Transcript
  • :

    : -13

    : 2013-2014

    . http://study.eap.gr

    :

    21 2014

    ( 21 2014) (0,5 ). 7 .

  • 4 :

    1. Word 1 - 4 ( : Eponymo.Onoma-GE2.doc).

    , . ,

    Excel

    .

    2. Excel Excel (

    : Eponymo.Onoma-GE2.xls). Excel

    Excel.

    . .. 3-, 4 .

    . 13

    .

    Excel Excel. T word.

    (Equation Editor) Word ( : Insert Object Object type Microsoft Equation 3.0 :

    Microsoft Equation 3.0).

    (Equation Editor)

    .

    CD Microsoft Office. Equation

    Editor / (. 68-71), 13

    (http://class.eap.gr/deo13) :

    Egxeiridio H-Y.pdf.

  • 1 [20 (5+5+5+5)]

    [ ] (15 (5+5+5)) : QP 35,152 =

    : QQQVC 175155,0 23 +=

    300=FC .

    () TC, TR . (5 )

    () Q . (5 )

    () MC R. Q

    . ; (5 )

    [ ] (5 ) 3 3,30 . 2000 . :

    1) 5,0= .

    2) 1= .

    3) 2= .

    (5 )

    1 -

    [ ]

    ()

    :

    TC= VC+FC= 321 Q -15Q2+175Q+300

  • :

    TR= PQ=(152,5-3Q)Q=152,5 Q - 3Q2

    :

    =TR-TC=152,5Q-3Q2-( 321 Q -15Q2+175Q+300)= - 3

    21 Q +12Q2-22,5Q - 300

    ()

    1

    = 5,222423 2 + QQ

    2

    = 2432426

    +=+ QQ

    =0 5,222423 2 + QQ =0 Q=15 Q=1

    =0 2

    Q=1 (1)=-3*1+24=21>0 .

    Q=15 (15)=-3*15+24=-21

  • : MR C Q* . : (Q)=TR(Q)-TC(Q),

    (Q)=TR(Q)-TC(Q)=MR(Q)-MC(Q) Q*

    (Q*)=0.

    [ ]

    Q1=2000 P1=3.

    TR1=P1 x Q1=3x2000=6000.

    H PdPQdQ

    PQ //

    , =112

    112

    /)(/)(PPPQQQ

    =

    1) 5,0= 3/)330,3(

    2000/)2000(5,0 2

    =

    Q

    1900)05,0(200020002000

    200010,0)5,0( 22 =+=

    = QQ

    TR2=P2 x Q2=3,30x1900=6270 .

    : 10%

    10%

    .

    2) 1= 3/)330,3(

    2000/)2000(1 2

    =

    Q

    1800)10,0(200020002000

    200010,0)1( 22 =+=

    = QQ

    TR2=P2 x Q2=3,30x1800=5940 .

    : 10%

    10% .

    3) 2= 3/)330,3(

    2000/)2000(2 2

    =

    Q

    1600)20,0(200020002000

    200010,0)2( 22 =+=

    = QQ

  • TR2=P2 x Q2=3,30x1600=5280 .

    : 10%

    10% .

    2 [25 (3+5+5+7+5)]

    962 ++= QQPs

    25102 += QQPd .

    () Ps, Pd Excel Q 0 6,5

    0,25. Q . (3

    )

    () Ps Pd Ps>0 Ps , Pd>0 Pd . (5 )

    () . (5 )

    () Pd Q 10%. (7 ) (E) (). (5 )

    (:

    ( Q P ),

    ,

    .

    Q.)

