10000
T entrada °F 80°Brix iniciales 15°Brix finales 30
0.91
Duhring 212
Balance de materia
F=L+V10000=L+VFxf =Lxl + Vyv10000(0,15)=L(0,30)+V(0)
L= ((10000*0,15)/0,30)L= 5000 Lbm/h
Despejamos VF-L=V10000-5000=5000V= 5000Lbm/h
240°F
214°F
Alimentacion lbm/h
Cp alimentacion btu/lbm °F
Despejamos L asi
Fhf+Shs=Lhl +VHv1000(0,91)(80-214)+S(952,3)=5000(0)+5000(971,2)S=6380
A= 667 pie2
g=6,380(952,3)=(350 btu/h pie2 °F *A*(∆T K)
Tv Saturado °F 240 Area ?
U btu/h pie2 °F 350 Consumo de vapor ?
Balance de energia
Correccion de T
°F=3,2x + 11,2 X^2°F=3,2(0,30)+ 11,2 (0,30)^2°F=1,968
T1=212+1,968T1=213,968
EntoncesEPE = 214-212
hf=cpF(TF-T1) EPE = 2hf=0,90(80-213,968)hf=-121,91 Calor latente 240°F 952,3 BTU/lb
hfg=952,171 BTU/lb Calor latente 212°F 970,3 BTU/lb
hfg=968.929 BTU/lb ∆T = 0,45
Hv= 971,2
Fhf+Shs=Lhl +VHv1000(0,91)(80-214)+S(952,3)=5000(0)+5000(971,2)
Hv= Calor Latente + 2∆T
g=6,380(952,3)=(350 btu/h pie2 °F *A*(∆T K)