8 No. of 20 DIA BARS 500 mm 35.00 tonne

Input Data5No. of 16 DIA BARS

346.50 mm

300 mm

600.00 mm

FAILURE PLANE(CL 40.5.1 IS 456)

30

d'=

6No. of 16 DIA BARS

Vertical un factored loadMT

Vertical Load = Vu 516000 N

Horizontal Load = Hu 113520 N OK

Shear Span of Bracket= 500 mm mm OK

Width of Bracket = 400 mm

Overall Depth of Bracket (D) = 600 mm

Depth of Straight Portion(hv) = 300 mm OK

Grade of Concrete (f ck ) = M25 25

Grade of Steel (f y ) = Fe 415

Coefficient of Friction (= 1Clear Cover (Cc ) = 20 mm

Primary Tensile Reinforcement Dia () = 20 mmDia of Horizontal Stirrup () = 16 mmDia of Vertical Stirrup () = 16 mmMaximum Allowable Spacing = 300 mm

Minimum Allowable Spacing = 30 mm

Effective Depth (d) = D - Cc - PT/2 = 572 mmEffective Depth (d) = D1 - Cc - PT/2 = 272 mm28 days cylinder strength of concrete (fc') = 0.80 x fck = 20 M Pa

Vertical Shear Stress developed = Vu/ (bx0.8d) = 2.82 M Pa

450.46 mm

478.46 mm

Value of 0.15 x fc' = 3.00 M Pa OK

Shear friction reinforcement (Avf)= Vu/(0.85 x fy x ) = 1462.792 mm2

Direct tension reinforcement (At)= Hu/(0.85 x fy ) = 321.8143 mm2

Flexural tension reinforcement (Af)= [Vu x a + Hu (D d)] / (0.85 x fy x d)= 1610.394 mm2

Percentage of steel(pt1)= 0.70 % OK

Total primary tensile reinforcement (As)= Maximum of ( (Af + At), (2/3Avf + At), (0.04fc/fy)bd)

(Af + At) 1932.208 mm2

(2/3Avf + At), 1297.009 mm2

(0.04fc/fy)bd) 441.0602 mm2

Max= 1932.208 mm2

Percentage of steel(pt2)= 0.84 % OK

Total Horizontal stirrup area (Ah)= maximum(0.5 x Af, 0.333 x Avf) = 805.1968 mm2

C/S area of primary tensile reinforcement (APT)=x PT2 /4 = 314.1593 mm2

C/S area of Horizontal Stirrup (Ah)=x h2 /4 = 201.0619 mm2

C/S area of vertical Stirrup (Av)=x v2 /4 = 201.0619 mm2

No. of bars required for primary tensile reinf (NPT)= As/APT = 8

Number of horizontal stirrup required (Nh)= Ah/Afh = 6

Number of Vertical stirrup 5

Minimum no of reinforcement bars considered = 2.0

Spacing of primary tensile reinforcement required (SPT)= (b - 2 x Cc )/(NPT- 1) = 51.43

Spacing of Horizontal stirrup required (Sh)= 2/3 x d' / Nh = 50.05

Spacing of Vertical stirrup required (Sv)= 2 x Av x fy x d/(Vu - 10 x b x d) = 145.68

Spacing of primary tensile reinforcement provided (SPTprov) = 50

Spacing of Horizontal stirrup provided (Shprov) = 50

Spacing of Vertical stirrup provided (Svprov) = 145