the f raction that represents the shaded portion ofthe f ollowing shape:
Step 2
Total number of equal parts in the image = 13Number of parts that are shaded in the image = 9
Step 3
Fraction of parts of the image that are shaded = Number of shaded parts
Total number of parts
= 9
13
Step 4
Hence, the f raction that is represented by the shaded portion of the shape is 9
13 .
ID : ph-4-Fractions [13]
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F)
7
10
Step 1
We have been asked to f ind the f raction that represents the shaded portion ofthe f ollowing shape:
Step 2
Total number of equal parts in the image = 10Number of parts that are shaded in the image = 7
Step 3
Fraction of parts of the image that are shaded = Number of shaded parts
Total number of parts
= 7
10
Step 4
Hence, the f raction that is represented by the shaded portion of the shape is 7
10 .
(3)
4
12
Step 1
Lets count all f ruits in this box. There are total 12 f ruits, out of which 4 are apples
Step 2
Theref ore f raction of apples,= (Number of apples) / (Total number of f ruits)
= 4
12
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(4) 4
9
+ 1
9
+ 1
9
=
and and makes
(5)b.
9
14
(6)a. 3
7
8
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(7) A)
24
80 =
3
10
.
Step 1
A f raction is said to be in the simplest/lowest f orm if its numerator and thedenominator have no common f actor higher than 1. In other words, we can saythat a f raction is said to be in the simplest/lowest f orm if the HCF of itsnumerator and denominator is equal to 1.
Step 2
If f or any f raction, both the numerator and the denominator are divided by theirHCF, the HCF of the new numerator and denominator will be 1. This means thatthe new f raction will be in its simplest/lowest f orm.
Step 3
In order to write the f raction 24
80 in the simplest/lowest f orm, let us f ind the
HCF of 24 and 80:
2 | 24
2 | 12
2 | 6
3 | 3
| 1
Factors of 24 = 2 × 2 × 2 × 3
2 | 80
2 | 40
2 | 20
2 | 10
5 | 5
| 1
Factors of 80 = 2 × 2 × 2 × 2 × 5
The HCF of 24 and 80 is 2 × 2 × 2 = 8.
Step 4
Now, let us divide both the numerator and denominator of the f raction 24
80 by
its HCF 8 in order to bring it into its simplest/lowest f orm:
24
80 =
24 ÷ 8
80 ÷ 8 =
3
10
Step 5
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Hence, the simplest/lowest f orm of 24
80 is
3
10 .
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B)
9
18 =
1
2
.
Step 1
A f raction is said to be in the simplest/lowest f orm if its numerator and thedenominator have no common f actor higher than 1. In other words, we can saythat a f raction is said to be in the simplest/lowest f orm if the HCF of itsnumerator and denominator is equal to 1.
Step 2
If f or any f raction, both the numerator and the denominator are divided by theirHCF, the HCF of the new numerator and denominator will be 1. This means thatthe new f raction will be in its simplest/lowest f orm.
Step 3
In order to write the f raction 9
18 in the simplest/lowest f orm, let us f ind the
HCF of 9 and 18:
3 | 9
3 | 3
| 1
Factors of 9 = 3 × 3
2 | 18
3 | 9
3 | 3
| 1
Factors of 18 = 2 × 3 × 3
The HCF of 9 and 18 is 3 × 3 = 9 .
Step 4
Now, let us divide both the numerator and denominator of the f raction 9
18 by
its HCF 9 in order to bring it into its simplest/lowest f orm:
9
18 =
9 ÷ 9
18 ÷ 9 =
1
2
Step 5
Hence, the simplest/lowest f orm of 9
18 is
1
2 .
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C)
7
98 =
1
14
.
Step 1
A f raction is said to be in the simplest/lowest f orm if its numerator and thedenominator have no common f actor higher than 1. In other words, we can saythat a f raction is said to be in the simplest/lowest f orm if the HCF of itsnumerator and denominator is equal to 1.
Step 2
If f or any f raction, both the numerator and the denominator are divided by theirHCF, the HCF of the new numerator and denominator will be 1. This means thatthe new f raction will be in its simplest/lowest f orm.
Step 3
In order to write the f raction 7
98 in the simplest/lowest f orm, let us f ind the
HCF of 7 and 98:
7 | 7
| 1
Factors of 7 = 7
2 | 98
7 | 49
7 | 7
| 1
Factors of 98 = 2 × 7 × 7
The HCF of 7 and 98 is 7.
Step 4
Now, let us divide both the numerator and denominator of the f raction 7
98 by
its HCF 7 in order to bring it into its simplest/lowest f orm:
7
98 =
7 ÷ 7
98 ÷ 7 =
1
14
Step 5
Hence, the simplest/lowest f orm of 7
98 is
1
14 .
