Photons in a permutation anti-symmetric state?

and

What would a quantum-statistic violation mean?

Dmitry Budkerhttp://socrates.berkeley.edu/~budker

Inauguration MeetingIceland, July 2007

Support: N$F

Identical particles: the ultimate equality

• Permutation symmetry postulate

• Spin-Statistics Theorem (SST)

Individualism: the ultimate diversity

Prof. Richard P. Feynman(1918-1988)

Feynman’s Lectures on Physics, V. 3:

Okun’ on Pauli

How? Landau-Yang Theorem!Landau, L. D., Dokl. Akad. Nauk., USSR 60, 207-

209 (1948)

Doesn’t go because no symmetric statefor two photons with J=1

Landau-Yang theorem and the Landau-Yang theorem and the degenerate two-photon transition degenerate two-photon transition

selection ruleselection rule • L-Y:L-Y: V(J=1) V(J=1)

• Inverse L-Y:Inverse L-Y: Nothing(J=0) + Nothing(J=0) + V(J=1) V(J=1)

MJ=0MJ=-1 MJ=1

1

1

2

2

Destructive interference of two quantum paths

S. N. Bose

DeMille 11999

Interaction region

Lasers

Results

Results

Numbers

Damon English

Disturbing Questions

• No consistent relativistic theory accommodating a statistics violation

• How to compare with other experiments? (Z→γγ, …)

• Constrains from lasers, BBR, static limit ?

Need a generalized E&M theory