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  • 8/16/2019 [eBook] Math - Vedic Maths Tutorial

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    Vedic Maths Tutorial

    Vedic Maths is based on sixteen sutras or principles. These principles are general innature and can be applied in many ways. In practice many applications of the sutras may

     be learned and combined to solve actual problems. These tutorials will give examples ofsimple applications of the sutras, to give a feel for how the Vedic Maths system works.

    These tutorials do not attempt to teach the systematic use of the sutras. For moreadvanced applications and a more complete coverage of the basic uses of the sutras, we

    recommend you study one of the texts available.

     .!. The following tutorials are based on examples and exercises given in the book "Funwith figures" by #enneth $illiams, which is a fun introduction some of the applications

    of the sutras for children.

    If you are having problems using the tutorials then you could always read the

    instructions.

    Tutorial %Tutorial &

    Tutorial '

    Tutorial (Tutorial )

    Tutorial *

    Tutorial +

    Tutorial 1

    se the formula - F/0M 1 -2 T34 -5T F/0M %6 to perform instant

    subtractions.

    • For example 1000 - 357 = 643 

    $e simply take each figure in ')+ from 1 and the last figure from %6.

    5o the answer is 1000 - 357 = 643

    -nd thats all there is to it7

    http://www.vedicmaths.org/Group%20Files/sutras/sutras.asphttp://www.vedicmaths.org/Files/Books.asphttp://www.vedicmaths.org/Files/Books.asphttp://www.vedicmaths.org/Group%20Files/tutorial/tutorial.asp#instructionshttp://www.vedicmaths.org/Group%20Files/tutorial/tutorial.asp#tutorial1http://www.vedicmaths.org/Group%20Files/tutorial/tutorial.asp#tutorial2http://www.vedicmaths.org/Group%20Files/tutorial/tutorial.asp#tutorial3http://www.vedicmaths.org/Group%20Files/tutorial/tutorial.asp#tutorial4http://www.vedicmaths.org/Group%20Files/tutorial/tutorial.asp#tutorial5http://www.vedicmaths.org/Group%20Files/tutorial/tutorial.asp#tutorial6http://www.vedicmaths.org/Group%20Files/tutorial/tutorial.asp#tutorial7http://www.vedicmaths.org/Group%20Files/sutras/sutras.asphttp://www.vedicmaths.org/Files/Books.asphttp://www.vedicmaths.org/Group%20Files/tutorial/tutorial.asp#instructionshttp://www.vedicmaths.org/Group%20Files/tutorial/tutorial.asp#tutorial1http://www.vedicmaths.org/Group%20Files/tutorial/tutorial.asp#tutorial2http://www.vedicmaths.org/Group%20Files/tutorial/tutorial.asp#tutorial3http://www.vedicmaths.org/Group%20Files/tutorial/tutorial.asp#tutorial4http://www.vedicmaths.org/Group%20Files/tutorial/tutorial.asp#tutorial5http://www.vedicmaths.org/Group%20Files/tutorial/tutorial.asp#tutorial6http://www.vedicmaths.org/Group%20Files/tutorial/tutorial.asp#tutorial7

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    This always works for subtractions from numbers consisting of a % followed by

    noughts8 %669 %6669 %6,666 etc.

    • 5imilarly 10000 - 104! = "!51

    • For %666 : ;', in which we have more

  • 8/16/2019 [eBook] Math - Vedic Maths Tutorial

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    ; is & below %6 and + is ' below %6.

    Think of it like this8

    The answer is )*.

    The diagram below shows how you get it.

    ?ou subtract crosswise ;:' or + : & to get ),the first figure of the answer.

    -nd you multiply vertically8 & x ' to get *,

    the last figure of the answer.

    That's all you do:

    5ee how far the numbers are below %6, subtract onenumber"s deficiency from the other number, and

    multiply the deficiencies together.

    • 7 % 6 = 4$

    3ere there is a carry8 the % in the %& goes over to make ' into (.

     Multply These:

    1# ;

      ; x

    $# 1

      + x

    3# ;

      1 x

    4# +

      + x

    5# 1

      1 x

    6# *

      * x

    Total >orrect =Reset Test

    3ere"s how to use V4/TI>-? -2 >/055$I54 for multiplying numbers close to%66.