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D)
35
133 =
5
19
.
Step 1
A f raction is said to be in the simplest/lowest f orm if its numerator and thedenominator have no common f actor higher than 1. In other words, we can saythat a f raction is said to be in the simplest/lowest f orm if the HCF of itsnumerator and denominator is equal to 1.
Step 2
If f or any f raction, both the numerator and the denominator are divided by theirHCF, the HCF of the new numerator and denominator will be 1. This means thatthe new f raction will be in its simplest/lowest f orm.
Step 3
In order to write the f raction 35
133 in the simplest/lowest f orm, let us f ind the
HCF of 35 and 133:
5 | 35
7 | 7
| 1
Factors of 35 = 5 × 7
7 | 133
19 | 19
| 1
Factors of 133 = 7 × 19
The HCF of 35 and 133 is 7.
Step 4
Now, let us divide both the numerator and denominator of the f raction 35
133 by
its HCF 7 in order to bring it into its simplest/lowest f orm:
35
133 =
35 ÷ 7
133 ÷ 7 =
5
19
Step 5
Hence, the simplest/lowest f orm of 35
133 is
5
19 .
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E)
27
45 =
3
5
.
Step 1
A f raction is said to be in the simplest/lowest f orm if its numerator and thedenominator have no common f actor higher than 1. In other words, we can saythat a f raction is said to be in the simplest/lowest f orm if the HCF of itsnumerator and denominator is equal to 1.
Step 2
If f or any f raction, both the numerator and the denominator are divided by theirHCF, the HCF of the new numerator and denominator will be 1. This means thatthe new f raction will be in its simplest/lowest f orm.
Step 3
In order to write the f raction 27
45 in the simplest/lowest f orm, let us f ind the
HCF of 27 and 45:
3 | 27
3 | 9
3 | 3
| 1
Factors of 27 = 3 × 3 × 3
3 | 45
3 | 15
5 | 5
| 1
Factors of 45 = 3 × 3 × 5
The HCF of 27 and 45 is 3 × 3 = 9 .
Step 4
Now, let us divide both the numerator and denominator of the f raction 27
45 by
its HCF 9 in order to bring it into its simplest/lowest f orm:
27
45 =
27 ÷ 9
45 ÷ 9 =
3
5
Step 5
Hence, the simplest/lowest f orm of 27
45 is
3
5 .
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F)
8
16 =
1
2
.
Step 1
A f raction is said to be in the simplest/lowest f orm if its numerator and thedenominator have no common f actor higher than 1. In other words, we can saythat a f raction is said to be in the simplest/lowest f orm if the HCF of itsnumerator and denominator is equal to 1.
Step 2
If f or any f raction, both the numerator and the denominator are divided by theirHCF, the HCF of the new numerator and denominator will be 1. This means thatthe new f raction will be in its simplest/lowest f orm.
Step 3
In order to write the f raction 8
16 in the simplest/lowest f orm, let us f ind the
HCF of 8 and 16:
2 | 8
2 | 4
2 | 2
| 1
Factors of 8 = 2 × 2 × 2
2 | 16
2 | 8
2 | 4
2 | 2
| 1
Factors of 16 = 2 × 2 × 2 × 2
The HCF of 8 and 16 is 2 × 2 × 2 = 8.
Step 4
Now, let us divide both the numerator and denominator of the f raction 8
16 by
its HCF 8 in order to bring it into its simplest/lowest f orm:
8
16 =
8 ÷ 8
16 ÷ 8 =
1
2
Step 5
Hence, the simplest/lowest f orm of 8
16 is
1
2 .
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(8) A) 46
45 -
2
9 =
4
5
B) 50
7 -
7
1 =
1
7
C) 21
30 -
1
5 =
1
2
D) 27
6 -
6
3 =
5
2
E) 26
3 -
8
3 =
6
1
F) 9
4 -
2
4 =
7
4
(9) A) <
B) >
C) >
D) >
E) <
F) >
(10) smaller
(11) 7 19
(12) like
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(14) 6
Step 1
It is given that sum of f ractions is equal to 1. Theref ore nominator and denominator of thesum should be equal
Step 2
On addition of f raction we get,
19
+ 3
19 +
4
19 +
6
19 =
+ 3 + 4 + 6
19
Step 3
As we know that nominator and denominator of sum are equal, + 3 + 4 + 6 = 19
Step 4
Now it can be seen that above relation is satisf ied only when is equal to 6. Theref ore, = 6
(15)Iska ate
2
7 of pizza in the dinner. If she had
5
7 of pizza, the part of the pizza that is lef t
with her is 3
7 .
ID : ph-4-Fractions [24]
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Answer the questionsChoose correct answer(s) from given choiceFill in the blanksAnswers