dual water model
TRANSCRIPT
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Dual Water Model
Intellectual Property
This presentation is sole the property
of the INDONESIA TRAININGCENTRE.
It is not to be duplicated or used byanyone other than the individual for
personal use who has attended thecourse.
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Dual Water Model
Dual Water Model
Schlumber er 1999
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Dual Water Model
Shale and Saturation
The Archie equation has to be changed to takeaccount of the shale effect.
The shale looks like low resistivity so anotherterm is added to the equations.
The result is an equation which will can be usedto compute water saturation in shaly sands.
All these equations return to Archies equation ifthere is no shale present.
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Saturation Equations
Indonesia Equation
Nigeria Equation
Waxman-Smits Equation
Dual Water Equation
1
Rt=
Sw2
F*Rw
+ BQvSw
F*
Ct = tmSwtn
aCw +
Swb
SwtCwb Cw( )
Sw = 1
Vcl
1Vcl2
Rcl
+ eR
w
* 1
Rt
1
Rt=
Vcl1.4
Rcl+
em
2
aRw
2
Swn
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Saturation equations 2
One of the difficulties is the number ofequations available for shaly sands.
They are often country oriented, Nigeria,Venuzeula..
The choice of equation was (is) dictated bylocal practice.
Waxman-Smits (WS) and Dual Water(DW) approach the problem fromexperiments on the clay properties and are
thus more realistic and universal.
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Dual water
The Dual Water Model takes the basic work ofWaxman Smits and expands it for use with loggedinformation
It divides the formation into solids and fluids.
It splits the clay into dry clay and its associated
water, called bound water
The standard definitions for porosity andsaturation to describe the fractions of fluids in theformation are expanded to include the new model.
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Dual water model definitions
hydrocarbon
far
water
bound
water
dry
clay
clean
matrix
fluids
solids
unitvolume
Vcl
wet clayVdcl
wb
wf
hyeffectiveporosity
etotal
porosity
t
= wf+ hy
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Clean to Shale
t
t
t
t
Matrix
Matrix
Matrix
Dry Colloid
Dry Colloid
Bound water
Far Water
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Dual Water Model
Dual Water definitions 2
the porosities are combined to give the saturations of thefluids present
Swb = wb
t
Swf =
wf
t
Shy =hy
t
wt = wf + wb
t =e + wb = t1 Swb( )+ tSwb
wt + hy =1
Vcl = Vdcl + t wb
saturation of bound water
saturation of far water (this is Sw)
Hydrocarbon saturation
Total water saturation is the sum
of the saturations of the two waters
total water saturation plushydrocarbon saturation must beone
wet clay volume includes the volume
of bound water
The total porosity is given by
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Simplified DWM
Swt2
=Rf
t2Rt
Archie Equation can be generalized into the following form;
where;
Swt - total water saturation
ft - total porosity
Rt - true formation resistivity
Rf - resistivity of the water(s)
The equation can be solved if Rf is known.
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Simplified DWM 2
1) Clean water bearing zone
Swt = 1
t2Rt = Rf
This is Rwf, the resistivity of Far water
2) Clean 100% shale zone
Swt = 1
t2Rt = Rf
This is Rwb, the resistivity of Bound water
These are the two end points. To give a universalsolution they are combined linearly using thevolume of shale.
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Practical DWM 2
Ct=
t
mSwt
n
aC
wf+
Swb
Swt
Cwb
Cwf
( )
The standard equation for the water saturationis expressed in terms of the conductivity, as it islinear.
This equation is in terms of measured quantities,porosity and resistivity and parameters that canbe found, the far and bound water conductivities.
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DWM Saturation solution
Swt =x + x2
+CtF0
Cw
x = Swb Cw Cwb( )2Cw
Fo = a m
The solution to the equation is
where
and
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Practical outputs
The equations give total water saturation Swtand total porosity t. These have to betransformed into effective saturation, Sw andeffective porosity, wf (or e)
Sw = Swt Swb
1 Swb
wf = t Swt Swb( )
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Dual water equation solution
This derivation of the Dual Water equations isvalid for any rock with any mixture of fluids
It is possible to use the Dual Water Model tomake a manual computation of a shaly zone.
However computer programs are bestequipped to handle the calculations.
The selection of key parameters is essential toobtain the correct answers,
Cwf - free water conductivity
Cwb - bound water conductivity
Swb - bound water saturation
t - total porosity
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Rwa-GR crossplot
10.00
3.16
1.00
.32
.10
.03
Hydrocarbon Sands
FREQUENCY PLOT
Shales
Water Sands
Gamma Ray API
1500 30 60 90 120
Rwb
Rw
R =wa
tm
aR
t
in clean zones R = Rwa w
in shale zones R = Rwa wb
Rwa
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Appendix
This appendix contains a brief introduction to thebehaviour of clays in the formation.
Full details are available in the relevant technicalpapers.
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Clays
Clays are usually present as sheet like particles
with very large surface areas compared to theirvolume
There is an excess negative charge inside thesheet due to atoms with 3 units of positivecharge (e.g. Al) being substituted by atoms
with 2 (e.g. Mg)The system is balanced by positive counterionson the surface of the clay sheets
This is measured by the Cation ExchangeCapacity - CEC
the units are milli-ion equivalent per 100gr ofdry clay material
It is different for each clay type
Montmorillonite - 1.00 meq/gr
Illite - 0.20 meq/gr
Kaolinite - 0.05 meq/gr
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Clay charge
When the clays are immersed in water (as in areservoir)
- the force keeping the counterions on the claysurface are reduced by the dielectric propertiesof the water
- the counterions leave the clay surface- they move in a layer of water close to thesurface
- they contribute to the electrical conductivityof the rock
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Diffuse layer
The sodium ions (Na+) from the salt water areat a high concentration close to the clay surface
This decreases until far away they reachequilibrium with the chlorine
The negative chlorine (Cl-) behaves in theopposite sense
The thickness of the layer where the positiveions are at a higher concentration is governedby the Gouy model and depends on the salinityof the water
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Exclusion Layer
The simple situation is complicated by the finitesize of the molecules involved.
There is a layer of water molecules adsorbed onthe clay surface and a shell around the sodiumion
This gives a minimum thickness of the layer atthe Outer Helmholtz Plane of xH
This distance at standard temperatures andpressures is 6.18 angstroms ()
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Diffuse layer thickness
The diffuse layer thickness, xd has its minimumof xH at a water resistivity, Rw of 0.245 ohm-m(at standard temperature and pressure)
Above this resistivity
xd = xHwhere depends on the resistivity (salinity),i.e.
= 1= , if Rw < 0.245 ohm-mxd
xH