Download - Calculation of detector acceptance for measuring muon lifetime in MuSIC beam test by GEANT4
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CALCULATION OF DETECTOR ACCEPTANCE FOR MEASURING MUON LIFETIME IN MUSIC BEAM TEST BY GEANT4
Kuno-Group D1Nguyen Duy Thong
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OUTLINE Introduction Results Summary
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INTRODUCTIONMuSIC facility
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The process in MuSIC facility: At first, protons are accelerated in the
MuSIC facility. Then, they will impact with a target to
produce p+ or p–. m+, m– are emitted in p+, p– in the decay
process. Last, particles will be detected by
detector.
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proton
targetpion
muon
detector
Particles (m+, m–) are detected by a detector with 2 scintillators and 1 target.
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The detector consists of 2 scintillators and 1 target. 2 scintillators have
same size 380x50x3.5 mm3
Target is made of Mg. The size of target: 370x80x20mm3
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In this study, by using Geant4 simulation:
First, without using dipole magnetic-field(By=0T), the acceptance of detector is determined.
Using dipole magnetic-field (By = ±0.04T), evaluate the acceptances of detector.
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MOTIVATION Evaluate efficiency of muon between
beamline and captured muon. Consider about detector acceptance.
Detector acceptance is defined as ratio between number of detected e+ or e– and number of incident m+ or m–at detector.
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RESULTS For By=0T,
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0.1mA-proton beam impacts with target, from Geant4, some results were calculatedBeamline Sci 1 Sci 2
p + 4949 663 187
p ー 1249 130 38
m + 10128 1530 352
m ー 2024 277 68
e + 0 335 212
e ー 0 335 329The efficiency of m
€
effμ + =
number of detected at Sci1 μ +
number of beamline μ + =153010128
≈ 0.151 =15.1%
€
effμ − =
number of detected at Sci1 μ -
number of beamline μ − =277
2024≈ 0.1369 ≈13.7%
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The detector acceptance
€
P μ + →e+( ) =number of detected e+ at Sci1 and Sci2
number of beamline μ + =335 + 212
10128≈ 0.054 = 5.4%
€
P μ − →e−( ) =number of detected e- at Sci1 and Sci2
number of beamline μ − =335 + 329
2024≈ 0.328 = 32.8%
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For By=+0.04TBeamline Sci 1 Sci 2
p + 1957 222 46
p ー 1550 315 125
m + 5461 690 149
m ー 2306 402 131
e + 0 441 274
e ー 0 382 219The efficiency of m
€
effμ + =
number of detected at Sci1 μ +
number of beamline μ + =6905461
≈ 0.1264 =12.64%
€
effμ − =
number of detected at Sci1 μ -
number of beamline μ − =402
2306≈ 0.1743 =17.43%
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The detector acceptance
€
P μ + →e+( ) =number of detected e+ at Sci1 and Sci2
number of beamline μ + =441+ 274
5461≈ 0.1309 =13.09%
€
P μ − →e−( ) =number of detected e- at Sci1 and Sci2
number of beamline μ − =382 + 219
2306≈ 0.2606 = 26.06%
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For By=–0.04TBeamline Sci 1 Sci 2
p + 7745 1232 400
p ー 545 57 10
m + 13073 2158 564
m ー 1248 139 26
e + 0 1269 847
e ー 0 709 363The efficiency of m
€
effμ + =
number of detected at Sci1 μ +
number of beamline μ + =2158
13073≈ 0.165 =16.5%
€
effμ − =
number of detected at Sci1 μ -
number of beamline μ − =1391248
≈ 0.1113 =11.13%
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The detector acceptance
€
P μ + →e+( ) =number of detected e+ at Sci1 and Sci2
number of beamline μ + =1269 + 847
13073≈ 0.1618 ≈16.18%
€
P μ − →e−( ) =number of detected e- at Sci1 and Sci2
number of beamline μ − =709 + 363
1248≈ 0.859 ≈ 85.9%
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SUMMARY In this research, with 0.1mA-proton beam,
numbers of p+,p–,m+,m–,e+,e ー were estimated The detector acceptances were calculated.
Next step• Some features need to be improved to ensure simulation better.
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THANK YOU FOR YOUR ATTENTION
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BACKUP
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By = 0T Beamline Sci 1 Stop at Sci1
Sci 2 Stop at Sci2
p + 4949 663 44 187 34
p ー 1249 130 16 38 7
m + 10128 1530 444 352 73
m ー 2024 277 43 68 12
e + 0 335 16 212 5
e ー 0 335 0 329 0
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By=+0.04T
Beamline Sci 1 Stop at Sci 1
Sci 2 Stop at Sci 2
p + 1957 222 16 46 13
p ー 1550 315 9 125 10
m + 5461 690 188 149 36
m ー 2306 402 50 131 11
e + 0 441 4 274 3
e ー 0 382 0 219 0
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By= ー 0.04TBeamline Sci 1 Stop at
Sci1Sci 2 Stop at
Sci 2
p + 7745 1232 73 400 27
p ー 545 57 4 10 1
m + 13073 2158 496 564 90
m ー 1248 139 34 26 2
e + 0 1269 14 847 9
e ー 0 709 0 363 0