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普通物理 Sept./18/2008 Dr. 陳柏頴 W01 上課資料

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  • Sept./18/2008

    Dr. W01

  • 1. 1991 (Sep.)-1995 (May.)

    2. 1989 (Sep.)-1991 (May.)

  • 30 %: 20% 3%

    : 1x 30 %=30 %

    : 2 x 5 %=10%

    ---

    2%, (14)

    : 1x 10 %=10 % ()

    : 1x 10 %=10 % ()

  • : 25 min presentation, 5min Q&A

    Power-point presentation

    Word13, 12

    :

    ---- topics

    ---

  • ---

    1.

    2. 3.

    4.

    5.

    6.

    8. 7.

    ---

  • & &

    2. Textbook

    (1) Harris Benson, University Physics, Revised Edition, Wiley

    International Edition,

    (2) Reese, University Physics, 2,

    , ,

    , 0005A7

  • C = ( K + S ) A C=CompetenceK=KnowledgeS=SkillA=Attitude

    Stein B.Jensen, et al. ICEE 2001 International Conference on Engineering Education 2001 Oslo, Norway

  • 1.1 1.1

    1.2 - 1.2 -

    1.3 1.3

    1.4 1.4

    1.5 1.5

    1.6 1.6

    1.7 1.7

    1.8 1.8

  • m (momentum)

    SI

    m (momentum)

    SI

    rv rp

    r rp vm

    kg m / s

  • CH1CH11

    r rF atotal = m

    r r

    F ptotal =ddt

    r r

    F ptotal total=d

    dt

    r r r

    rr

    F p v

    v a

    totaltotal= =

    = =

    ddt

    ddt

    m

    m ddt

    m

    ( )

  • CH1CH11 1.1

    rv i= +( . )$5 00 m / s ( )$600 m / s j

    600 kg

    a. b. 0.145 kg

  • CH1CH11r rp v

    i j

    i j

    =

    = +

    = +

    m

    (600 kg)[(5.00 m / s) m / s

    kg m / s) (3.60 10 kg m / s3$ ( . )$]

    ( . $ )$6 00

    3 00 103

    p = + =

    [( . ) ].

    /300 104 69 10

    3 2 1 2

    3

    kg m / s) (3.60 10 kg m / skg m / s

    2 3

    p m=

    4 69 103. ) =kg m / s (0.145 kg

    = =3 23 10. 4 m / s 32.3 km / s

    b. b.

  • CH1CH11 -

  • CH1CH11

    r rF ptotal ( )t dt d=

    ( )t ti fr r

    r

    r

    F pp

    p

    totali

    f

    i

    f ( )t dt dt

    t=

    r r rF p ptotal f ii

    f ( )t dtt

    t=

    r rI F total

    i

    f ( )t dtt

    t

  • CH1CH11 (1.3)

    - (impulse-momentum theorem)

    r rp pf i rp

    r rI p=

  • CH1CH111.2 ti tf

    ( )t ti f

  • CH1CH11 (impulsive force)1.3

    F t F dt Ix x xtt

    ave totali

    f

    I F t px x x= =ave

    F ptxx

    ave =

  • CH1CH110.250 kg2.00 m

    a. (1.4)

    b.

    c. 0.010 s

    7.2

  • CH1CH11y y t a ty y= + +0 0

    212

    y

    ay

    y

    0

    0

    2 000

    ==

    =

    . mm / s

    9.81 m / s2y = 0

    0 2 00m m (0 m / s) 12

    ( 9.81 m / s )2 2= + + . t t

    t = 0 639. srI j j

    j

    = =

    =

    ( $) $( )$

    mg dt mg dt

    mg t

    t t

    0 0

    0rI j

    j

    =

    =

    ( )$

    ( . $0.250 kg)(9.81 m / s )(0.639 s

    1 kg m / s )

    2

    257

  • CH1CH11m/s27.6)s)(0.639m/s9.81(m/s0 20 =+=+= ta yyy

    j)m/skg57.1(j)m/s6.27kg)((0.250vp ff ===rr m

    rp ji kg m / s= ( )$0

    j)m/skg57.1(j)m/skg0(j)m/skg57.1(ppp if

    ===

    rrr

    ( .t = 0 010 s)

    j)m/skg57.1(j)m/s6.27kg)(025.0(vp impacti

    ===

    rr m

    rp jf 0 kg m / s= ( )$2

    j)m/skg57.(1j)m/skg57.1(jm/s)kg0(ppp if

    ===

    rrr

    r rI p=

    j)N106.1(s010.0

    j)m/skg75.1(IF2

    2

    ave

    =

    =

    =

    t

    rr 16 10

    2 4565

    2..

    =N

    N

    b.

    b.

  • CH1CH11

    (conservation of momentum)

    rp total

    0 N total= ddt

    rp

    rp total

    r r

    F ptotal total=d

    dt

  • CH1CH11

    r r rp p ptotal bfr bfr bfr +1 2r r rp p ptotal aft aft aft +1 2r rp ptotal bfr total aft=