double integrals

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intermadiate analysis double integral section

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  • 15.3 Double Integrals over General Region

    Evaluating Double Integrals over General (Non-Rectangular) Regions

    We will consider two types of regions

    1

    Type I region

    A region bounded by

    the lines ,x a x b= = and

    the curves 1 2( ), ( )y g x y g x= = with [ ]1 2( ) ( ) ,g x g x x a b

    Type I region is

    1 2{( , ) : , ( ) ( )VR x y a x b g x y g x=

    2 ( )y g x=

    1( )y g x= X

    Type II region

    A region bounded by

    the lines ,y c y d= = and

    the curves 1 2( ), ( )x h y x h y= = with [ ]1 2( ) ( ) ,h y h y y c d

    Type II region is

    1 2{( , ) : , ( ) ( )}HR x y c y d h y x h y=

    x = a x = b

    X

    Y

    2 ( )x h y=

    y c=

    y d=

    1( )x h y=

    R

    R

  • 2

    If R is type I then

    2

    1

    ( )

    ( )( , ) ( , )

    b g x

    a g xR

    f x y dA f x y dydx= If R is type II then

    2

    1

    ( )

    ( )( , ) ( , )

    d h y

    c h yR

    f x y dA f x y dxdy=

    Step 2. Move the line left and then right. Leftmost position where the line intersects the

    region R is x a= which is lower limit of the outer integral. Rightmost position where the line intersects the region R is x b= which is the upper limit of the outer integral.

    Find limit of Integrats for type II region R

    Step 1. Draw a horizontal line through the region R at an arbitrary fixed value y. This

    line intersects the region left at the curve 1( )y h x= and right at the curve . 2 ( )y h x=Then is the lower limit and 1( )y h x= 1( )y h x= is the upper limit of the inner integral.

    Step 2. Move the line down and then up. Lowest position where the line intersects the

    region R is which is lower limit of the outer integral. Highest position where the

    line intersects the region R is which is the upper limit of the outer integral.

    y c=y d=

    Step 1. Draw a vertical line through the region R at an arbitrary fixed value x. This line

    intersects the region below at the curve 1( )y g x= and above at the curve . 2 ( )y g x=Then is the lower limit and 1( )y g x= 1( )y g x= is the upper limit of the inner integral.

    Find limit of Integrals for type I region R

    Double integrals over both regions

    evaluated as iterated integrals

  • Important points to note:

    Outer limits always constant The idea of using a vertical line as explained in class Sometimes need to break into more integrals.

    Question 5/1002: Evaluate /2 cos

    sin

    0 0

    e drd

    .

    Question 9/1002: Evaluate the double integral 22

    1R

    y dAx +

    where {( , ) : 0 1,0 }R x y x y x= .

    Question 17/1002: Evaluate the double integral (2 )R

    x y dA ; R is bounded by the circle with center the origin and radius 2.

    Question 22/1002: Use double integral to find the volume of the solidenclosed by

    the paraboloid 2 3 2z x y= + and the plane 0, 1, , 0x y y x z= = = = .

    3

  • 4

    2

    Question 28/1002: Find the volume of the region bounded by the cylinders

    2 2x y r+ = and 2 2 2y z r+ = .

    Question 42/1003: Sketch the region of integration and change the order of the

    integration 1 /4

    0 arctan

    ( , )f x y dydx

    .

    Question 48/1003: Evaluate the integral 4

    3

    8 2

    0

    x

    y

    e dxdy by reversing the order of integration.