final lab report for thermos 2(mech)

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Cape Peninsula University of Technology Bellville Campus Department of Mechanical Engineering THERMODYNAMICS LABORATORY THE DRYNESS FRACTION OF THE STEAM By L.Nyandu Subject: APT200S Lecturer: S Makhomo Evaluation Criteria Introduction: (Aim for each lab, Background, List of the apparatus, Procedure etc) 10% Result: (Calculations, Correct method, etc) 55% Explanations (did you explain what you are doing rather than put formulas.) 10% Discussion: (Discussion of the results, do they make sense? Any possible errors, etc) 10% Conclusion and Recommendations: (Did we achieve our aims? What do we need to do to improve our results) 5% Presentation, layout and neatness: (Cover page, Typed/ print neat, report format, etc) 10% Total 100% Date of submission: LAB 1: THE DRYNESS FRACTION OF THE STEAM The aim of this experiment is to determine the dryness fraction of wet steam.

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Page 1: Final lab report for thermos 2(mech)

Cape Peninsula University of TechnologyBellville Campus

Department of Mechanical Engineering

THERMODYNAMICS LABORATORY

THE DRYNESS FRACTION OF THE STEAM

By L.Nyandu

Subject: APT200SLecturer: S Makhomo

Evaluation Criteria

Introduction: (Aim for each lab, Background, List of the apparatus, Procedure etc)

10%

Result: (Calculations, Correct method, etc) 55%

Explanations (did you explain what you are doing rather than put formulas.)

10%

Discussion: (Discussion of the results, do they make sense? Any possible errors, etc)

10%

Conclusion and Recommendations: (Did we achieve our aims? What do we need to do to improve our results)

5%

Presentation, layout and neatness: (Cover page, Typed/ print neat, report format, etc)

10%

Total 100%

Date of submission:

LAB 1: THE DRYNESS FRACTION OF THE STEAM

The aim of this experiment is to determine the dryness fraction of wet steam.

Page 2: Final lab report for thermos 2(mech)

1. Apparatus• Steam boiler plant.

• Separating and throttling calorimeter.

• Measuring beaker

2. Theoretical background

According to Philip (1998) the separating calorimeter is a vessel used initially to separate some of the moisture from the steam, to ensure superheat conditions after throttling. The steam is made to change direction suddenly; the moisture droplets, being heavier than the vapor, drop out of suspension and are collected at the bottom of the vessel.The throttling calorimeter is a vessel with a needle valve fitted on the inlet side. The steam is throttled through the needle valve and exhausted to the condenser. Suppose M kg of wet steam with a dryness fraction of x enters the separating calorimeter. The vapor part will have a mass of x M kg and the liquid part will have a mass of M kg. In the separating calorimeter part of the liquid, say1 kg will be separated from the wet steam. Hence the dryness fraction of the wet steam will increase to x1 which will pass through the throttling process valve. After the throttling process the steam in the throttling calorimeter will be in superheated state.

3. Procedure1. Start the boiler and supply steam to the separating and throttling

calorimeter unit.

2. Start the cooling water flow through the condenser.

3. Open steam valve and allow the steam to flow through the calorimeters to warm through the steam.

4. Open the throttle valve and adjust to give a pressure at exhaust of about 5cm Hg measured on the manometer.

5. Drain the separating calorimeter.

6. Start the test and take readings at 2-3 minutes intervals.

7. When a reasonable quantity of condensate is collected measure the quantity of separated water and the quantity of condensate.

Page 3: Final lab report for thermos 2(mech)

Figure2. T-S diagram of the separating and throttling calorimeter.From the steady flow energy equation: Q – W = hC - hB

Since throttling takes place over a very small distance, the heat transfer is negligible Q = 0. Then the steady flow energy equation for the throttling process becomes,

hC = hB

Hence, enthalpy after throttling = enthalpy before throttlinghC=hf + xhfg

If the pressure of the steam before throttling, the pressure and temperature of the steam after throttling, are known the value of x can be calculated using steam tables.

Dryness Fraction =

Therefore, ws

so mm

mx

+=

Where, Ms the mass of dry steam and Mw is the mass of suspended water separated from the calorimeter.

Results

●C

A B ● ●

P2

P1

T2

T1

T

S

Page 4: Final lab report for thermos 2(mech)

Absolute Pressure = Gauge Pressure + Atmospheric pressure

=

=

= 841.33 KPa and = 30 KPa

= 112.5 and = 69.06

The above written values were calculated using interpolation method and values from the steam tables.

Separating calorimeter only (xo):

Ms: 1830mL = 1.83L = 1.83

Mw: 94mL = 0.94L= 0.94

=

=

= 0.95

Throttling calorimeter only x1

Specific enthalpy before throttling at P1 = specific enthalpy after throttling at P2

(Using interpolation)

= +

=

=

Page 5: Final lab report for thermos 2(mech)

This means it lies outside the dome

=

= 0,951

Table 1: Lab readingsReading Units

Volume of Steam (Vs) 0.00183 m3

Volume of Water (Vw) 0.000094 m3

Pressure before throttling (P1) 840 kPaPressure After throttling (P2) 30 kPaTemperature of steam before throttling (t1) 112,5 oCTemperature of steam After throttling (t2) 69,06 oC

4. Discussion Using the readings that were recorded in the lab the dryness fraction of the steam could be found, using the theoretical equations. From the results obtained the dryness fraction is 0.957 at x0 and 1.0064 at x1. The combined separating and throttling calorimeter was found by using equation 7 where both x0 and x1 were multiplied to get 0.951.

5. Conclusion It can be concluded that the experiment was successful. The dryness fraction of the steam was found using the readings found in the lab.

