Download - TRIAL MATE SPM 2010 Kedah Paper 2 Answer
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8/8/2019 TRIAL MATE SPM 2010 Kedah Paper 2 Answer
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SULIT 1449/2(PP)
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1449/2(PP) SULIT
1449/2 (PP)
Matematik
Kertas 2
Peraturan
Pemarkahan
September
2010
PERSIDANGAN KEBANGSAAN PENGETUA-PENGETUA
SEKOLAH MENENGAH
NEGERI KEDAH DARUL AMAN.
PEPERIKSAAN PERCUBAAN SPM 2010
UNTUK KEGUNAAN PEMERIKSA SAHAJA
Peraturan pemarkahan ini mengandungi 19 halaman bercetak
MATHEMATICS
Kertas 2
PERATURAN PEMARKAHAN
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8/8/2019 TRIAL MATE SPM 2010 Kedah Paper 2 Answer
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SULIT 1449/2(PP)
1449/2(PP) SULIT
2
Section A
[ 52marks]
Question Solution and Mark Scheme Marks
1(a)
(b)
Note :
PR correctly shaded, award K1
K1
K2 3
P R
Q
P R
Q
P R
Q
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SULIT 1449/2(PP)
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1449/2(PP) SULIT
3
Question Solution and Mark Scheme Marks
2 24 3 7 0 !x x
1 4 7 0 !x x or equivalent
OR2( 3) ( 3) 4(4)( 7)
2(4)
s !x (K1)
1! x
7 31 1 75
4 4! x or or
Note : 1. Accept without =0.
2. Accept three terms on the same side, in any order.3. Accept correct answer from the correct term without
factorisation for Kk2.
K1
K1
N1
N1 4
3 33 21
2p q ! or 3 2 18p q ! or equivalent
Note:
Attempt to equate the coefficient of one of the unknowns award
K1
4 12q ! or 4 32p ! or equivalent
OR
14 2p q! or14
2
pq
! or equivalent (K1)
2(9 )
3
qp
! or
39
2q p! or equivalent (K1)
Note:
Attempt to make one of the unknowns as the subject, award K1
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SULIT 1449/2(PP)
1449/2(PP) SULIT
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Question Solution and Mark Scheme Marks
OR
1 2141
3
3 911 1 2 22
p
q
!
or equivalent (K2)
8p !
3q !
Note :
Accept
1.8
3
p
q
!
as final answer, award N1
2.
1 2141
33 91
1 1 2 22
or equivalent seen, award (K1)
N1
N1
4(a)
(b)
T or
T
2 2
12tan
6 8!
or equivalent
50 19 r or 50 11'r or 50 12'r
P1
K1
N1 3
5(a)(i)
(ii)
(b)
False // Palsu
True // Benar
If 2 0x " , then 0 or 0x x" //
Jika 2 0x " , maka 0 atau 0x x"
P1
P1
P1
4
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SULIT 1449/2(PP)
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1449/2(PP) SULIT
5
Question Solution and Mark Scheme Marks
(c)
If 0 or 0x x" , then 2 0x " //
Jika 0 atau 0x x" , maka 2 0x "
5 and 9 are odd numbers // 5 dan 9 adalah nombor ganjil
P1
K1 5
6(a)
(b)
0 2 5x! or equivalent
5
2x ! or
12
2 or 2 5
mQR = 2
6
4
y
x
!
*mQR or 6 =
*mQR(4) + c or equivalent
2 14y x! or equivalent
K1
N1
P1
K1
N1 5
7(a)
(b)
p = 14
q = 4
2 3 13
4 1 5
x
y
!
1 3 131
4 2 2(2)(1) ( 3)(4)
x
y
!
or
*
13
2
x inverse
y matrix
!
2x !
3y !
P1
P1
P1
K1
N1
N1
2
4
6
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SULIT 1449/2(PP)
1449/2(PP) SULIT
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Question Solution and Mark Scheme Marks
Note:
1. Do not accept
*
2 3 1 0
4 1 0 1
inverseor
atrix
!
.
2.2
3
x
y
!
as final answer, award N1.
3. Do not accept any solutions solved not using matrix method.
8 21 22 3 5 63 7
v v v
222
5 47 v v
2 21 22 223 5 6 5 43 7 7
v v v v v - -
2739
7 or
2391
7 or 391 3
Note :
1. Accept T for K mark.2. Correct answer from incomplete working, award Kk2.
K1
K1
K1
N1 4
9(a)
(b)(i)
{(S,C), (S,O), (S,R), (S,E), (C,S), (C,O), (C,R), (C,E), (O,S),
(O,C), (O,R), (O,E), (R,S), (R,C), (R,O), (R,E), (E,S), (E,C),
(E,O), (E,R)}
Note :
1. Accept correct tree diagram or grid for P22. Accept 10 correct listings for P1
{(C,S), (C,O), (C,R), (C,E)}
4
20 or
1
5
P2
K1
N1
2
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SULIT 1449/2(PP)
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1449/2(PP) SULIT
7
Question Solution and Mark Sche me Marks
(ii) {(S,C), (S,R), (C,S), (C,R), (O,E), (R,S), (R,C), (E,O)}
8
20 or
2
5
Note :
Accept answer without working from correct listing,
tree diagram or grid.