  • 2 -

    ()

    Q Ps Pd 0 9 25

    0,25 10,5625 22,5625 0,5 12,25 20,25

    0,75 14,0625 18,0625 1 16 16

    1,25 18,0625 14,0625 1,5 20,25 12,25

    1,75 22,5625 10,5625 2 25 9

    2,25 27,5625 7,5625 2,5 30,25 6,25

    2,75 33,0625 5,0625 3 36 4

    3,25 39,0625 3,0625 3,5 42,25 2,25

    3,75 45,5625 1,5625 4 49 1

    4,25 52,5625 0,5625 4,5 56,25 0,25

    4,75 60,0625 0,0625 5 64 0

    5,25 68,0625 0,0625 5,5 72,25 0,25

    5,75 76,5625 0,5625 6 81 1

    6,25 85,5625 1,5625 6,5 90,25 2,25

    P

    A B

    C

    Q

  • ()

    Q

    . : (i) 0Q , (ii) 0>sP

    0>dP (iii) , 0'sP

    , 0'dP .

    (i) (ii)

    1 . (ii), 22 )3(96 +=++= QQQPs 0>sP 0Q . ,

    22 )5(2510 =+= QQQPd 0>dP

    5Q . (i) (ii) 0Q 5Q .

    (iii) : Ps Ps=2Q+6 0Q

    0'sP .

    Pd Pd=2Q-10. 0'dP 50102 QQ .

    , (i),

    (ii) (iii) 50

  • ()

    Ps Pd Ps = Pd Q=1.

    .

    Ps = Pd Q2+6Q+9 = Q2-10Q+25 6Q+9 = -10Q+2516Q= 16Q=1

    Q=1 = 12+6*1+9=16

    ()

    Q 10% 10 =Q 10,11 =Q .

    10,11 =Q 21,1525)10,1(1010,12

    1, =+=dP

    ( : 05,0049375,016/)1621,15(/)( 0,0,1, == ddd PPP .

    dP 5%.)

    . ( ,

    .)

    Pd (

    ) (Q=1,

    P=16)

    2510102

    2510)102( 2

    2

    2 +

    =+

    ==QQ

    QQQQ

    QQPQ

    dQdP

    d

    dd

    Q=1 5,016

    825110111012

    2

    2

    =

    =+

    =d

    Q 10% Pd

    (0,5x10)%=5%.

    :

    . (dy/dx)

    y/x=(y2-y1)/(x2-x1).

  • ()

    Q=1 :

    33,202521)10(

    31]25

    210

    3[)2510( 10

    2321

    0=+=+=+ Q

    QQdQQQ

    :

    =20,33-(1x16)=4,33

    (1x16)= =Q x P.

    3 [25 (6+6+6+7)]

    MR : 216100)( QQQMR += Q . ,

    23650)( QQQMC += .

    , () 0=FC

    .

    .

    () N TC, AC. (6 )

    () N TR Pd ( Q) . (6 )

    () N Q

    . (6 )

    () N Q . EXCEL,

    TC, TR,

    Q 0 13 0,5. (7 )

  • 3

    ()

    TC TR MC MR :

    ++=+== CQQQdQQQdQQMCTC3

    32

    650)3650()(32

    2 .

    :

    00)0(0 === CTCFC . QQQTC 503 23 += .

    5032 +== QQQ

    TCAC

    ()

    :

    ++=+== cQQQdQQQdQQMRTR32

    16100)16100()(32

    2 00)0( == cTR .

    32

    318100 QQQTR += .

    QPTR = , (

    ) . ,

    232

    318100)3/1(8100 QQP

    QQQQ

    QTRP dd +=

    +== .

    ()

    : )503(1008)3/1( 2323 QQQQQQTCTR +++== .

    QQQ 5011)3/4( 23 ++=

    0ddQ

    = 2

    2 0ddQ

    < .

  • 20 50 22 4 0d Q QdQ

    = + =

    Q1 = 7,23 Q2 = -1,73. ,

    Q1 = 7,23 Q2 = -1,73 . ,

    Q1 = 7,23 :

    084,35)23,7(82282222

  • 4 [30 (8+6+6+5+5)]

    ) :

    1) 752

    )( += xexf

    2) 423 )75(2)( += xxxf

    3) )75ln()( 2 += xxf

    4) 3253

    )21()4()(

    xxxf+

    =

    (8 ) B) :

    (5) 10)25()( = xxf

    (6) )25(

    1)(

    =x

    xf

    (7) )25()( = xexf

    (: ) (6 )

    ) :

    8) + dxexx x)52( 2

    9) dxxx )ln( (: ) (6 )

    ) :

    10) 4

    0)2( dxxx

    11)

    1

    20)

    313( dxxe x

    (5 ) ) :

    12) 4432)( 234 ++= xxxxxf ,

    (5 ) 4)

  • 1) u=5x2+7 y=eu .

    dxdu

    dudy

    dxdy

    = = 752

    )10(10 += xu exxe

    2) . u=5x2+7 z=2x3 y=z u-4 .