    • 5uppose you want to multiply "" &y !".

     ot easy,you might think. !ut with

    V4/TI>-? -2 >/055$I54 you can give

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  • 8/16/2019 [eBook] Math - Vedic Maths Tutorial

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    Try a few:

    1# %6& x %6+ =

    1# %6* x %6' =

    1# %6( x %6( =

    4# %61 x %6; =

    5# %6% x%&' =

    6# %6' x%6& =

    Total >orrect =Reset Test

    /eturn to Index

    Tutorial 3

    The easy way to add and subtract fractions.

    se V4/TI>-? -2 >/055$I54 to write the answer straight down7

    Multiply crosswise and add to get the top of the answer8

    & x ) = %6 and % x ' = '. Then %6 D ' = %'.The bottom of the fraction is Cust ' x ) = %).

    ?ou multiply the bottom number together.

    5o8

    5ubtracting is Cust as easy8 multiply crosswise as before, but the subtract8

    http://www.vedicmaths.org/Group%20Files/tutorial/Tutorial.asphttp://www.vedicmaths.org/Group%20Files/tutorial/Tutorial.asp

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    Try a few:

    Total >orrect =Reset Test

    /eturn to Index 

    Tutorial 4

    - Euick way to sEuare numbers that end in ) using the formula !? 04 M0/4 T3-

    T34 04 !4F0/4.

    • 75$ = 56$5

    +)& means +) x +).The answer is in two parts8 )* and &).

    The last part is always $5.The first part is the first number, +, multiplied by the number one more, whichis ;8

    so + x ; = 56

    http://www.vedicmaths.org/Group%20Files/tutorial/Tutorial.asphttp://www.vedicmaths.org/Group%20Files/tutorial/Tutorial.asp

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    • 5imilarly "5$ = 7$$5 because ; x 1 = +&.

    Try these:

    1# ()& =

    $# *)& =

    3# 1)& =

    4# ')& =

    5# %)& =

    Total >orrect =Reset Test

    Method for multiplying numbers where the first figures are the same and the last figures

    add up to %6.

    • 3$ % 3" = 1$16

    !oth numbers here start with ' and the last

    figures A& and ;B add up to %6.

    5o we Cust multiply ' by ( Athe next number upBto get 1$ for the first part of the answer.

    -nd we multiply the last figures8 & x ; = 16 to

    get the last part of the answer.

    2iagrammatically8

    • -nd "1 % "! = 7$0!

    $e put 61 since we need two figures as in all the other examples.

     Practise some:

    1# (' x (+ =

    $# &( x &* =

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    3# *& x *; =

    4# %+ x %' =

    5# )1 x )% =

    6# ++ x +' =

    Total >orrect =Reset Test

    /eturn to Index 

    Tutorial 5

    -n elegant way of multiplying numbers using a simple pattern.

    • $1 % $3 = 4"3

    This is normally called long multiplication butactually the answer can be written straight down

    using the V4/TI>-? -2 >/055$I54

    formula.

    $e first put, or imagine, &' below &%8

    There are ' steps8

    aB Multiply 'ertically on the left8 & x & = 4.

      This gives the first figure of the answer. bB Multiply cross(ise and add8 & x ' D % x & = "  This gives the middle figure.

    cB Multiply 'ertically on the ri)ht8 % x ' = 3  This gives the last figure of the answer.

     And thats all there is to it.

    • 5imilarly 61 % 31 = 1"!1

    http://www.vedicmaths.org/Group%20Files/tutorial/Tutorial.asphttp://www.vedicmaths.org/Group%20Files/tutorial/Tutorial.asp

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    • * x ' = 1"9 * x % D % x ' = !9 % x % = 1

    Try these, just write down the answer:

    1# %(

      &% x

     

    $# &&

      '% x

     

    3# &%

      '% x

     

    4# &%

      && x

     

    5# '&

      &% x

    Total >orrect =Reset Test

    Multiply any &:figure numbers together by mere mental arithmetic7

    If you want &% stamps at &* pence each you caneasily find the total price in your head.

    There were no carries in the method given above.

    3owever, there only involve one small extra step.

    • $1 % $6 = 546 

    The method is the same as above

    except that we get a &:figure number, %(, in themiddle step, so the % is carried over to the left

    A( becomes )B.

    5o &% stamps cost G).(*.

    Hractise a few8

    1# &%

      (+ x

     

    $# &'

      (' x

     

    3# '&

      )' x

     

    4# (&

      '& x

     

    5# +%

      +& x

     

    Total >orrect =Reset Test

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    • 33 % 44 = 145$

    There may be more than one carry in a sum8

    Vertically on the left we get %&.

    >rosswise gives us &(, so we carry & to the left

    and mentally get %((.