K1
N1 4
6
10(a)
(b)
90 222 14
360 7v v v or
120 222 7
360 7v v v
90 222 14
360 7v v v +
120 222 7
360 7v v v + 14 + 7 + 7 or equivalent
194
3 or
264
3 or 64 67
290 22 14360 7
v v or 2120 22
7360 7
v v
290 22 14360 7
v v 2120 22 7
360 7v v or equivalent
308
3 or
2102
3 or 102 7
Note :
1. Accept for K mark.2. Correct answer from incomplete working, award KK2.
K1
K1
N1
K1
K1
N1 6
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SULIT 1449/2(PP)
1449/2(PP) SULIT
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Question Solution and Mark Scheme Marks
11(a)
(b)
(c)
45915.3
30!
11 28
10
or
17
10
71
10 or 1 7
Note : Without working, award K1N1
1 1
11 28 10 11 12 11 8 4592 2
v
v v v v v ! - -
or equivalent method
Note:
1. 1 11 28 102
v v or 11 12v or 1
11 82
vv v
or equivalent, award K1
2. Accept 195 or 132 for K1
22
P1
K1
N1
K2
N1 6
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SULIT 1449/2(PP)
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1449/2(PP) SULIT
9
Question Solution and Mark Scheme Marks
12(a)
(b)
(c)(i)
(ii)
(d)
7
2
Note : Konly meant for table value.
Graph
Axes drawn in correct direction, uniform scales in 3 5 4x e e
and 8 28y
.
All 7 points and *2 points correctly plotted or curve passes
through these points for 3 5 4x
and 8 28y
.
A smooth and continuous curve without any straight line and passes
through all 9 correct points using the given scale for 3 5 4x e e .
Note : 1. 7 or 8 points correctly plotted, award K1.
2. Ignore curve out of range.
4.0 < y < 5.0
3 20 3 10x
Identify equation 2 9y x! or equivalent.
Straight line 2 9y x! correctly drawn.
Values of x : 2 65 2 55x
3 05 3 15x e e
Note : 1. Allow N marks if values of xshown on the graph.
2. Values x obtained by calculation, award N0.
K1
K1
P1
K2(does not
depend on P)
N1(depends on
P and K)
P1
P1
K1
K1
N1(dep 2nd K1)
N1(dep 2nd K1)
2
4
2
4
12
Note:
1. Allow P mark if value of x and y areshown on the graph.
2.
Value ofx and y obtained by calculation,award P0.
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SULIT 1449/2(PP)
1449/2(PP) SULIT
10
y = 2x+ 9
22 3 7y x x! v
v
v
v
v
v
vvv
2 1 O 1
20
15
10
5
5
10
2 3 4 x
25
30
y
3 4
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SULIT 1449/2(PP)
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1449/2(PP) SULIT
11
Question Solution and Mark Scheme Marks
13(a)(i) (6, 1) P2
Note: (6, 1) marked or (1, 4) seen or (1, 4) marked, award P1
(ii) (8, 5) P2 4
Note: (8, 5) marked or (3, 8) seen or (3, 8) marked, award P1
(b)(i)(a) W: Reflection in the line x = 1 P2
Note :
1. P1 : Reflection // Pantulan.
(b) V: Enlargement at centreK or (6, 10) with scale factor3
2 P3
Note :
