Copyright © 2011 Pearson Education, Inc. Slide 6.1-1
Copyright © 2011 Pearson Education, Inc. Slide 6.1-2
Chapter 6: Analytic Geometry
6.1 Circles and Parabolas
6.2 Ellipses and Hyperbolas
6.3 Summary of the Conic Sections
6.4 Parametric Equations
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6.1 Circles and Parabolas
• Conic Sections– Parabolas, circles, ellipses, hyperbolas
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• A circle with center (h, k) and radius r has length to some point (x, y)
on the circle. • Squaring both sides yields the center-radius
form of the equation of a circle.
6.1 Circles
A circle is a set of points in a plane that are equidistant from a fixed point. The distance is called the radius of the circle, and the fixed point is called the center.
22 )()( kyhxr
22 )()( kyhxr 2
Copyright © 2011 Pearson Education, Inc. Slide 6.1-5
Notice that a circle is the graph of a relation that is
not a function, since it does not pass the vertical line
test.
6.1 Center-Radius Form of the Equation of a Circle
The center-radius form of the equation of a circle with center (h, k) and radius r is
. 2 2( ) ( ) 2x h y k r
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6.1 Finding the Equation of a Circle
Example Find the center-radius form of the equation of a circle with radius 6 and center (–3, 4). Graph the circle and give the domain and range of the relation.
Solution Substitute h = –3, k = 4, and r = 6 into the equation of a circle.
22
222
)4()3(36
)4())3((6
yx
yx
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6.1 Equation of a Circle with Center at the Origin
A circle with center (0, 0) and radius r has equation
. 2 2 2x y r
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6.1 Graphing Circles with the Graphing Calculator
Example Use the graphing calculator to graph the circle in a square viewing window.
Solution
922 yx
.9 and 9Let
9
9
9
22
21
2
22
22
xyxy
xy
xy
yx
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6.1 Graphing Circles with the Graphing Calculator
• TECHNOLOGY NOTES:– Graphs in a nondecimal window may not be
connected.
– Graphs in a rectangular (non-square) window look like an ellipse.
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6.1 General Form of the Equation of a Circle
For real numbers c, d, and e, the equation
can have a graph that is a circle, a point, or is empty.
22x y cx dy e 0
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6.1 Finding the Center and Radius of a Circle
Example Find the center and radius of the circle with equation
Solution Our goal is to obtain an equivalent equation of the formWe complete the square in both x and y.
2 26 10 25 0.x x y y
.)()( 222 kyhxr
2 2
2 2
2 2
2 2 2
6 10 25
( 6 9) ( 10 25) 25 9 25
( 3) ( 5) 9
( 3) ( 2) 3
x x y y
x x y y
x y
x y
The circle has center (3, –2) with radius 3.
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6.1 Equations and Graphs of Parabolas
• For example, let the directrix be the line y = –c and the focus be the point F with coordinates (0, c).
A parabola is a set of points in a plane equidistant from a fixed point and a fixed line. The fixed point is called the focus, and the fixed line the directrix, of the parabola.
Copyright © 2011 Pearson Education, Inc. Slide 6.1-13
6.1 Equations and Graphs of Parabolas
• To get the equation of the set of points that are the same distance from the line y = –c and the point (0, c), choose a point P(x, y) on the parabola. The distance from the focus, F, to P, and the point on the directrix, D, to P, must have the same length.
cyxcycycycyx
cycycycyx
cyxxcyx
DPdFPd
422
22
))(()()()0(
),(),(
2
22222
22222
2222
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6.1 Parabola with a Vertical Axis
and Vertex (0, 0)
• The focal chord through the focus and perpendicular to the axis of symmetry of a parabola has length |4c|.– Let y = c and solve for x.
The endpoints of the chord are ( x, c), so the length is |4c|.
The parabola with focus (0, c) and directrix y = –c has equation x2 = 4cy. The parabola has vertex (0, 0), vertical axis x = 0, and opens upward if c > 0 or downward if c < 0.
c cxcx
cyx
2or 24
422
2
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6.1 Parabola with a Horizontal Axis
and Vertex (0, 0)
• Note: a parabola with a horizontal axis is not a function.
• The graph can be obtained using a graphing calculator by solving y2 = 4cx for y:
Let and graph each half of the parabola.
The parabola with focus (c, 0) and directrix x = –c has equation y2 = 4cx. The parabola has vertex (0, 0),
horizontal axis y = 0, and opens to the right if c > 0 or to the left if c < 0.
.2 cxy cxycxy 2 and 2 21
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6.1 Determining Information about Parabolas from Equations
Example Find the focus, directrix, vertex, and axis
of each parabola.(a)
Solution(a)
xyyx 28 (b)8 22
284
cc
Since the x-term is squared, the parabola is vertical, with focus at (0, c) = (0, 2) and directrix y = –2. The vertex is (0, 0), and the axis is the y-axis.
Copyright © 2011 Pearson Education, Inc. Slide 6.1-17
6.1 Determining Information about Parabolas from Equations
(b)
The parabola is horizontal, with focus (–7, 0), directrix x = 7, vertex (0, 0), and x-axis as axis of the parabola. Since c is negative, the graph opens to the left.
7284
cc
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6.1 Translations of Parabolas
A parabola with vertex (h, k) has an equation of the form
or
where the focus is a distance |c| from the vertex.
24x h c y k
24y k c x h
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6.1 Writing Equations of Parabolas
Example Write an equation for the parabola with vertex (1, 3) and focus (–1, 3).
Solution Focus lies left of the vertex implies theparabola has
- a horizontal axis, and- opens to the left.
Distance between vertex and focus is 1–(–1) = 2, so c = –2.
)1(8)3()1)(2(4)3(
2
2
xyxy
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6.1 An Application of Parabolas
Example The Parkes radio tele-scope has a parabolic dish shape with diameter 210 feet and depth 32 feet. Because of this parabolic shape, distant rays hitting the dish are reflected directly toward the focus.
Copyright © 2011 Pearson Education, Inc. Slide 6.1-21
6.1 An Application of Parabolas
(a) Determine an equation describing the cross section.(b) The receiver must be placed at the focus of the parabola.
How far from the vertex of the parabolic dish should the receiver be placed?
Solution(a) The parabola will have the form y = ax2 (vertex at the
origin) and pass through the point ).32,105(32,2210
2
2
2
32 (105)32 32
The cross section can be described by105 11,025
32.
11,025
a
a
y x
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6.1 An Application of Parabolas
(b) Since
The receiver should be placed at (0, 86.1), or 86.1 feet above the vertex.
,025,11
32 2xy
.1.86128
025,1132025,11
4
14
c
c
ac