four-side plane figures
TRANSCRIPT
-
7/29/2019 Four-Side Plane Figures
1/26
-
7/29/2019 Four-Side Plane Figures
2/26
-
7/29/2019 Four-Side Plane Figures
3/26
Properties of
RectangleB = A ; C = D = 90
AB # CD ; AD # BC
AC = BD
AO = BO = CO = DO
2 Axis of symmetry
-
7/29/2019 Four-Side Plane Figures
4/26
-
7/29/2019 Four-Side Plane Figures
5/26
B = A ; C = D = 90
AB # CD ; AD # BC
AC = BD
AO = BO = CO = DO4 Axis of symmetry
-
7/29/2019 Four-Side Plane Figures
6/26
-
7/29/2019 Four-Side Plane Figures
7/26
Rectangle
it has areaA = l.w
it has perimeter P= 2l+ 2w = 2(l+ w)
-
7/29/2019 Four-Side Plane Figures
8/26
Square
It has areaA = s.s
It has perimeter P= 4s
-
7/29/2019 Four-Side Plane Figures
9/26
-
7/29/2019 Four-Side Plane Figures
10/26
A Parallelogram can be formed by combining atriangle and its image which is rotated through half afull turn about midpoint of one of the triangles side
-
7/29/2019 Four-Side Plane Figures
11/26
Area of a Parallelogram The area of a parallelogram is b h, where b is the
length of the base of the parallelogram, and h is thecorresponding height. To picture this, consider theparallelogram below:
-
7/29/2019 Four-Side Plane Figures
12/26
Perimeter of a Parallelogram
The formula for finding the perimeter is Side A +Side B + Side A + Side B. This could also be statedas 2 x Side A + 2 x Side B or 2 x (Side A + Side B).
-
7/29/2019 Four-Side Plane Figures
13/26
-
7/29/2019 Four-Side Plane Figures
14/26
Every rhombus has two diagonals connecting oppositepairs of vertices and two pairs of parallel sides.Using congruent triangles, one can prove that the rhombusis symmetric across each of these diagonals. It follows thatany rhombus has the following properties:
Opposite angles of a rhombus have equal measure.
The two diagonals of a rhombus are perpendicular; that is,a rhombus is an orthodiagonal quadrilateral. Its diagonals bisect opposite angles.
-
7/29/2019 Four-Side Plane Figures
15/26
To find the perimeter of a rhombus, just addup all the lengths of the sides:
-
7/29/2019 Four-Side Plane Figures
16/26
To find the area of a rhombus, multiply thelengths of the two diagonals and divide by 2(same as multiplying by 1/2):
-
7/29/2019 Four-Side Plane Figures
17/26
-
7/29/2019 Four-Side Plane Figures
18/26
Kites
-
7/29/2019 Four-Side Plane Figures
19/26
Kites
A kite is formed by combining two isoscelestriangles whose bases are equal in length andcoincident
In every kite, there is a pair of opposite interiorangles which are equal in measure
In every kite, one of the diagonals is an axis ofsymmetry
In every kite, each of two diagonal bisects theother diagonal and is perpendicular to that otherdiagonal
-
7/29/2019 Four-Side Plane Figures
20/26
The perimeter of a kite
To find the perimeter of a kite, just add upall the lengths of the sides:
-
7/29/2019 Four-Side Plane Figures
21/26
The area of a kite
To find the area of a kite, multiply thelengths of the two diagonals and divide by2 (same as multiplying by 1/2):
-
7/29/2019 Four-Side Plane Figures
22/26
TRAPEZIUM
by : Bagaskara W H
-
7/29/2019 Four-Side Plane Figures
23/26
Trapezium is a four slided plane figurewhich has a pair of parallel lines
Type of Trapezium :
Arbitrary Trapezium : Trapezium eachhaving four sides not equal in length
Isosceles Trapezium : Trapezium
having one pair of opposite sides equal
in length Right Angled Trapezium : Trapezium
having right interior angles
-
7/29/2019 Four-Side Plane Figures
24/26
The Area of Trapezium : x (Sum ofthe parallel lines) x Altitude
The Perimeter of Trapezium : Sum of
all sides on the Trapezium
-
7/29/2019 Four-Side Plane Figures
25/26
Applying the geometry of the four
sided plane figure Example of problem :1. A square garden has sides measuring 9 m each.If the
perimeter of that garden is to be planted with fencing trees
with distance 1,5 m between every two trees,then how many
trees are required?Answer :
The perimeter of the garden : Perimeter of square
= 4x side length
= 4 x 9
= 36 m
The number of fencing trees reqiured = 36 : 1,5 = 24 trees
-
7/29/2019 Four-Side Plane Figures
26/26
2. The floor of a room measures 4m x 3m.If the floor of thatroom is to be covered with floor masuring 20 cm x 20 cm
each,then how many floors are required?
Answer :
The length of the room = 4m = 400 cmThe width of the room = 3m = 300 cm
Number of floor required to cover the length of the room = 400 :
20 = 20 floors
Number of floor required to cover the width of the room =
300 : 20 = 15 floors
Thus,the total number of floor required is : 20 x 15 : 300 floors