dimensioning of mobile data - non-uniform usage ... 2016... · cell planning and re-use 1 2 33 2 2...

21
1 1 Dimensioning of mobile data - Non-uniform usage Dimensioning of voice services (Thanks to Claes Beckman) Jan Markendahl December 12, 2016 2 Time Time 00:00 01:00 02:00 03:00 04:00 05:00 06:00 07:00 08:00 09:00 10:00 11:00 12:00 13:00 14:00 15:00 16:00 17:00 18:00 19:00 20:00 21:00 22:00 23:00 Time Call Attempts

Upload: buidang

Post on 24-Jun-2018

216 views

Category:

Documents


0 download

TRANSCRIPT

1

1

Dimensioning of mobile data- Non-uniform usage

Dimensioning of voice services(Thanks to Claes Beckman)

Jan MarkendahlDecember 12, 2016

2

TimeTime

00:0

0

01:0

0

02:0

0

03:0

0

04:0

0

05:0

0

06:0

0

07:0

0

08:0

0

09:0

0

10:0

0

11:0

0

12:0

0

13:0

0

14:0

0

15:

00

16:0

0

17:0

0

18:0

0

19:0

0

20:0

0

21:0

0

22:0

0

23:0

0

Time

Cal

l Att

empt

s

2

3

Today

• Dimensioning not assuming uniform usage• Non uniform usage profile• Conditions set by bit rates• Erlang type of dimensioning• Criticism of simple ”HW3” model

• Capacity of a cell• System bandwidth• Spectral efficiency• Spectral reuse

4

Today

• Dimensioning not assuming uniform usage• Non uniform usage profile• Conditions set by bit rates• Erlang type of dimensioning• Criticism of simple ”HW3” model

• Capacity of a cell• System bandwidth• Spectral efficiency• Spectral reuse

3

5

Capacity dimensioning – Mobile broadband

Montly demand of MBB spread out - all days of the month- all 24 hours of the day

Time

For data NRT data traffic the approach with”average data rate” per user can be used

X GB per user and month -> Y kbps per user

6

Montly demand of MBB spread out - all days of the month- 12 out of 24 hours of the day

Capacity dimensioning – Mobile broadband

Time

4

7

Capacity dimensioning – Mobile broadband

Montly demand of MBB spread out - all days of the month- 8 out of 24 hours of the day

Time

8

Capacity dimensioning – Mobile broadband

Montly demand of MBB spread out- Non-uniform during 24 hours- Peak hours morning and evening

Time

5

9

Capacity dimensioning – Mobile broadband

Montly demand of MBB spread out- Non-uniform during 24 hours

Time

Office area

10

Capacity dimensioning – Mobile broadband

Montly demand of MBB spread out- Non-uniform during 24 hours

Time

Residential area

6

11

Capacity dimensioning – Mobile broadband

Montly demand of MBB spread out- Non-uniform during 24 hours

Time

Example area

00 06 12 18 24

10 14

Units100

50

2512,5

12

Today

• Dimensioning not assuming uniform usage• Non uniform usage profile• Conditions set by bit rates• Erlang type of dimensioning• Criticism of simple ”HW3” model

• Capacity of a cell• System bandwidth• Spectral efficiency• Spectral reuse

7

13

Conditions set by bit rates• What happens if there are requirements

on data rates?• Examples: 10 users per cell

1 Mbps per user10 Mbps per user

14

A short exercise: how many users can be served,- in a cell with capacities as below ?

Spectralefficiency

5 MHz of Spectrum

10 MHz of Spectrum

20 MHz of Spectrum

0,7 bps/Hz 3,5 MbpsA: 70 usersB: 4 users

7,0 Mbps 14 Mbps

2,0 bps/Hz 10 Mbps 20 Mbps 40 MbpsA: 800 usersB: 50 users

“user demand” • A: [ 5,4 GB/month; 8 hrs/day] => 50 kbps per user• B: [21,6 GB/month; 2 hrs/day] => 800 kbps per user

8

15

Today

• Dimensioning not assuming uniform usage• Non uniform usage profile• Conditions set by bit rates• Erlang type of dimensioning• Criticism of simple ”HW3” model

• Capacity of a cell• System bandwidth• Spectral efficiency• Spectral reuse

16

9

17

Cell planning and re-use

1

2

3 3

221

3

2

2

2

1

1

2

33

2

1

3

1

2

111

4

2

6 7

537

2

1

4

5

6

3

6

47

7

5

3

1

4

621

a) K= 7 b) K= 3

DD

18

Bandwidth for differents systems

LTE1.4MHz 3MHz 5MHz 10MHz 15MHz 20MHzRe-use: 1(2 with fractional frequency reuse)

UMTS, WCDMA 5MHz carriers5MHz 10MHz 15MHz 20 MHzRe-use: 1

GSM, N 200 kHz carriers• Voice: 8 time slots (calls) per carrier• Data: 9,6-59,2 kbps per time slot

max downlink 4*59,2 kbps = 236,8 kbps/carrierRe-use: 1, 3, 4, 7, 9

10

19

Today

• Dimensioning not assuming uniform usage• Non uniform usage profile• Conditions set by bit rates• Erlang type of dimensioning• Criticism of simple ”HW3” model

