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KULLIYYAH OF ENGINEERING END-OF-SEMESTER EXAMINATION SEMESTER 1, 2015/2016 SESSION Programme : Engineering Level of Study : UG 1 Time : 9.00 am -12.00 pm Date : 03/01/2016 Duration : 3 Hrs Course Code : ECE 1312/EECE 1312 Section(s) : 1- 5 Course Title : Electronics This Question Paper Consists of 12 (Twelve) Printed Pages (Including Cover Page) with 5 (Five) Questions. INSTRUCTION(S) TO CANDIDATES DO NOT OPEN UNTIL YOU ARE ASKED TO DO SO Total mark of this examination is 100. This examination is worth 50 % of the total course assessment. Answer ALL QUESTIONS Only approved calculator with ‘KoE approved’ sticker is allowed (non-programmable and non-graphical). Marks assigned to each problem are listed in the margins. 1

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KULLIYYAH OF ENGINEERING

END-OF-SEMESTER EXAMINATIONSEMESTER 1, 2015/2016 SESSION

Programme : Engineering Level of Study : UG 1Time : 9.00 am -12.00 pm Date : 03/01/2016Duration : 3 HrsCourse Code : ECE 1312/EECE 1312 Section(s) : 1- 5Course Title : Electronics

This Question Paper Consists of 12 (Twelve) Printed Pages (Including Cover Page) with 5 (Five) Questions.

INSTRUCTION(S) TO CANDIDATES

DO NOT OPEN UNTIL YOU ARE ASKED TO DO SO

Total mark of this examination is 100. This examination is worth 50 % of the total course assessment. Answer ALL QUESTIONS Only approved calculator with ‘KoE approved’ sticker is allowed (non-programmable and

non-graphical). Marks assigned to each problem are listed in the margins.

Any forms of cheating or attempt to cheat is a serious offence which may lead to dismissal.

All electronics gadgets are prohibited in the exam hall / venue.(e.g. mobile / smart phones, smart watches, and smart glasses)

APPROVED BY:

1

QUESTION 1 (20 marks)

a) A solar cell is a special type of pn-junction diode. The current equation of a particular solar cell is represented as follows:

I D=5.0×10−13[e(V D

V T)−1]−7.7×10−2 (A)

When the cell is irradiated with sunlight and the cell current, I D=0, the voltage V Dis referred to as the open circuit voltage, V OC. Similarly, when the cell is irradiated in the sunlight and the cell voltage, V D=0, the current I Dat that time is called the short circuit current, I SC. If the cell is operating at room temperature determine the parameters of the solar cell as follows: (4 + 2 marks)

i. Open circuit voltage, V OC

ii. Short circuit current, I SC

b) Consider the circuit shown in Fig. 1(b). The diode cut-in voltage is V γ=0.7V . Calculate the output voltage vO and plot it with respect to the input voltage v I in the same time

scale over the range of voltages −10V ≤ v I ≤ +10V for V B=5V. (4 marks)

Fig. 1(b)

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c) A clamper circuit is shown in Fig. 1(c). Write the equation of input-output voltage relation of the circuit. Sketch the output voltage waveform, vOagainst the time, t, if the input has sinusoidal voltage, vI=6 sin ( ωt )V and diode cut-in voltage, V γ=0V . (4 marks)

Fig. 1(c)

d) In the circuit shown in Fig. 1(d), the power rating of the Zener diode is 4W . Let, V I=58V , R i=150Ω ,V Z=16V and the minimum diode current is 15mA. (2 + 4 marks)

i. Determine the range of the diode current

ii. Determine the range of the load resistance, RL

Fig. 1(d)

QUESTION 2 (20 marks)

3

a) Consider the circuit shown in Fig. 2(a). Assume that V CC=2.8V ,β=180andV BE (on )=0.7V . Design the circuit by finding the values of RBand RCsuch thatI C=0.12mA and V CE=1.4V . (6 marks)

