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TRANSCRIPT
Electric Potential Energy &
Voltage
Tesla Envy http://www.youtube.com/watch?v
=jlzEQZ4EfqA&feature=related
Ch 25: ENERGY & VOLTAGE
E is the FORCE FIELD: VECTOR
V is the ENERGY FIELD: SCALAR
The force field lines are everywhere
perpendicular to the potential energy field lines
Review: Work
• If F is constant then
• If F varies with r then along any radial segment
• The total work is
( )dW d F r dr F r
( ) f
i
r
rW F r dr
A force moving a mass through a displacement does WORK.
cosW Fr F r
Review: Conservative Forces
and Potential Energy
• A conservative force is defined as a vector field
that is equal to the negative of the
• gradient of a scaler field –
the ‘Poetential Energy’ function U:
• Leads to Work Energy Theorem and Conservation of
Energy:
f
i
x
xx
W F dx U K
x
dUF
dx
The gradient of a scalar field at a point is a vector pointing in the direction of
the steepest slope or grade at that point. The steepness of the slope at that
point is THE FORCE!!!
0
U K
E K U
Electric Potential Energy
• The work done by F along any radial segment is
• The work done by a force that is perpendicular to the displacement is 0. ds = dr
• The total work is
Since the Force is Conservative, the Work is independent of path.
W U K Recall that the work done by a
conservative force on an object is:
(As a rock falls, it loses PE but gains KE!!!)
0( ) ( )dW r ds q r ds F E
0 ( )B
AW q r d E r
Potential Difference in a Uniform Field
• Electric field lines always point in
the direction of decreasing electric
potential
• When the electric field is directed
downward, point B is at a lower
potential than point A
• When a positive test charge moves
from A to B, the charge-field system
loses potential energy
B B
B AA A
V V V d E d Ed E s s
The Electric Field does
work on the charge to
move it a distance d from
A to B, converting
Potential Energy into
Kinetic Energy, same as
with the gravitational field.
Conservation of Energy
and the Work-Energy
Theorem apply:
U K W F r
E
g
U qEd
U mgh
r d
(Uniform Field Only)
Electric Potential
B AV V V
The Electric Potential Energy per
unit charge between A and B is
called the Electric Potential
Difference between A and B.
For a uniform field:
0 0/q Ed q
Ed
V Ed
0/U q
ABV Ed
Electric Potential
•Unit for Electric Potential is the VOLT:
•1 V = J/C = N m /C
• Electric Potential is a SCALAR!
• Only DIFFERENCES in potential between
two points can be measured. There is no
potential for a single point unless the other
point is zero – the ground.
• Electric Potential is NOT Potential Energy!
• + charges move from hi to low potential
(think gravity – water fall)
• - charges move from low to hi potential
(think antigravity – water pump)
High Potential
Low Potential
B AV V V E s
Potential Difference: VOLTAGE
As a + particle moves from A to B, its
electric potential energy changes by
0 ( )B
B AA
U U U W q r d E r
Define the potential difference between points
A and B 0/V U q
B
B AA
V V V E ds
• The electric potential is independent of the path
• It is customary to choose a reference potential of V = 0 at rA = ∞
• E and V are perpendicular!!!
Electron Volts
What is the kinetic energy gained by
an electron when it moves across a
potential difference of 1 volt?
K U Vq
19( 1 )( 1.6 10 )V x C
191 / (1.6 10 )J C x C
191.6 10x J
191 1.6 10eV x J
Note: 5eV electron breaks organic bonds in molecules.
Nuclear decay energies ~ 1MeV
High Potential Low Potential
Example What is the final speed of a free
electron accelerated from rest through
a potential difference of 1V?
2qVv
m
K U
21
2mv q V
195
31
2( 1.6 10 )15.93 10 /
9.11 10
x C Vv x m s
x kg
Example A 12V motorcycle battery moves 5000C of charge. How much
energy does it deliver to that charge?
12V V
0/V U q
0U Vq
12 (5000 )V C
12 / (5000 )J C C
46.00 10x J
Potential (Voltage) is NOT Energy!
Problem
What is the magnitude of the maximum voltage that can be
sustained between 2 parallel plates separated by 2.5 cm of dry
air? Dry air supports max field strength (dielectric strength CH
26) of 3x 106 V/m .
