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AP Statistics Survey ProjectDesiree Acevedo, Frank Palomarez, Paul
OrtizMr. Eastvedt
Period 4June 4, 2011
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Survey QuestionsO Q1 - What grade are you in?O Q2 - How old are you?O Q3 - Are you male or female?O Q4 - How many siblings do you have?O Q5 - How many people live in your
house?O Q6 - How many days of the week do you
typically get homework?O Q7 - How many pairs of jeans do you
own?
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Questions continued …. O Q8 - Which do you prefer to watch:
College Football or Professional FootballO Q9 - What type of phone do you prefer:
Touch screen or Full KeyboardO Q10 - Which do you prefer: Fast Food or
Home-made FoodO Q11 - Would you rather play videogames
or physical sports?
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Confidence Intervals for Means
Question 1: Grade level of participants
x= 9.93 s= 1.095 n= 84 df= 83 9.93 ± (T*)×(1.095/√84)
= (9.70, 10.16)O This confidence interval means that we
are 95% confident that the true mean grade level of survey participants is between 9.70 and 10.16
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Confidence Intervals for Means
Question 2: Age of participants
x= 15.27 s= 1.19 n= 84 df= 83 15.27 ± (T*)×(1.19/√84)
= (15.02, 15.53)
O This confidence interval means that we are 95% confident that the true mean age of survey participants is between 15.02 and 15.53
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Confidence Intervals for Means
Question 4: Number of siblings participants have
x= 2.63 s= 1.63 n= 84 df= 83 2.63 ± (T*)×(1.63/√84)
= (2.28, 2.98)O This confidence interval means that
we are 95% confident that the true mean of number siblings of survey participants is between 2.28 and 2.98
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Confidence Intervals for Means
Question 5: Number of people in participant’s householdx= 5.71 s= 2.39 n= 84 df= 83
5.71 ± (T*)×(2.39/√84)
= (5.20, 6.23)O This confidence interval means that we
are 95% confident that the true mean of people in the household of survey participants is between 5.20 and 6.23
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Confidence Intervals for Means
Question 6: Day of week participants typically receive homeworkx= 4.44 s= 1.13 n= 73 df= 72
4.44 ± (T*)×(1.13/√73)
= (4.17, 4.70)O This confidence interval means that
we are 95% confident that the true mean of days per week survey participants receive homework is between
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Confidence Intervals for Means
Question 7: Pairs of jeans participants own
x= 10.91 s= 12.87 n= 67 df= 66
10.91 ± (T*)×(12.87/√67)
= (7.77, 14.05)O This confidence interval means that
we are 95% confident that the true mean age of survey participants is between 7.77 and 14.05
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Confidence Intervals for Proportions
Question 3: Gender (p=female q=male) p= .548 q= .452 z*= 1.960
n= 84 .548 ± 1.960√((.548×.452)/84)
= (.442, .654)
O This means that we are 95% confident that the true proportion of affirmative participants (females) is between .442 and .654
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Confidence Intervals for Proportions
Question 8: Watching NFL vs. NCAA Football (p = prefer NFL ; q = prefer NCAA)
p= .868 q= .132 z*= 1.960 n= 76 .868 ± 1.960√((.868×.132)/76)
= (.792, .944)O This means that we are 95% confident that
the true proportion of affirmative participants (prefer watching NFL) is between .792 and .944
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Confidence Intervals for Proportions
Question 9: Touch screen vs. Full Keyboard(p= Full keyboard q= Touch screen)
p= .561 q= .439 Z*= 1.960 n= 82 .561 ± 1.960√((.561×.439)/82)
= (.454, .668)O This means that we are 95% confident
that the true proportion of affirmative participants (prefer a full keyboard cell phone) is between .454 and .668
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Confidence Intervals for Proportions
Question 10: Fast food vs. Home-made (p= Fast Food q= Home-made)
p= .296 q= .701 Z*= 1.960 n= 81 .296 ± 1.960√((.296×.701)/81)
= (.197, .396)
O This means that we are 95% confident that the true proportion of affirmative participants (prefer fast food) is between .197 and .396
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Confidence Intervals for Proportions
Question 11: Videogames vs. Physical sports
(p= Videogames q= Sports)p= .266 q= .742 Z*= 1.960 n= 79
.266 ± 1.960√((.266×.742)/79)
= (.168, .364)O This means that we are 95% confident
that the true proportion of affirmative participants (prefer playing videogames) is between .168 and .364
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Hypothesis Test: Question 6How many days of the week do you typically
get homework?“ … researchers say that American students have just the right
amount of homework.”
1. Ho: x=4.44 Ha: x≠4.44
2. Assumptions/Conditions:*Randomness-our sample was randomly selected*10%-our sample is less than 10% of the student
population*Distribution-we can assume that the sample is
randomly distributed3. We will conduct a 1 sample T-test4. p-value= .6125. With such a high p-value we cannot reject the null hypothesis. This means that we can assume that the average student receives homework about four to five days a week.
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Larger Study LinksO Question 6- http://
www.greatschools.org/students/homework-help/251-homework-is-too-much.gs
O Question 7- http://www.fashionwindows.net/2009/06/american-own-7-pairs-of-denim-jeans-on-average/
O Question 8- http://www.cbssports.com/collegefootball/story/11212751
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Males vs. Females: Question 11Would you rather play videogames or physical
sports?1. Ho: proportion of males > proportion of females (prefer playing video games) Ha: proportion of males < proportion of females (prefer playing video games)2. Assumptions/Conditions:
*Randomness-our sample was randomly selected*10%-our sample is less than 10% of the student
population*Distribution-we can assume that the sample is randomly
distributed3. We will conduct a 2-proportion Z-test4. females = .256 males = .286
p-value = .3225. With a high p-value we cannot reject the null hypothesis. This means that we can assume that the average teenage male prefers to play video games over physical sports than the average teenage female.