    Then vertically on the right we get %& and the %

    here is carried over to the %(( to make %()&.

    6# '&  )* x

     

    7# '&  )( x

     

    "# '%  +& x

     

    !# ((  )' x

     

    10# )(  *( x

     

    Total >orrect =Reset Test

    -ny two numbers, no matter how big, can bemultiplied in one line by this method.

    /eturn to Index 

    Tutorial 6

    Multiplying a number by %%.

    To multiply any &:figure number by %% we Cust put

    the total of the two figures between the & figures.

    $6 % 11 = $"6 

     otice that the outer figures in &;* are the &*

     being multiplied.

    -nd the middle figure is Cust & and * added up.

    • *o 7$ % 11 = 7!$ 

    http://www.vedicmaths.org/Group%20Files/tutorial/Tutorial.asphttp://www.vedicmaths.org/Group%20Files/tutorial/Tutorial.asp

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    Multiply by %%8

    1# (' =

    $# ;% =

    3# %) =

    4# (( =

    5# %% =

    Total >orrect =Reset Test

    • 77 % 11 = "47 

    This involves a carry figure because + D + = %(

    we get ++ x %% = +%(+ = ;(+.

    Multiply by %%8

    1# ;; =

    $# ;( =

    3# (; =

    4# +' =

    5# )* =

    Total >orrect = Reset Test

    • $34 % 11 = $574 

    $e put the & and the ( at the ends.

    $e add the first pair & D ' = ).and we add the last pair8 ' D ( = +.

    Multiply by %%8

    1# %)% =

    $# )&+ =

    3# ''' =

    4# +%( =

    5# 161 =

    Total >orrect =Reset Test

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    /eturn to Index 

    Tutorial 7Method for diving by 1.

    • $3 + ! = $ remainder 5 

    The first figure of &' is &, and this is the answer.

    The remainder is Cust & and ' added up7

    • 43 + ! = 4 remainder 7 

    The first figure ( is the answer and ( D ' = + is the remainder : could it be easier

    2ivide by 18

    1# *% = remainder

    $# '' = remainder

    3# (( = remainder

    4# )' = remainder

    5# ;6 = remainder

    Total >orrect =Reset Test

    • 134 + ! = 14 remainder " 

    The answer consists of 14 and ".

    1 is Cust the first figure of %'(.

    4 is the total of the first two figures %D ' = (,and " is the total of all three figures %D ' D ( = ;.

    2ivide by 18

    6# &'& = remainder

    7# %)% = remainder

    "# '6' = remainder

    !# &%& = remainder

    http://www.vedicmaths.org/Group%20Files/tutorial/Tutorial.asphttp://www.vedicmaths.org/Group%20Files/tutorial/Tutorial.asp

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    10# &%&% = remainder

    Total >orrect =Reset Test

    • "4$ + ! = "1$ remainder 14 = !$ remainder 14 

    -ctually a remainder of 1 or more is not usually permitted because we are trying to find howmany 1"s there are in ;(&.

    5ince the remainder, %( has one more 1 with )

    left over the final answer will be !3 remainder 5 

    2ivide these by 18

    1# ++% = remainder

    $# 1(& = remainder

    3# )*) = remainder

    4# ))) = remainder

    5# +++ = remainder

    6# &';& = remainder

    7# +6+6 = remainder

    Total >orrect =Reset Test

    /eturn to Index 

    Instructionsfor using the tutorials

    4ach tutorial has test sections comprising of several Euestions each. ext to each

    Euestion is a box AfieldB into which you can enter the answer to the Euestion. 5elect the

    first Euestion in each test with the mouse to start a test. 4nter the answer for the Euestionusing the numeric keys on the keyboard. To move to the answer field of the next Euestion

    in the test, press the ,T, key. Moving to the next Euestion, will cause the answer youentered to be checked, the following will be displayed depending on how you answered

    the Euestion 8:

    http://www.vedicmaths.org/Group%20Files/tutorial/Tutorial.asphttp://www.vedicmaths.org/Group%20Files/tutorial/Tutorial.asp

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    >orrect

    $rong-nswer has more than one part Asuch as fractions and those answers with

    remaindersB. -nswering remaining parts of the Euestion, will determine whether youanswered the Euestion correctly or not.

    5ome browsers will update the answer on ,/T/2, being pressed, others do not. -ny problems stick to the "T-!" key. Hressing ,*T T, will move the cursor back to the

    answer field for the previous Euestion.

    The button will clear all answers from the test and set the count of correct answers backto