V E s 6(3 10 )(.025 )x V m
47.5 10x V
75kV
More than this and the air breaks down and
becomes a conductor. LIGHTENING!
B AV V V E s
The dielectric breakdown strength of dry air, at
Standard Temperature and Pressure (STP), between
spherical electrodes is approximately 33 kV/cm.
Jacob’s Ladder
WARNING!
Exposure to an arc-producing device can pose health hazards. In a closed space such as a classroom or home, the continuous arc formation of an open-air Jacob's Ladder will ionize oxygen and nitrogen, which then reforms into reactive molecules such as ozone and nitric oxide. These free radicals can be damaging to the mucous membranes of people near the spark gap.
Time exposure
Potential and Point Charges • A positive point charge produces a
field directed radially outward
• The potential difference between
points A and B will be
1 1B A e
B A
V V k qr r
2
1 1B B B
B AA A A
B A
kqV V V E ds E dr dr kq
r r r
• The electric potential is independent of the
path between points A and B
• It is customary to choose a reference
potential of V = 0 at rA = ∞
• Then the potential at some point r is:
e
qV k
r
PROBLEM What is the electric potential 1.2m from a
point charge Q = + 4x10-8C. How does the potential
change if the charge is positive or negative?
r
Point Charge: ( )Q
V r kr
2 89
2
4 10( ) 9.00 10
1.2
Nm x CV r x
C m
( ) 300Nm
V rC
( ) 300V r V (Note: If Q is negative, V is negative!)
r
dVE
dr
The Electric Field is the Negative of the
Slope (Gradient) of the Electric Potential!
e
qV k
r
2e
qE k
r
The gradient of a scalar field at a point is a vector pointing in the direction of
the steepest slope or grade at that point. The steepness of the slope at that
point is given by the magnitude of the gradient vector.
In Sum: Potential due to a Point Charge
r
The potential a distance r from a point charge is given by:
( )Q
V r kr
V is the potential difference between r
and infinity where the potential is taken
to be zero (the ground is at infinity.)
V gives the amount of energy per unit
charge that it takes to bring a test charge
from infinity to r.
The total potential due to a distribution of charge is equal to the
algebraic sum of all the potentials (not vector sum!) The sign of
the charge matters!!!
Multiple Charges • The electric potential due to several
point charges is the sum of the potentials due to each individual charge, taking the potential at infinity equal to zero and r is the distance from the charge to the point P:
• The potential energy of the system is
1 2
12
q qU k
r
i
i i
qV k
r
0U q V
Problem Determine the electric potential at point A & B due to a dipole
A proton is placed at point A and released.
What is the change in potential energy of the proton between A and B?
What is the velocity of the proton at B?
U for System of Static Charges
• The potential energy of a system of charges is the energy needed to assemble them from infinity where U = 0. The total U includes a term for every pair of charges!!!
• For two charges it is:
• For three charges:
1 3 2 31 2
12 13 23
q q q qq qU k
r r r
1 2
12
q qU k
r
i j
net
ij ij
q qU k
r
Potential Energy Problem Determine the electric potential energy of the triangular group. That
is, find the work done to bring them from infinity to the triangular
arrangement. Is there a place interior to the group where the
potential is zero? The side of the triangle is 0.50m.
1 3 2 31 2
12 13 23
e
q q q qq qU k
r r r
i j
net
ij ij
q qU k
r
i
i i
qV k
r
Case 4: Electric Potential for ANY
Continuous Charge Distribution In general, the potential at
some point due to a small
charge element dq is
P e
dqdV k
r
V( )=0P e
dqV k
r
As shown in the text…
V for a Uniformly Charged Ring
Easier to calculate V
because it is a scalar! Find
E from the gradient.
