factors affecting the x-ray output dr. nahla nagy
TRANSCRIPT
Factors affecting the
X-Ray output
Dr. Nahla Nagy
What is intensity?
1.Quantity
2.Quality
Intensity:
Total energy contained in the beam (product of quality and quantity of x-ray photons) per unit area per unit time
Quantity is the number
Quality is the energy
Together = the intensity of the X-ray
X-Ray Quantity
X-ray quantity: measure of the number of x-ray photons in the useful beam.
AKA x-ray output, intensity, or exposure Unit Roentgen (R) Directly affected by: Miliamperage-second (mAs) Kilovoltage (kVp) Distance (d)
X-Ray Quality
X-ray quality: : measurement of the penetrating ability of the x-ray beam.
Describes the distance an x-ray beam travels in matter. High energy x-ray photons travel farther in matter- more penetrating Numerically represented by the Half-value layer (HVL).
Factors Affecting IntensityFactors affecting intensity of x-ray beam actually
affect no. of photons or penetration power of
photon in x-ray beam.
1.Target Material
2.X-ray Tube Current (Miliamperage- mA)
3.Tube voltage (kVp)
4.Exposure time (s)
5.Filtration
6.Collimation
7.Source to film distance
Target Material
●Determines efficiency of X-ray production
●Higher the atomic number- greater will be
the efficiency of the production of x rays
X-ray Tube Current (mA)
1.Produced by flow of electrons from their point of origin (filament) to the anode (target) of x-ray tube
2.A change in filament voltage of about 5% result in 20-30% change in x-ray tube current (mA)
3.Hotter filament emits more electrons and adds electrons to the current electrons (mA) across the x-ray tube
4.Increased mA means increase in quantity of electrons available to hit the target -that results an increase in the quantity of x-ray photons
mA is directly proportional to quantity of x-ray beam
y axis = number of X-ray photons (quantity)x axis = energy of X-ray photons (quality)Area under the curve = intensity (product of quantity and quality)
Exposure Time (s)
1) Increasing time (s) heats filament for a
longer time.
2) Longer the filament is heated more
electrons are produced.
3) Increase in quantity of electrons
mAs (miliamperage seconds)
●mA and exposure time have a direct effect on the quantity of X-ray photons produced
●mAs is the product of mA (current) and exposure time (seconds); determine total number of x-ray photons produced
●The miliamperage required for a given exposure is inversely proportional to the exposure time
mAs Rule:
Original mA x Original time = New mA x New time
mA multiplied by s
ExampleIn an examination controls are set for 10 mA
and time is 30 sec, what is the mAs?
10mA x 30s = 300 mAs
If mA is increased to 15, how much time is
required to produce same mAs?
(original mA x original time = new mA x new time)
10mA x 30s = 15mA x Xs
X = 20 sec.
Tube Voltage (kVp)
1.Increasing kVp increases potential difference between the cathode and anode.
2.kVp controls the speed of the electrons, increasing kVp will
1.increase the number of x ray photons produced per unit time
2.Shorter wavelength and more penetrating photons of x-ray radiation are produced (i.e., increases speed)
3.Increase in quantity and quality of x-rays.Quantity = number (speed)Quality = energy
Increasing kVp, increases both number and
energy of x-rays Drastic increase in intensity (area under the graph)
Tube Voltage (kVp)
●Intensity is proportional to (kVp)2
●In dentistry to maintain same density :rule
of thumboIncrease of 15 kVp requires halving the exposure
time
oDecrease of 15 kVp requires doubling the
exposure time
Filtration
Filtration is the removal of low energy,
less penetrating photons from x-ray
beam by placing filter in the path of x-
ray beam. Filters are aluminum sheets placed at the end of the tube where x-rays exit
FiltrationTypes of Filtration
1.Inherent-X-ray tube and its housing
2.Added-Sheets of metal placed in
the path of the beam
3.The patient
Filtration1.No. of photons decreas
2.Mean (average) energy of photons increase
3.Maximum energy is unchanged
Effects quality and quantity of x-ray beam
Half value Layer
●Definition: The thickness of an absorber
required to reduce the number of x-ray
photons passing through it by one half of
its original value
●In dentistry :
69 kVp/ below HVL of 1.5mm Al
70-90 kVp HVL of 2.5 mm Al
Collimation
A collimator is a metallic barrier with an
aperture in the middle used to reduce the
size of the x-ray beam, thus, the volume of
irradiated tissue within patient is also
reduced
Main Functions
●Protect the patient
●Decrease the scatter radiation
Collimation
1.Reduces patient exposure
2.Reduces scatter radiation
3.Increases film quality
Round beam limiting device, 20
cm (8”) focus-film distance, 6 cm
(2,36”) output field diameter.
Rectangular beam limiting device as an
option to reduce patient’s exposure to
radiation.
www.jzimaging.com/SigmaBiomedics_Intraos_70.htm
Collimation
1.Number of photons decreases
2.Mean energy of photons is unchanged
3.Maximum energy of the photons is
unchanged
Inverse Square LawThe intensity of the X ray beam is inversely proportional to square of the source-film distance
I1/I2 = (D2)2/(D1)2
Source –film distance
●The x-rays of primary beam emerge from the
protective tube housing not as parallel rays but as divergent rays
●Intensity of the x-ray beam decreases as the distance from
the
source increases
Source –film distance
●Doubling the SFD distance ,exposure time
will have to be increased by the factor of 4
to maintain the same density on the film
Inverse Square Law
1.No of photons decreases
2.Mean energy of photons is unchanged
3.Maximum energy of the photons is
unchanged
Review
Factors affecting intensity
Tube voltage (kVp)
Current (mA)
exposure time (s)
Filtration
Collimation
Source to film
distance
Factors affecting Quantity
kVp
mA
Exposure time Filtration Collimation
Distance
Factors affecting
Quality
kVp
Filtration
Thank You