• Capacity of a cell• System bandwidth• Spectral efficiency• Spectral reuse

20

Peak data rate ~10 - 20 bps per Hz

Average data rate~1 -2 bps per Hz

Cell border rate < 0,10 bps per Hz

Spectral effiency

11

21

Spectral effiency and cylinder model

22

Spectral effiency and cylinder model

12

23

From Ericsson: Capital markets day, May 2008

24

Maximum throughput – LTE

Spectralefficiency(bps/Hz)

1,683,365,0410,0820,16

13

25

Dimensioning of mobile data- Non-uniform usage

Dimensioning of voice services(Thanks to Claes Beckman)

Jan MarkendahlDecember 12, 2016

26

Capacity dimensioning – The busy hour

00:0

0

01:0

0

02:0

0

03:0

0

04:0

0

05:0

0

06:0

0

07:0

0

08:0

0

09:0

0

10:0

0

11:0

0

12:0

0

13:0

0

14:0

0

15:0

0

16:0

0

17:0

0

18:0

0

19:0

0

20:0

0

21:0

0

22:0

0

23:0

0

Time

Cal

l Att

emp

ts

Capacity that is deployed

Blockedtraffic

14

27

TrafficAn Erlang is a unit of telecommunications traffic

measurement. Strictly speaking, an Erlang represents the continuous use of one voice path. In practice, it is used to describe the total traffic volume of one hour.

Example, if a group of users make 30 calls in one hour, and each call had an average call duration of 5 minutes, then the number of Erlangs this represents is worked out as follows:

Minutes of traffic in the hour = number of calls x duration Minutes of traffic in the hour = 30 x 5 = 150Hours of traffic in the hour = 150 / 60 = 2.5

Traffic figure= 2.5 Erlangs

28

Erlang BSeveral traffic models exist which share their name with the Erlang unit of traffic. They are formulae which can be used to estimate the number of lines required in a network, or to a central office (PSTN exchange lines).

Erlang B is the most commonly used traffic model, and is used to work out how many lines are required if the traffic figure (in Erlangs) during the busiest hour and the number of blocked calls are known. The model assumes that all blocked calls are immediately cleared.

http://www.erlang.com/calculator/erlb/

15

29

Excercise - Erlang

• How many Erlang do YOU produceyourself during your most busy hour?

30

• Specified by ETSI• Frequency Division Duplex• TDMA system• Originally at 900MHz, but today

also at 800, 1800, 1900 and some other bands world wide

0 200 400 600 800 1000 1200 1400 1600 1800 2000 MHz

16

31

Basic Frame Structure

•8 time slots (voice channels) /TDMA carrier

•1 time slot / cell used for signaling (BCCH)

•Symbol rate 271 kbps

BCCH TCH TCHTCH

32

Cell planning and re-use

1

2

3 3

221

3

2

2

2

1

1

2

33

2

1

3

1

2

111

4

2

6 7

537

2

1

4

5

6

3

6

47

7

5

3

1

4

621

a) K= 7 b) K= 3

DD

17

33

Number of channels to use- Short exercise

How many voice channels per site in the cases

A. Bandwidth 2,8 MHz, re-use factor 7, omni antenna

B. Bandwidth 1,2 MHz, re-use factor 3, omni antenna

34

Number of channels to use- Short exercise

How many voice channels per site in the cases

A. Bandwidth 2,8 MHz, re-use factor 7, omni antennaNo carriers: 2,8/0,2= 14, No Carriers per site: 14/7 = 2

=> 2*8 = 16 voice channels (no signalling)

B. Bandwidth 1,2 MHz, re-use factor 3, omni antennaNo carriers: 1,2/0,2= 6, No Carriers per site: 6/3 = 2

A. => 2*8 = 16 voice channels (no signalling)

18

35

Network Capital requirements are a

function of peak demand

Service Revenues are a function of average

demand

Network Traffic Load

30mErlang is the statistical traffic per subscriber in busy hour.

Minutes of use is the sum of all traffic,i.e the blue area

36

Blocking in Cellular systems

• Typically we plan the voice capacity of our mobile phone systems for 2% blocking rate (98% availability)

19

37

An example• Bandwidth 1,2 MHz, re-use factor 3, three sectors• Assume that one channel will be used for control• No carriers:2• Total No cannels: 16• Usable No channels: 15

• 2% blocking => 9 Erlang

• How many 20mE users can be served? 9/(20*10-3) = 450• How many 50mE users can be served? 9/(50*10-3) = 180

38

20

39

The examples we did Dec 12• A and B from before, both leading to 2 carriers• How many 100 mE users can be served for cases K and L

Case availability No Ctrl channels No GPRS channelsK 90% 1 1L 99,9% 1 4

40

The examples we did Dec 12• A and B from before, both leading to 2 carriers• How many 100 mE users can be served for cases K and L

Case availability No Ctrl channels No GPRS channelsK 90% 1 1L 99,9% 1 4

Blocking prob No of voice channels Offered trafficK 10% 16-1-1= 14 11,47 EL 0,1% 16-1-4= 11 3,651 E

No users (100mE)K 114L 36

21

41