flexural analysis and design of beamns 2

8
Plain & Reinforced Concrete-1 CE-313 Flexural Analysis and Design of Beams

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Page 1: Flexural Analysis and Design of Beamns 2

Plain & Reinforced Concrete-1

CE-313

Flexural Analysis and Design of

Beams

Page 2: Flexural Analysis and Design of Beamns 2

Plain & Reinforced Concrete-1

Cracked Transformed SectionWhen tensile stress cross fr, crack appear on the tension face of beam.

Tensile strength of concrete is neglected. All the concrete on the tension side of N.A. is neglected.

Only the Shaded area of cross-section is considered effective.

N.A

Concrete

Steel

Page 3: Flexural Analysis and Design of Beamns 2

Plain & Reinforced Concrete-1

Cracked Transformed Section (contd…)

Cc

T = Asfs

la = jdN.A.

fcεc

fs

Strain Diagram

Stress Diagram

Internal Force Diagram

When the tension side is cracked the concrete becomes ineffective but the strains goes on increasing. The steel comes in to action to take the tension.

εs

Cracked Transformed

Section

hkd

dnAs

b

Page 4: Flexural Analysis and Design of Beamns 2

Plain & Reinforced Concrete-1

Cracked Transformed Section (contd…)

Calculations for“k”, taking top face as reference

kd = [b x kd x kd/2 + nAsd]/ [b x kd + nAs]

b x (kd)2 + nAs kd = b x (kd)2/2 + nAsd

b x (kd)2/2 = nAsd - nAs kd

b x (kd)2/2 = (1-k) nAsd

bd2 k2 /2 = (1-k) nρbd2

k2 = 2(1-k) nρ

k2 + 2nρ k - 2nρ = 0

Cracked Transformed

Section

kd

nAs

b

d

ρ = As / bd

Page 5: Flexural Analysis and Design of Beamns 2

Plain & Reinforced Concrete-1

Cracked Transformed Section (contd…)

k2 + 2nρ k - 2nρ = 0

k = [ -2nρ ± √ (4n2ρ2 + 8nρ) ] /2

k = [ -nρ ± √ (n2ρ2 + 2nρ) ]

k = √ (n2ρ2 + 2nρ) -nρTaking only positive value as distance can’t be negative

Cracked Transformed

Section

kd

nAs

b

d

Page 6: Flexural Analysis and Design of Beamns 2

Plain & Reinforced Concrete-1Cracked Transformed Section (contd…)

Value of “j”jd = d – kd/3

J = 1 – k/3Cc = volume of stress diagramCc = ½ kd x fc x b

Cc = fc/2 x kdb

T = Asfs = nfcAs

b

kd

fc

T = Asfs

Cc

jdN.A d

Page 7: Flexural Analysis and Design of Beamns 2

Plain & Reinforced Concrete-1Cracked Transformed Section (contd…)

Resisting Moment CapacityFor longitudinal equilibrium

T = Cc

Mr = T x jd = Cc x jd

Mr = Asfs x jd = fc/2 x kdb x jd ------------- 1 FOR MAXIMUM VALUE RESISTING MOMENTPut in eq-1fs = 0.5 fy for grade 300 steel

fs = 0.4 fy for grade 420 steel

fs = Maximum allowable tensile stress in steel

fc= 0.45 fc’

fc = Maximum allowable concrete stress

Page 8: Flexural Analysis and Design of Beamns 2

Concluded