experiment7chem210.doc
TRANSCRIPT
-
7/27/2019 Experiment7Chem210.doc
1/6
EXPERIMENT VII
DETERMINATION OF THE pKaOF AN INDICATOR (A WEAK ACID)
These files are in Adobe Acrobat format, if you are using NetscapeNavigator or Internet Explorer and have Adobe Acrobat Readerinstalled (If you do not; Acrobat Reader can be downloaded for freefrom Adobe) these files should open directly in your browser.
INTRODUCTION
Bromothymol blue is a common indicator used in acid-base titrations. Aswith many acid-base indicators, bromothymol blue is itself a weak acid anddissociates in the following manner;
Structure I Structure III
Structure II
C3H
7
C3
H7
CH3CH3
SO3-
OH+
BrBr
HO
C3 H7 C3 H7
CH3 CH3SO3
-
BrBr
C3 H7 C3 H7
CH3CH3
SO3-
BrBr
HO
O-O
O
Red (pH < 1) Blue (pH > 8)
Yellow (3 < pH < 6)
The above reaction can be written in a more general and convenient from as:
HIn + H2O In- + H3O+
HIn represents the protonated form of the indicatorIn- represents the unprotonated form of the indicator.
-
7/27/2019 Experiment7Chem210.doc
2/6
In order to be able to select an indicator for use in a titration a knowledge ofits pKa is necessary. In this experiment the pKa for bromothymol blue will bedetermined. A spectrophotometric method is particularly useful because adirect knowledge of [HIn] and [In-] is not necessary only the ratio of theconcentrations. The data from spectrophotometric measurements will providethe information necessary to calculate the ratio of these two forms.
PART I
THE DETERMINATION OF THE VISIBLE SPECTRUM OF[HIn] AND [In-]
THEORY
Bromothymol blue is a weak acid and in aqueous solution the followingreaction occurs:
HIn + H2O In- + H3O+
In a very acidic solution bromothymol blue will be present as the protonatedform HIn(Le Chtletiers Principle). This is solution 1 in in the Experimental Sectionbelow. In very basic solution bromothymol blue will be present as theunprotonated from In-(Le Chtletiers Principle). This is solution 2 in the Experimental Sectionbelow. Both bromothymol blue species [HIn] and [In-], strongly absorbelectromagnetic radiation in the visible region. At any particular wavelengththe amount of electromagnetic radiation absorbed (A) is related to the molar
concentration (C) of the absorbing species in solution through Beers Law:A = bC
Where:
= molar absorbtivity and is a constant at any wavelength
b = path length in cm of the solution through which theelectromagnetic radiation
passes; it is determined by the dimensions of the cell used inthe experiment.
A measure of absorbance A then is related directly to the concentration Cof the absorbing species in solution.
EXPERIMENTAL
1. Carefully pipet 4 mL of bromothymol blue stock solution into a clean 100-mL volumetric flask, add ~ 10 mL of deionized water to the flask, thenadd 16 drops of concentrated hydrochloric acid and dilute to the markwith deionized water and mix well. This will give you a pH = 1 solutioncontaining only HIn.
-
7/27/2019 Experiment7Chem210.doc
3/6
2. In a second 100-mL volumetric flask add 16 drops of hydrochloric acidand dilute to the mark with deionized water. This is your blank solution.
-
7/27/2019 Experiment7Chem210.doc
4/6
3. Carefully pipet 4 mL of the bromothymol blue stock solution into a third,clean, 100- mL volumetric flask, add ~ 10 mL of deionized water to theflask, then add 2 mL of a 4M sodium hydroxide solution and dilute to themark with deionized water, and mix well. This will give you a pH = 13solution containing only In-.
4. Into a fourth 100-mL volumetric flask add 2 mL of 4M sodium hydroxideand dilute to the mark with deionized water. This is your blank solution.
5. Use the solutions prepared above to obtain two spectra of bromothymolblue, one of the protonated form of the indicator HIn (Structure I) andthe other of the unprotonated form of the indicator In- (Structure III) overthe wavelength range 350 - 750 nm (Visible region of theelectromagnetic spectrum). For this, use a scanning spectrophotometer.Your instructor will give you instructions on the use of thespectrophotometer.
CALCULATIONS AND RESULTS
From your spectra select two wavelengths, one where the absorbance ofHIn is large and the absorbance of In- is small and the other where theabsorbance of In- is large the absorbance of HIn is small. These twowavelengths are critical and will be used in the second part of theexperiment.
PART II
DETERMINATION OF THE ABSORBANCE OF HIn
AND In
-
AS A FUNCTION OF pH
In the second part of the experiment the absorbance of HIn and In- at twowavelength selected in PART I. will be determined in solutions of varying pHusing a spectrophotometer.
THEORY
Bromothymol blue in aqueous solution is a weak acid and its dissociation aswe saw previously can be represented as:
HIn + H2O In- + H3O+
or mathematically
[ ]
-
3
a
In H OK
HIn
+ =
taking the -log and rearranging
-
7/27/2019 Experiment7Chem210.doc
5/6
-
a
InpH pK log
HIn
= +
The concentrations [In-] and [HIn] are related to the absorbencies (A) (BeersLaw) at the two wavelengths determined in Part I. The absorbencies willvary with pH as the concentrations of [In-] and [HIn] are pH dependent. Aplot of pH vs. Absorbance (A) at each wavelength gives a s shaped curvemuch like a titration curve. The point of inflexion in the curve represents thesituation where [In-] = [HIn] and the pH is numerically equal to the pKa.
EXPERIMENTAL
1. Into each of eight clean 100-mL volumetric flasks pipet carefully 4.00 mL
of bromothymol blue stock solution. Dilute to the mark using a differentbuffer solution (provided) for each flask.
2. Using a pH meter, determine the exact pH of each of the eight solutionsprepared in (1) above.
3. Measure the absorbance spectrum of each of the eight solutions from350 to 750nm using the appropriate buffer solution as a blank.
4. From your spectra, determine for each solution the absorbance at thetwo wavelengths of interest you selected in Part 1.
CALCULATIONS AND RESULTS
Determination of the ratio
Hln
-In
Combine the data from your spectra at pH = 1 and 13 (from Part I) andthe eight intermediate pH solutions. You should have ten absorbancemeasurements at each of two wavelengths and ten different pH's. Using
Excel construct two graphs, one graph at each wavelength of absorbance vs.pH. Take the derivative of each curve
pH
A
and plot the derivative vs. pH.
The peak in the curve represents the situation where [HIn] = [In-] and from
pH = pKa + log[ ][ ]lnHIn
pH = pKa
You have now two values at pKa compare the two values and then compare
them with the literature value.
-
7/27/2019 Experiment7Chem210.doc
6/6