factoring different polynomials
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FactoringPolynomials
Because polynomials come in manyshapes and sizes, there are several patterns you need to recognize and
there are different methods for solvingthem.
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In Grade ten, you learned that there was a pattern withthese types of expressions. When this expression isfactored into two binomials, the two numbers will have a
product of 9 and a sum of -6.
Factoring Polynomials:
))(( x x
962 x x
Type 1:
Quadratic Trinomials with a Leading coefficient of 1
=962 x x - 3 - 3
2 Binomial Factors
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Factoring Quadratic
Equations with a = 1
Try these examples:
1) x2 + 7x + 12 2) x2 + 8x + 12
3) x2 + 2x –
3 4) x2 –
6x + 8
5) x2 + x – 12 6) x2 – 3x – 10
7) x2 – 8x + 15 8) x2 – 3x – 18
9) x2 – 3x + 2 10) x2 – 10x + 21
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There are a variety of ways that you can factor these typesof Trinomials:
a) Factoring by Decomposition
b) Factoring using Temporary Factors
c) Factoring using the Window Pane Method
Factoring Polynomials:
4195 2 x x
Type 2:
Quadratic Trinomials with a Leading coefficient = 1
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a) Factoring by Decomposition
Factoring Polynomials:
4195 2 x x
Type 2:
Quadratic Trinomials with a Leading coefficient = 1
1. Multiply a and c
2. Look for two numbers that multiply to that product and add to b
3. Break down the middle term into two terms using those two
numbers
4. Find the common factor for the first pair and factor it out & then
find the common factor for the second pair and factor it out.
5. From the two new terms, place the common factor in one bracket
and the factored out factors in the other bracket.
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a) Factoring by Decomposition
Factoring Polynomials: Type 2:
Quadratic Trinomials with a Leading coefficient = 1
1. Multiply a and c
2. Look for two numbers thatmultiply to that product and add to
b
3. Break down the middle term into
two terms using those two numbers
4. Find the common factor for the
first pair and factor it out & then
find the common factor for the
second pair and factor it out.
5. From the two new terms, place the
common factor in one bracket and
the factored out factors in the other
bracket.
20ca
The 2 nos. are -20 & 1
4195 2 x x
41205 2 x x x
)4(1)4(5 x x x
)15)(4( x x
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b) Factoring using Temporary Factors
Factoring Polynomials:
4195 2 x x
Type 2:
Quadratic Trinomials with a Leading coefficient = 1
1. Multiply a and c
2. Look for two numbers that multiply to that product and add to b
3. Use those numbers as temporary factors.
4. Divide each of the number terms by a and reduce.
5. Multiply one bracket by its denominator
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a) Factoring by Temporary Factors
Factoring Polynomials: Type 2:
Quadratic Trinomials with a Leading coefficient = 1
20ca
The 2 nos. are -20 & 1
4195 2 x x
)1)(20( x x
)15)(4( x x
1. Multiply a and c
2. Look for two numbers that multiply
to that product and add to b
3.Use those numbers as temporary
factors.
4.Divide each of the number terms by
a and reduce.
5.Multiply one bracket by its
denominator
5
1
5
20 x x
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c) Factoring using the Window Pane Method
Factoring Polynomials:
4195 2 x x
Type 2:
Quadratic Trinomials with a Leading coefficient = 1
1. Multiply a and c
2. Look for two numbers that multiply to that product and add to b
3. Draw a Windowpane with four panes. Put the first term in the
top left pane and the third term in the bottom right pane.
4. Use the two numbers for two x-terms that you put in the other
two panes
5. Take the common factor out of each row using the sign of the
first pane. Take the common factor out of each column using the
sign of the top pane. These are your factors.
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a) Factoring by Temporary Factors
Factoring Polynomials: Type 2:
Quadratic Trinomials with a Leading coefficient = 1
20ca
The 2 nos. are -20 & 1
4195 2 x x
1. Multiply a and c Look for two numbers
that multiply to that product and add
to b
2. Draw a Windowpane with four panes. Put
the first term in the top left pane and
the third term in the bottom right
pane.
3. Use the two numbers for two x-terms thatyou put in the other two panes.
4.Take the common factor out of each row
using the sign of the first pane. Take
the common factor out of each column
using the sign of the top pane. These
are your factors.
25 x
4 x20
x1
x5
1
x 4
)15)(4( x x
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Special Case Trinomials:
Loooking for Patterns:
A trinomial formed by squaring a binomial.
Ex1: (x + 5)2 Ex2: (2x – 3)2
Ex3: (x - 4)2 Ex4: (5x + 2)2
What do you notice about the resulting trinomials?
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Factoring Special Cases:Type 3:
Factoring Perfect Square Trinomials
1. First determine if the first and third terms are perfect
squares. Identify their square roots.
2. Determine if the middle term is twice the product of
those square roots. If so, then this Trinomial is a Perfect
Square Trinomial!
3. Set up two brackets putting the square roots in as the first
and second term for each binomial.
9124 2 x x
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Factoring Special Cases:Type 3:
Factoring Perfect Square Trinomials
1. First determine if the first and third
terms are perfect squares. Identify
their square roots.
2. Determine if the middle term is twice
the product of those square roots. If
so, then this Trinomial is a Perfect
Square Trinomial!
3. Set up two brackets putting the square
roots in as the first and second term
for each binomial.
9124 2 x x
Perfect Squares
2
22
)3(9
)2(4
x x
And )3)(2(212 x x
9124 2 x x
)32)(32( x x
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Factoring Special Cases:
Determine which of the following polynomials is a perfectsquare trinomial. If so, factor it.
1) x2 – 12x + 36
2) 9x2 + 34x + 25
3) x2 + 18x + 81
3) 64x2 - 20x + 1
Type 3: Factoring Perfect Square Trinomials
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Factoring Special Cases:
A binomial that is created by subtracting two perfectsquares.
Ex 1: x2 – 4 Ex 2: x2 – 625
Ex 3: 4x2 – 25 Ex 4: 16x2 - 81
What is true about the factored form of each of thesebinomials?
Type 4: Factoring a Difference of Squares
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Factoring Special Cases:Type 4:
Factoring A Difference of Squares
1. First determine if the two terms are perfect squares.
Identify their square roots.
2. Set up two brackets , one with an addition sign and the
other with a subtraction sign. They are different, get it?
3. Then insert the square roots in as the first and second
term for each binomial.
259 2 x
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Factoring Special Cases:Type 4:
Factoring A Difference of Squares
1. First determine if the two terms are
perfect squares. Identify their square
roots.
2. Set up two brackets , one with an
addition sign and the other with a
subtraction sign. They are different,
get it?
3. Then insert the square roots in as thefirst and second term for each
binomial.
259 2 x
Perfect Squares?
A Difference?
))(( x3 x35 5
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Factoring Special Cases:
Difference of Squares
Factor each of the following completely:
1) x2 – 100
2) x4 –
163) 100x2 – 400
4) 3x2 - 75
5) 225x2
–
121
#2 isn’t quadratic but it still can be factored!