diodos bjt-
DESCRIPTION
Presentacion estudiante de CIDETRANSCRIPT
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DIODOS YTRANSISTORES BJT
SEMICONDUCTORES
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BJT: BASE COMUNIE= IB + IC IC= IE
VBE =0.7V IC/IE= α
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EMISOR COMUN
IC=(β+1)IB
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CURVAS DE SALIDA
PUNTO Q
ΔIC
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COLECTOR COMUN
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IDENTIFICACION DE TERMINALES
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REGIONES DE OPERACIONLINEAL:
1. B-E DIRECTA (0.6 O 0.7)
2. B-E INVERSA. (HOJA)
CORTE:
1. B-E INVERSA
SATURACION:
1.B-E DIRECTA
2. B-C DIRECTA
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POLARIZACION FIJAVcc
C1
C2RB RC
Malla B-E Malla C-E
Señalentrada
Señalsalida
VCE = VC-VE
VBE = VB - VEIcsat= VCC/RC
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EJERCICIO Determinar: IB, VCE, VB, VC Y VBC
β = 60
Ic =βIb
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ANALISIS DE RECTA DE CARGAVCE= VCC – IC*RC
Q
HALLAR VCC, RC Y RB PARA EL PUNTO Q MOSTRADO.
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CIRCUITO DE POLARIZACION ESTABILIZADO EN EMISOR
Vcc
RbRc
Re
C1
C2
Malla EBIe=(β+ 1)Ib
Malla CEIe=Ic
Ve: Vc: Vb: Vce:
Icsat= Vcc/(Rc+Re)
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EJERCICIO
Calcule: Ib, Ic, Vce, Vc, Ve, Vb, Vbc
β = 60
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POLARIZACION POR DIVISOR DE VOLTAJE
Vcc
R1
R2
C1
C2 Rc
Re Vcc
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ANÁLISIS EXACTO
Vcc
Re R1
R1
Hallar equivalente thevenin, dibujar nuevamente el circuito , aplicar Kirchhoff, se sustituye IE y se despeja Ib, se analiza malla CE como ya se estudio.
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Determinar Vce e Ic
EJERCICIO
β = 120
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ANÁLISIS APROXIMADO
Vcc
Ri R2
R1
Ri>>R2; Ib=0
R1 y R2 en serie, VR2=Vb.β Re≥ 10R2
Ve = Vb –VbeIe= Ve/ReIe=IcVce= Vcc-IcRc-IeRe
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ACTIVIDAD DE INVESTIGACION Realice un trabajo a mano, donde deje ver
las características de cada una de las polarizaciones del BJT estudiadas en clase, ventajas, desventajas, aplicaciones.
Desarrolle tres ejercicios para cada una de las polarizaciones vistas.
Investigue en que consiste la polarización de DC por retroalimentación de voltaje, tenga en cuenta los literales anteriores.