Physics 1A, Section 7
October 15, 2007
Reminders
• Homework #2 due Wednesday 4 PM
• Quiz #1 due Thursday noon, box outside 110 E. Bridge
OM Chapter 4
OM Chapter 4
OM Chapter 4
Circular Motion
• a = v2/r(At least two ways to show that.)
• v = r
Quiz Problem 19
Quiz Problem 19
• Answer:a) t = 2 (tan - tan) cos2 v0
2 / g
Quiz Problem 26
Quiz Problem 26
• Answer:a) 10.3 m
b) 2.04 s
c) 4.97 m/s2
d) ball, by 7.2 m/s
e) 2.27 sec
OM, Problem 4-55
OM, Problem 4-55
OM, Problem 4-55
• Answer: maximum height = R + R/2[Rg/u2 + u2/Rg]
(for u2 ≥ Rg)
specific case: u = 30 km/h, R = 0.80 m, g = 9.80 m/s2 4.39 m
Thursday, October 18:
• Quiz Problem 36, part (a)
• OM, Chapter 5, Problem 55
• Quiz Problem 37
• Optional to work on these in advance.
Quiz Problem 34
Quiz Problem 34
• Answer:a) vi = -sqrt[2gL/(1-e2)]
b) ti = sqrt[2L(1+e)/(g(1-e))]
c) h = Le2/(1-e2)