final exam review current, power, voltage, resistance ohm’s law series & parallel circuits...
TRANSCRIPT
Final Exam Review
Current, Power, Voltage, ResistanceOhm’s Law
Series & Parallel CircuitsElectromagnetic Induction
Calculating a Power Bill
• Formula: $ = rPt• Bill = Rate * Power (kW) * time (h)
• For this application ONLY, Power is in kilowatts, and time is in hours.
Example
• At 0.007 $/kWh, calculate the cost of running a 1000W microwave for 30 minutes.
• $ = rPt• $ = (0.007 $/kWh)(1kW)(0.5h)• $ = $0.00350
=
Current, Power, Voltage
• 3 main equations:• Q = It• Charge (C) = Current (A) * time (s)
• V = IR• Voltage (V) = Current (A) * Resistance (Ω)
• P = IV• Power (W) = Current (A) * Voltage (V)
Properties of Circuit Types
• Series Parallel• Itot = I1 = I2 = I3 =… Itot = I1 + I2 + I3 + …
• Vtot = V1 + V2 + V3 +… Vtot = V1 = V2 = V3 =…
• Rtot = R1 + R2 + R3 +… 1/Rtot = 1/R1+1/R2+…
Example- Series Circuit
• A 9.0V battery is connected to four light bulbs in series, with resistances of 4.0 Ω, 5.0Ω, 7.0Ω, and 2.0Ω. Find the equivalent resistance for the circuit and the current in the circuit.
Example
• A 9.0V battery is connected to four light bulbs in series, with resistances of 4.0 Ω, 5.0Ω, 7.0Ω, and 2.0Ω. Find the equivalent resistance for the circuit and the current in the circuit.
• Rtot = R1 + R2 + R3 + R4
Example
• A 9.0V battery is connected to four light bulbs in series, with resistances of 4.0 Ω, 5.0Ω, 7.0Ω, and 2.0Ω. Find the equivalent resistance for the circuit and the current in the circuit.
• Rtot = R1 + R2 + R3 + R4
• Rtot = 4.0 + 5.0 + 7.0 + 2.0 = 18.0Ω
Example
• A 9.0V battery is connected to four light bulbs in series, with resistances of 4.0 Ω, 5.0Ω, 7.0Ω, and 2.0Ω. Find the equivalent resistance for the circuit and the current in the circuit.
• Rtot = R1 + R2 + R3 + R4
• Rtot = 4.0 + 5.0 + 7.0 + 2.0 = 18.0Ω
• V=IRtot
Example
• A 9.0V battery is connected to four light bulbs in series, with resistances of 4.0 Ω, 5.0Ω, 7.0Ω, and 2.0Ω. Find the equivalent resistance for the circuit and the current in the circuit.
• Rtot = R1 + R2 + R3 + R4
• Rtot = 4.0 + 5.0 + 7.0 + 2.0 = 18.0Ω
• V=IRtot
• 9.0V = I (18.0Ω)• I = 0.5A
Example- Parallel Circuit
• A 9.0V battery is connected to two resistors of 2.0Ω and 4.0Ω in parallel. Find the equivalent resistance for the circuit and the total current in the circuit.
Example
• A 9.0V battery is connected to two resistors of 2.0Ω and 4.0Ω in parallel. Find the equivalent resistance for the circuit and the total current in the circuit.
• 1/Rtot = 1/R1 + 1/R2
Example
• A 9.0V battery is connected to two resistors of 2.0Ω and 4.0Ω in parallel. Find the equivalent resistance for the circuit and the total current in the circuit.
• 1/Rtot = 1/R1 + 1/R2
• 1/Rtot = 1/2.0 + 1/4.0 = .75
• Rtot = 1.33Ω
Example
• A 9.0V battery is connected to two resistors of 2.0Ω and 4.0Ω in parallel. Find the equivalent resistance for the circuit and the total current in the circuit.
• 1/Rtot = 1/R1 + 1/R2
• 1/Rtot = 1/2.0 + 1/4.0 = .75
• Rtot = 1.33Ω
• V= IRtot
Example
• A 9.0V battery is connected to two resistors of 2.0Ω and 4.0Ω in parallel. Find the equivalent resistance for the circuit and the total current in the circuit.
• 1/Rtot = 1/R1 + 1/R2
• 1/Rtot = 1/2.0 + 1/4.0 = .75
• Rtot = 1.33Ω
• V= IRtot
• 9.0 = I (1.33Ω) I = 6.92A