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Physical Chemistry
Lecture 6Reaction mechanisms and reaction-velocity predictions
Elementary reactionsReactions of interest are often complexSome reactions do occur in a single step -- elementary reactions Generally involve simple mono- or
bimolecular interactions “Order” (correctly, molecularity) in
elementary reactions is always the stoichiometry number of the reactant
Examples: H2 + O H2OH + Br HBr
“Simple” reaction sequences
Reversible two-step reaction
Irreversible sequential two-step reaction
Irreversible parallel two-step reaction
A B
B C a product
k
k
1
2
( )
A B
B A
k
k
f
r
A B
A C
k
k
1
2
Mathematics of simple reaction sequences
Reversible two-stepBoth first order
Irreversible parallelBoth first order
v k A k A 1 2[ ] [ ]
v k A k Bf r [ ] [ ]
Two-step irreversible process
Both steps first orderExactly solubleGives complex resultCan be understood qualitatively, as well as quantitatively
A B
B C a product
k
k
1
2
( )
Reaction mechanismA description of the course of a reaction that gives a set of elementary reactions Example from Bodenstein’s work:
Reaction mechanisms are not necessarily unique
52
42
32
22
12
5
4
3
2
1 2
vBrBrBrvBrHHBrHvBrHBrBrHvHHBrHBr
vBrBr
k
k
k
k
k
)(2)()( 22 gHBrgBrgH
2
Finding reaction velocityAssuming that every step is elementary allows one to know its rate equationFind expressions for disappearance of reactant or appearance of productInclude terms for every step that affects reactants (or products), with stoichiometryExample from Bodenstein’s work:
5312
432422
][
][][
vvvdt
Brd
vvvdt
HBrdvv
dt
Hd
Reducing rate equations
Eliminate dependence on reactive species (reactive intermediates such as radicals)Use approximations Steady state for reactive species Fast-equilibrium approximation when two
fast steps precede a slow one
Steady-state approximationReactive species have very low concentrationsAfter initiation, this concentration is presumed to be independent of time
Gives relation between velocitiesExample from Bodenstein’s work:
0][
dt
speciesreactived
d Br
dtv v v v v
[ ] 2 2 01 2 3 4 5
Fast-equilibrium approximationOne step containing an intermediate is rate-limitingPrior step is reversible
One presumes a quasi-equilibrium in the first two steps to relate the concentrations
( )
( )
( )
1
2
3
A B C fast
C A B fast
C
Product slow
]][[][][
]][[
][33
2
1 BAKkCkdt
Productd
BA
C
k
kK eqeq
Steady-state rate of formation of HBr
From the reaction mechanism, identify time changes of reactive species and use the steady-state approximation
These two equations give relations0
][
022][
432
54321
vvvdt
Hd
vvvvvdt
Brd
ss
ss
][][
]][[][
][][
423
2/122
2/1
5
221
2/12
2/1
5
151
HBrkBrk
BrH
k
kkH
Brk
kBrvv
ss
ss
Example: H2 + Br2 continuedIdentify the reaction velocity in terms of change of a reactant or product
Substitution gives the final prediction of the steady-state reaction rate by this mechanism
3
5312 ][
v
vvvdt
Brdv
][][
]][[
423
2/322
2/1
5
23
221
HBrkBrk
BrH
k
kkkvss
3
SummaryEvery reaction is described by an equation
“Simple” reaction sequences solved exactlyGenerally, equation like above does NOT describe reaction courseOften cannot get exact time dependence of concentrations for reactions Use a mechanism
Overall reaction expressed in terms of elementary steps Not unique
“Solve” mechanism, using approximations if necessary Rate-limiting steps Steady-state approximation Fast-equilibrium approximation
H gas Br gas HBr gas2 2 2( ) ( ) ( )