6. Recommendations The equipment in the lab should be either replaced or maintained in order to get more accurate readings. The students should be given the opportunity to record more than one value per reading so a mean can be obtained or so that there can be more certainty for each reading.

Page 6: Final lab report for thermos 2(mech)

Cape Peninsula University of TechnologyBellville Campus

Department of Mechanical Engineering

THERMODYNAMICS LABORATORY

THE ENTHALPIES AND ENTROPIES

By Student name Student no Signature

L. Nyandu

Subject: APT200SLecturer: S Makhomo

Evaluation Criteria

Introduction: (Aim for each lab, Background, List of the apparatus, Procedure etc)

10%

Result: (Calculations, Correct method, etc) 55%

Explanations (did you explain what you are doing rather than put formulas.)

10%

Discussion: (Discussion of the results, do they make sense? Any possible errors, etc)

10%

Conclusion and Recommendations: (Did we achieve our aims? What do we need to do to improve our results)

5%

Presentation, layout and neatness: (Cover page, Typed/ print neat, report format, etc)

10%

Total 100%

Date of submission:

LAB 2. THE ENTHALPIES AND ENTROPIES

Page 7: Final lab report for thermos 2(mech)

(a) = 740 + 101

= 840 KPa = 0.841 MPa

=

6.835688 = + x.Sfg

= 0.2821 + x (8.40686) X = 0.78

@ = .

4.187 x 18

= 75.366 KJ/Kg

= 75,36 + 0.78 (2458,26)

= 1987,89 KJ/Kg

=

= 2382,89 KJ/Kg

= 6.835688

@ =210

(b) @

=

Page 8: Final lab report for thermos 2(mech)

= 0.2677 + 0.78(8,334)

= 6.835 KJ/Kg

@

(C) = -

= 1987.89 -75.366

= 1912.526 KJ/Kg

= -

= 2382.89 – 75.366

= 2307.53 KJ/Kg

= -

= 2860.29 – 75.366

= 2785.03 KJ/Kg

(d) = -

= 6.835 – 0.2677

Page 9: Final lab report for thermos 2(mech)

= 6.557 KJ/Kg

= 8.1763 – 0.2677

= 7.9086 KJ/Kg

= 6.8345 – 0.2677

= 6.567KJ/Kg

(e)= -

= 2382.89 – 1987.89

= 395 KJ/Kg

= -

= 2860.296 – 1987.89

= 872.405 KJ/Kg

Page 10: Final lab report for thermos 2(mech)

(f)

= 8.1263 – 6.83

= 1.341 KJ/Kg

= 6.835688 – 6.835688

= 0KJ/Kg

Lab 2 readingsReadings Units

Boiler Pressure 841 kPaTemperature of feed water (to) 18 oCTemperature of superheated steam (tf) 210 oC

Page 11: Final lab report for thermos 2(mech)

Cape Peninsula University of TechnologyBellville Campus

Department of Mechanical Engineering

THERMODYNAMICS LABORATORY

BOILER EFFICIENCY & CONDENSERS

By Student name Student no

Signature

L.Nyandu

Subject: APT200SLecturer: S Makhomo

Evaluation Criteria

Introduction: (Aim for each lab, Background, List of the apparatus, Procedure etc)

10%

Result: (Calculations, Correct method, etc) 55%

Explanations (did you explain what you are doing rather than put formulas.)

10%

Discussion: (Discussion of the results, do they make sense? Any possible errors, etc)

10%

Conclusion and Recommendations: (Did we achieve our aims? What do we need to do to improve our results)

5%

Presentation, layout and neatness: (Cover page, Typed/ print neat, report format, etc)

10%

Total 100%

Date of submission:

Page 12: Final lab report for thermos 2(mech)

LAB 3. THE EFFICIENCIES

Boiler efficiency

Equivalent Evaporation

Rackine efficiency

Page 13: Final lab report for thermos 2(mech)

Lab 3 readingsReading

Units

Volume of fuel 5.9 x10-4 m3

Time 2.22 minMass flow rate of steam 318.18 kg/hCV of fuel 45.5 MJ/kgDensity of fuel 0.84 kg/L

Cape Peninsula University of TechnologyBellville Campus

Department of Mechanical Engineering

THERMODYNAMICS LABORATORY

BOILER EFFICIENCY & CONDENSERS

Page 14: Final lab report for thermos 2(mech)

By Student name Student no

Signature

L.Nyandu

Subject: APT200SLecturer: S Makhomo

Evaluation Criteria

Introduction: (Aim for each lab, Background, List of the apparatus, Procedure etc)

10%

Result: (Calculations, Correct method, etc) 55%

Explanations (did you explain what you are doing rather than put formulas.)

10%

Discussion: (Discussion of the results, do they make sense? Any possible errors, etc)

10%

Conclusion and Recommendations: (Did we achieve our aims? What do we need to do to improve our results)

5%

Presentation, layout and neatness: (Cover page, Typed/ print neat, report format, etc)

10%

Total 100%

Date of submission:

Page 15: Final lab report for thermos 2(mech)

LAB 4. THE CONDENSERS

Pressure inside the condenser

Dryness fraction of turbine exhaust steam entering condenser

(a) Condenser efficiency(ηc)

Vacuum efficiency (ηvac)

Pa = ρmghm

= 13.6 x 9.81x hm(m) / 1000

Page 16: Final lab report for thermos 2(mech)

Note: Relative density of mercury is 13.6PA = Pg + 0.133h (kPa) or PA = Pg + hm / 7.5 (kPa)

Lab 4 readingsReading

Units

Mass flow rate of cooling water (Mc/w) 5.09 kg/minInlet temperature to condenser of cooling water (tw1)

21 oC

Outlet temperature to condenser of cooling water (tw2)

27 oC

Condenser Pressure (Pc) 75 kPaCondensate Temperature (tk) 46 oC