![Page 1: Quadratic Formula You can use this formula to find the solutions(roots) to a quadratic equation. This formula can be broken up into 2 parts: b 2 – 4ac](https://reader036.vdocuments.site/reader036/viewer/2022083010/5697bfaf1a28abf838c9d17d/html5/thumbnails/1.jpg)
Quadratic Formula
You can use this formula to find the solutions(roots) to a quadratic equation.
2 4
2
b b ac
a
This formula can be broken up into 2 parts:
b2 – 4ac is called the Discriminant. It can tell you what the roots look like.
![Page 2: Quadratic Formula You can use this formula to find the solutions(roots) to a quadratic equation. This formula can be broken up into 2 parts: b 2 – 4ac](https://reader036.vdocuments.site/reader036/viewer/2022083010/5697bfaf1a28abf838c9d17d/html5/thumbnails/2.jpg)
![Page 3: Quadratic Formula You can use this formula to find the solutions(roots) to a quadratic equation. This formula can be broken up into 2 parts: b 2 – 4ac](https://reader036.vdocuments.site/reader036/viewer/2022083010/5697bfaf1a28abf838c9d17d/html5/thumbnails/3.jpg)
Find the Discriminant and describe the type of roots:y = 3x2 + 5x – 4
a = 3b = 5 c = -4
(5)2 – 4(3)(-4) =25 + 48 =73
2 real roots
Practice finding the discriminant 5x2 + 20x + 21 = 0
![Page 4: Quadratic Formula You can use this formula to find the solutions(roots) to a quadratic equation. This formula can be broken up into 2 parts: b 2 – 4ac](https://reader036.vdocuments.site/reader036/viewer/2022083010/5697bfaf1a28abf838c9d17d/html5/thumbnails/4.jpg)
Quadratic Formula
You can use this formula to find the solutions(roots) to a quadratic equation.
2 4
2
b b ac
a
This formula can be broken up into 2 parts:
b2 – 4ac is called the Discriminant. It can tell you what the roots look like.
![Page 5: Quadratic Formula You can use this formula to find the solutions(roots) to a quadratic equation. This formula can be broken up into 2 parts: b 2 – 4ac](https://reader036.vdocuments.site/reader036/viewer/2022083010/5697bfaf1a28abf838c9d17d/html5/thumbnails/5.jpg)
Find the Discriminant and and solve for the roots:y = 3x2 + 5x – 4
a = 3b = 5 c = -4
(5)2 – 4(3)(-4) =25 + 48 =73
2 real roots
5 73 5 73
2 3 6 6
![Page 6: Quadratic Formula You can use this formula to find the solutions(roots) to a quadratic equation. This formula can be broken up into 2 parts: b 2 – 4ac](https://reader036.vdocuments.site/reader036/viewer/2022083010/5697bfaf1a28abf838c9d17d/html5/thumbnails/6.jpg)
Solving the roots:y = 2x2 – 3x + 6
a = 2b = -3c = 6
9 – 48 =- 39
3 39
4
3 39
4 4i
Practice solving: 3 – 8v – 5v2 = 2v s2 – s – 3 = s