    22 632)'( xxdxdzz ===

    )10()75(4)52()4()()()'( 52544

    4 xxxudxdu

    duud

    dxudu

    +==== .

    :

    =+= )'()()'( 44 uzuzdxdy )10]()75(4)[2()75)(6( 523422 xxxxx +++ =

    = 5224

    52

    422

    52

    4

    42

    2

    )75(4250

    )75(80)75(6

    )75(80

    )75(6

    ++

    =+

    +=

    +

    + xxx

    xxxx

    xx

    xx .

    3) u=5x2+7 y=ln(u).

    dxdu

    dudy

    dxdy

    = =75

    10)10(1 2 +=

    xxx

    u

    4)

    62225332243

    )21()4()21(3)4()21(3)4(5

    xxxxxxx

    dxdy

    ++

    =

    42

    3243

    )21()]4)(4()21(5[3)4(

    xxxxxx

    ++

    = 42343

    )21(]1656[)4(3

    xxxxx

    +++

    =

    4) 5) u=5x-2

    dxu 10

  • dx du du=d(5x-2)=5dx dx=51 du .

    dxu 10 = CxCuduu +=+= 55

    )25(115

    151 111110

    6) u=5x-2

    dxu1

    dx du du=d(5x-2)=5dx dx=51 du .

    dxu1 = cxcudu

    u+=+= 25ln5

    1ln511

    51

    7) u=5x-2

    ceceduedxe xuuu +=+== 2551

    51

    51

    4) 8)

    ( )2 2 5 xx x e dx + =

    ( ) ( )2 2 5 2 1x xe x x x e dx = + +

    ( ) ( ) 11 1x x x x x x xx e d xe x e d xxe e e c xe c = + = + + = +

    ( )2 2 5 xx x e dx + = ( ) ( )2 22 5 2 5x x xe x x xe c e x c + + = + +

    9)

  • 2 2 2 2 2 1ln ln ln ln2 2 2 2 2x x x x xxlnxdx xd x d x x dx

    x= = = =

    2 2 2 21 1 1ln ln ln2 2 2 2 2 2 2x x x xx xdx x c x c = = + = +

    4) 10)

    ==

    == 2/32/5

    4

    0

    2/32/54

    0

    2/12/34

    04

    344

    52

    2/32

    2/5)2()2( xxdxxxdxxx

    1532

    152523

    324

    52)4(

    34)4(

    52 563632/152/1 ====

    11)

    )20ln(31)(3|]20|ln|1|[ln

    31][31

    313)

    313( 201201

    1

    20

    1

    20

    1

    20+===

    eeeedxxdxedxxex

    x

    4) 12)

    4432)( 234 ++= xxxxxf

    :

    3 2( ) 4 6 6 4f x x x x = +

    :

    =+++=+=+ )1(6)1)(1(4)1(6)1(44664 2323 xxxxxxxxxxx

    )252)(1(2]3)1(2)[1(2 22 ++=+++ xxxxxxx

    -2, 12

    1.

    :

    ( ) ( )2 212 12 6 6 2 2 1f x x x x x = + = +

  • -2, 12

    1:

    ( )2 18 0f = > -2 .

    ( ) ( ) ( ) ( )4 3 2( 2 ) 2 2 2 3 2 4 2 4f = + + = 0

    1 9 02

    f = 1 .

    04)1(4)1(3)1(2)1()1( 234 =++=f .

    : : -13


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