2 2
dq kQV k
r a x
3/2
2 2
ˆ( )kxQ
E x ix a
x
dVE
dx
V for a Uniformly Charged Disk
• The ring has a radius R
and surface charge
density of σ
• P is along the
perpendicular central
axis of the disk
12 2 22V πkσ R x x
2 22 1Disk
xE k
x R
x
dVE
dx
Cavity in a Conductor
• Assume an irregularly
shaped cavity is inside
a conductor
• Assume no charges
are inside the cavity
• The electric field
inside the conductor
must be zero
Cavity in a Conductor, cont
• The electric field inside does not depend on the charge distribution on the outside surface of the conductor
• For all paths between A and B,
• A cavity surrounded by conducting walls is a field-free region as long as no charges are inside the cavity
0B
B AA
V V d E s
V Due to a Charged Conductor
• The potential difference between A and B is also zero
• The charge density is high where the radius of curvature is small
– And low where the radius of curvature is large
• The electric field is large near the convex points having small radii of curvature and reaches very high values at sharp points
Corona Discharge
• If the electric field near a conductor is sufficiently strong, electrons resulting from random ionizations of air molecules near the conductor accelerate away from their parent molecules
• These electrons can ionize additional molecules near the conductor
• This creates more free electrons
• The corona discharge is the glow that results from the recombination of these free electrons with the ionized air molecules
• The ionization and corona discharge are most likely to occur near very sharp points
Low energy corona discharge
surrounding a circular conductor.
Corona Discharge
Corona Discharge Supersonic Free-Jet
(CDSFJ) to generate excited-state molecular
nitrogen for growing III-N semiconductors. .
Jacob’s Ladder
WARNING!
Exposure to an arc-producing device can pose health hazards. In a closed space such as a classroom or home, the continuous arc formation of an open-air Jacob's Ladder will ionize oxygen and nitrogen, which then reforms into reactive molecules such as ozone and nitric oxide. These free radicals can be damaging to the mucous membranes of people near the spark gap.
Time exposure
Van de Graaff
Generator
• Charge is delivered continuously to a high-potential electrode by means of a moving belt of insulating material
• The high-voltage electrode is a hollow metal dome mounted on an insulated column
• Large potentials can be developed by repeated trips of the belt
• Protons accelerated through such large potentials receive enough energy to initiate nuclear reactions
Electrostatic Precipitator • An application of electrical discharge in gases
is the electrostatic precipitator
• It removes particulate matter from
combustible gases
• The air to be cleaned enters the duct and
moves near the wire
• As the electrons and negative ions created by
the discharge are accelerated toward the outer
wall by the electric field, the dirt particles
become charged
• Most of the dirt particles are negatively
charged and are drawn to the walls by the
electric field
Application – Xerographic
Copiers
• The process of xerography is used for
making photocopies
• Uses photoconductive materials
– A photoconductive material is a poor conductor
of electricity in the dark but becomes a good
electric conductor when exposed to light
Application – Laser Printer
• The steps for producing a document on a laser printer is similar to the steps in the xerographic process
• A computer-directed laser beam is used to illuminate the photoconductor instead of a lens
Millikan Oil-Drop Experiment –
Experimental Set-Up
PLAY
ACTIVE FIGURE
Millikan Oil-Drop Experiment
• Robert Millikan measured e, the magnitude
of the elementary charge on the electron
• He also demonstrated the quantized nature
of this charge
• Oil droplets pass through a small hole and
are illuminated by a light
Oil-Drop Experiment, 2
• With no electric field
between the plates, the
gravitational force and
the drag force
(viscous) act on the
electron
• The drop reaches
terminal velocity with D mF g
Oil-Drop Experiment, 3
• When an electric field is set up between the plates
– The upper plate has a higher potential
• The drop reaches a new terminal velocity when the electrical force equals the sum of the drag force and gravity
Oil-Drop Experiment, final
• The drop can be raised and allowed to fall
numerous times by turning the electric field on
and off
• After many experiments, Millikan determined:
– q = ne where n = 0, -1, -2, -3, …
– e = 1.60 x 10-19 C
• This yields conclusive evidence that charge is
quantized
• Use the active figure to conduct a version of the
experiment
Case 3: Electric Potential Given the
Electric Field
If there is sufficient symmetry
then you can use Gauss’s Law
to find the E field and find the
potential difference from
B
B AA
V V V dE s
Choose V = 0 at some convenient
point, usually infinity.
E Compared to V • The electric potential is a
function of r
• The electric field is a
function of r2
• The effect of a charge on
the space surrounding it:
– The charge sets up a
vector electric field
which is related to the
force
– The charge sets up a
scalar potential which
is related to the energy
Bohr Orbital Binding Energy for
Single Electron Atoms
2
213.6n
ZE eV
n
Ground State: n = 1
First Excited: n = 2
2nd Excited: n = 3
1. -13.6eV is the energy of the H ground state.
2. Negative because it is the Binding Energy and work must be
done on the atom (by a photon) to ionize it.
3. A 13.6eV photon must be absorbed to ionize the ground state