Fig. 2(a)

b) A transistor has current gain, β in the range of 90≤ β ≤180 and the collector current, I C is in the range of 0.8mA ≤ IC ≤1.2mA. What is the possible range of gmandr π? Assume that V T=0.026V . (5 marks)

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c) A common collector circuit is shown in Fig. 2(c). Given that = 100. Assume V BE (on )=0.7V . (3 + 3 + 3 marks)

i. Calculate the value of the DC collector current I C

ii. Sketch the small signal AC equivalent circuit. Assume that V A=∞

iii. Calculate the value of the output resistance RO

Fig. 2(c)

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QUESTION 3 (20 marks)

a) A transistor transconductance, gm=50mA /V and emitter resistancer π=1.5kΩwhen it is operating at room temperature. Determine the collector current I CQ and common emitter-current gain β of the transistor. Assume that V T=0.026V . (4 marks)

b) A common-emitter amplifier has output voltage −2.4V when its input voltage is 250mV . The collector resistance of the amplifier has 1.5kΩis changed to 2.5kΩ, what is the new voltage gain of the amplifier ? Consider that rO=∞.

(5 marks)

c) For the common emitter circuit in Fig. 3(c), the transistor parameters are β=100 and V A=∞. The parameters of the circuit are V BE (on )=0.7V , I C=0.5mA and V CE=3V . (5 + 2 + 4 marks)

i. Find the value of REand RC

ii. Draw the small-signal equivalent circuit

iii. Determine the value of the voltage gain, Av=vO /vS

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Fig. 3(c)

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QUESTION 4 (20 marks)

a) The transistor in the circuit in Fig. 4(a) has parameters V TN=0.8V and

Kn=0.2mA /V 2. Sketch the output load line and plot the Q-points for V DD=2V and RD=2kΩ. Assume the transistor is biased under saturation mode.

(7 marks)

Fig. 4(a)

b) The transistor in Fig. 4(c) has parameters V TN=0.4V , and Kn=4.8mA /V 2. The parameters of the circuit are I D=0.8mA and R1∨¿ R2=200kΩ. Assume that the transistor is biased under saturation mode.

(6 + 3 marks)i. Design the circuit by calculating R1 and R2

ii. Calculate the value of V DS and confirm that the transistor is biased under saturation mode

Fig. 4(c)

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c) For an NMOS biased in the saturation region, the parameters are K n' =0.1mA /V 2,

V TN=1.2V and I D=0.8mA. Determine the transistor width to length ratio (W /L ) such that gm=1.8mA /V . (4 marks)

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QUESTION 5 (20 marks)

a) The parameters of the common source circuit shown in Fig. 5(a) are V DD=12 ,RD=3 kΩ, RS=0.5kΩ , R1=894 kΩ , R2=347 kΩ and RL=10kΩ. The transistor parameters are, V TN=1.2V , Kn=1.5mA /V 2and λ=0.

(6 + 5 marks)

i. Find the values of I D and V DS

ii. Determine the input resistance, R¿ and the small-signal voltage gain, A v

Fig. 5(a)

b) Determine the output voltage vO for vI=3V for the op-amp circuit shown in Fig. 5(b). Then, calculate the output current that flows through 5kΩ resistor.

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(4 marks)

Fig. 5(b)

c) For the inverting summing amplifier shown in Fig. 5(c), determine the value of R3 if all the circuit parameters are given as: R1=50kΩ , R2=40kΩ, RF=50 kΩ and vO=−10V . The inputs to the circuit are, vI 1=1V , vI 2=2V and v I 3=0.3V .

(5 marks)

Fig. 5(c)Some Useful Equations

Equation for pn- junction:

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Equations for BJT

Equations for MOSFET

Kn=k n

'

2WL

END OF PAPER

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ID=I s(e

v D

V T −1)

gm=ICQ

V T

r π=β V T

I CQgm rπ=β

ro=V A

I CQ

I D=Kn [2 (V GS−V TN ) V DS−VDS2

]

ID=Kn (V GS−V TN )2

ro=V A

I DQ= 1

λ IDQ

λ= 1V A

gm=2√Kn I DQ