1. P2 : Enlargement at centre Kor(2, 1) or
Enlargement scale factor3
2
2. P1 : Enlargement.
(ii) * 2388
2
v
K1
* 23
88 882
v
K1
110 N18
12
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Question Solution and Mark Scheme Marks
14(a)
(b)
Frequency : (I to VIII)
Cumulative frequency : (I to VIII)
Upper Boundary : (I to VIII)
Note: Allow one mistake in frequency for P1
* * * * * * *
* * * * * * *
( 34 5 2) ( 44 5 3) ( 54 5 8) ( 64 5 10) ( 74 5 11) ( 84 5 4) ( 94 5 2)
2 3 8 10 11 4 2
v v v v v v v
Note :
1. Allow *midpoint for K12. Allow two mistakes for the multiplication of midpoint
and*frequency, for K1
65 75
Note :
Correct answer from incomplete working, award Kk2
e.g.2630
65 7540
! (without table)
P2
P1
P1
K2
N1
4
3
Marks
Markah
Frequency
Kekerapan
Cumulative
Frequency
Kekerapan
Longgokan
Upper
Boundary
Sempadan
Atas
20 29 0 0 29.5 I
30 39 2 2 39.5 II
40 49 3 5 49.5 III
50 59 8 13 59.5 IV
60 69 10 23 69.5 V
70 79 11 34 79.5 VI
80 89 4 38 89.5 VII
90 - 99 2 40 99.5 VIII
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SULIT 1449/2(PP)
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1449/2(PP) SULIT
13
Question Solution and Mark Scheme Marks
(c)
(d)
Axes drawn in correct direction and uniform scale for
29 5 99 5x
and 0e y e 40
Note :
Do not accept wrong label
*8 points correctly plotted
Note :
*6 or
*7 points correctly plotted or curve passes through
using at least 6 correct upper boundary, award K1
Smooth and continuous curve without any straight line passesthrough 8 correct points for using given scales 29 5 99 5x
Any true statement from the ogive
Note :
Do not accept answer without an ogive
P1
K2
N1
K1
4
1
12
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SULIT 1449/2(PP)
1449/2(PP) SULIT
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0
5
10
15
20
25
30
35
40
29.5 39.5 49.5 59.5 69.5 79.5 89.5
v
Marks
Frequency
45
v
v
v
v
v
v
99.5
v
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SULIT 1449/2(PP)
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1449/2(PP) SULIT
15
Question Solution and Mark Scheme Marks
15 Note :
(1) Accept drawing only (not sketch).(2) Accept diagrams with wrong labels and ignore wrong labels.(3) Accept correct rotation of diagrams.(4) Lateral inversions are not accepted.(5) If more than 3 diagrams are drawn, award mark to the
correct ones only.
(6) For extra lines (dotted or solid) except construction lines, nomark is awarded.
(7) If other scales are used with accuracy of s 0.2 cm one way,deduct 1 mark from the N mark obtained, for each part
attempted.
(8) Accept small gaps extensions at the corners.For each part attempted :
(i) If e 0 4 cm, deduct 1 mark from the N mark obtained.
(ii) If > 0 4 cm, no N mark is awarded.
(9) If the construction lines cannot be differentiated from theactual lines:
(i) Dotted line :If outside the diagram, award the N mark.
If inside the diagram, award N0.
(ii) Solid line :
If outside the diagram, award N0.
If inside the diagram, no mark is awarded.
(10) For double lines or non-collinear or bold lines, deduct 1mark from the N mark obtained, for each part attempted.
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SULIT 1449/2(PP)
1449/2(PP) SULIT
16
Question Solution and Mark Sche me Marks
15(a)
Correct shape with pentagonABHGF
All solid lines.
BA"AF"HG >BH
Measurement correct to s 0 2 cm (one way) and all angles
at vertices of rectangles = 90rs 1r
K1
K1
dep K1
N1 dep
K1K1 3
F
G H
BA
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SULIT 1449/2(PP)
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1449/2(PP) SULIT
17
Question Solution and Mark Scheme Marks
15(b)(i)
Correct shape with rectanglesPNML, FPLG, GLJHandFPJH
All solid lines
FN >FH >HJ = FP >MN =FG >LJ = GH = LM
Measurement correct to s 0 2 cm (one way) and all angles at the
vertices of rectangles = 90rs 1r
K1
K1dep K1
N2 dep
K1K1 4
N M
L J
HGF
P
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18
Question Solution and Mark Scheme Marks
15(b)(ii)
Correct shape with rectangles QNPD andADEF
All solid lines
Note : Ignore straight lineKG
Kand G joined with dashed line to form rectanglesADKG and
GKEF
QN= QA >AF>EF=AD > KE= GF >NP= QD >
EP = AG = DK
Measurement correct to s 0 2 cm (one way) and all angles at
the vertices of rectangles = 90rs 1r
K1
K1
dep K1
K1 dep
K1K1
N2 dep
K1K1K15
12
N P
Q
GK
FE
DA
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SULIT 1449/2(PP)
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19
Question Solution and Mark Scheme Marks
16 (a)
(b)
(c)
(d)
(75rS, 100rE) // (75rS, 100rT)
Note: 1. 100rE or 100rT , award P2
2. 100r or E or T, award P1
6420
60 or 107
642075
60
32S
80 20 60 cos75 v v r or 100 60 cos75v v r
Note: 80 20 or 100 or using cos75r correctly, award K1
1552 91
180 60
550
v or equivalent
Note:
*
180 60
550
v, award K1
19 64 hours or 19 hours 38 minutes
END OF MARK SCHEME
P3
K1
K1
N1
K2
N1
K2
N1
3
3
3
3
12