ecuacion

ECUACIONRESULRADO

Se obtuvo de la grafica Pi= 4580 psi

M= p/#ciclosM= 75

K= 162.6*((q*B*u)/ (m*h))K= 9.69 mD

Tp=24*(Np/Qo)Tp= 177822 hrs

P1h=> ((Tp+t)/ t)P1h=>177823

P3 = (((T3 T1) / (T2 T1))* (P2 P1))+ P1P3 = 4168 psi

P1h= Pi m *log ((Tp+t)/ t)P1h= 4186 psi

S= - 3.61

Ps=0.87*m*sPs= -235.6

Jreal= Q/(Pi-Pwf)Jreal=0.48

Jideal= Q/(Pi-Pwf- Ps)Jideal =0.39

Eff= (Jreal/ Jideal)*100Eff=123%

DIAMETROSECUACIONRESULTADO

1 9/16, 2, 3 3/8, 3 , 44 tiros = 1 pie x = 209.97 piesx= 840 tiros

2, 2 , 2 7/8, 3 3/86 tiros = 1 pie x = 209.97 piesx= 1260 tiros

3 5 tiros = 1 pie x = 209.97 piesx= 1050 tiros

La separacin de las cargas

4 tirosSep = (L / # de tiros)Sep = 0.25 pies



ECUACIONRESULTADO

BAJO BALANCE ESTTICO

sob = 0.052 x b x Dsob = Presin de sobre cargab = densidad del fluido de la formacin (ppg)D = profundidad

PARA EL GAS

Ggas=gas/ airgas = 7.55 x 10 -3 Lpg

sob = 0.052 x b x Dsob1 = 5.06 psi

PARA EL PETROLEO

GE = 141.5/(131.5+API)GE = 0.77

Goil=oil/ aguaoil = 6.42 Lpg

sob = 0.052 x b x Dsob2 = 4302 psi

sobT = sob1 + sob2sobT = 4307.06 psi

PRESIN DE PORO MNIMA

Ppmin = sob (1.7 x Rc)Ppmin = 4307.05 psi

PARA EL DESBALANCE MAXIMO

P max = Pf PpminP max = 5492.9 psi

PARA EL DESBALANCE MINIMO

Pmin (psi) = 2500/ k 0.17; 1 > k mdPmin (psi) =1317 psi

PARA EL DESBALANCE MEDIO

Pmed = (Pmax + Pmin)/2Pmed = 3405 psi

PRESIN HIDROSTTICA

Ph = Pf PPh = 6395 psi

Densidad Requerida

b = Ph / (1.4228 * D)b = 0.35 gr/cm3

BAJO BALANCE DINMICO.

Pdinamico = Pf PminimoDnde:Pdinamico= desbalance dinmico.Pf = presin de formacin

Pmin (psi) = 2500/ k 0.17; 1 > k mdPmin (psi) =1317 psi

Pdinamico = Pf PminimoPdinamico= 8483 psi

ecuacion

Documents